subdirectory

I am trying to get a list of all files in a directory and its subdirectories. My current recursive approach is as follows: private void printFiles(File dir) { for (File child : dir.listFiles()) { if (child.isDirectory()) { printFiles(child); } else if (child.isFile()) { System.out.println(child.getPath()); } } } printFiles(new File("somedir/somedir2")); However, I was hoping there was a non-recursive way (an existing API call, maybe) of doing this. If not, is this the cleanest way of doing this? Ryan Gross You can always replace a recursive solution with an iterative one by using a stack (for

This question already has an answer here: Delete directory with files in it? 33 answers I need a script which can remove a whole directory with all their subfolders, files and etc. I tried with this function which I found in internet before few months ago but it not work completely. function deleteFile($dir) { if(substr($dir, strlen($dir)-1, 1) != '/') { $dir .= '/'; } if($handle = opendir($dir)) { while($obj = readdir($handle)) { if($obj != '.' && $obj != '..') { if(is_dir($dir.$obj)) { if(!deleteFile($dir.$obj)) { echo $dir.$obj."<br />"; return false; } } elseif(is_file($dir.$obj)) { if(

I want to list every file and directory contained in a directory and subdirectories of that directory. If I chose C:\ as the directory, the program would get every the name of every file and folder on the hard drive that it had access to. A list might look like fd\1.txt fd\2.txt fd\a\ fd\b\ fd\a\1.txt fd\a\2.txt fd\a\a\ fd\a\b\ fd\b\1.txt fd\b\2.txt fd\b\a fd\b\b fd\a\a\1.txt fd\a\a\a\ fd\a\b\1.txt fd\a\b\a fd\b\a\1.txt fd\b\a\a\ fd\b\b\1.txt fd\b\b\a Ruslan F. string[] allfiles = Directory.GetFiles("path/to/dir", "*.*", SearchOption.AllDirectories); where *.* is pattern to match files If the

So I am writing a code that locates certain information on Protein databases. I know that a recursive folder search is the best possible way to locate these files, but I am very new to this language and have been told to write in Java (I normally do C++) SO this being said, what method would i use to: First: Locate the folder on desktop Second: Open each folder and that folders subfolders Third: Locate files that end with the ".dat" type (because these are the only files that have stored the Protein information Thanks for any and all help you can provide java.io.File is "An abstract

I'm programming the new version of my website and I'm trying to get .htaccess to rewrite properly. My new site is stored here: www.example.com/storage/new/ I need to rewrite these URLs: www.example.com/storage/new/welcome/ -> index.php?action=welcome www.example.com/storage/new/page/name/ -> index.php?action=page&url=name www.example.com/storage/new/post/name/ -> index.php?action=post&url=name This is my .htaccess file: RewriteEngine On RewriteRule ^/welcome/$ index.php?action=welcome [L] RewriteRule ^/page/([a-zA-Z0-9]+)/$ index.php?action=page&url=$1 [L] RewriteRule ^/post/([a-zA-Z0-9]+)/$

I'm using git-archive to archive a subdirectory in a git repo, like so: git archive -o ../subarchive.zip HEAD subdir/* However the resulting archive maintains the subdir/ directory structure, i.e. the contents are: subdir/ whatever.js morestuff.js When I actually want whatever.js and morestuff.js at the root of the archive. How do? Thanks. You can do that like this: git archive -o ../subarchive.zip HEAD:subdir By the way, an easy way to play with the command and see what it will generate is if you use it in this form: git archive --format=tar HEAD:subdir | tar t git archive --format=tar HEAD

I have a django application running on http://localhost:12345 . I'd like user to access it via url http://my.server.com/myapp . I use nginx to reverse proxy to it like the following: ... ... server_name my.server.com; location /myapp { rewrite /myapp(.*) $1 break; ... ... # proxy param proxy_pass http://localhost:12345; } ... ... The question is, when configured like the above, how to make the urls in my response pages to have a prefix of "/myapp" so that the nginx can direct them correctly to myapp. E.g., the urls in a page like "/foo/far" ought to be changed to "/myapp/foo/bar" to allow