struct

问题 If I have: type foo struct{ } func bar(baz interface{}) { } The above are set in stone - I can't change foo or bar. Additionally, baz must converted back to a foo struct pointer inside bar. How do I cast &foo{} to interface{} so I can use it as a parameter when calling bar? 回答1: To turn *foo into an interface{} is trivial: f := &foo{} bar(f) // every type implements interface{}. Nothing special required In order to get back to a *foo , you can either do a type assertion : func bar(baz

问题 Hello guys I'm trying to make a simple and re-usable Swift Network Layer Maybe it's not the best way to loop returned data in view but after I tried to get the returned Api data to Loop it in SwiftUI view I'm getting error : Escaping closure captures mutating 'self' parameter And don't know where or what i missed in this lesson and here's a picture of the file ContentView.swift struct ContentView: View { var emptyDataArr: [CollectionItem] = [] init() { ServiceLayer.request(router: Router

问题 I'm trying to embrace Swift's value types more in my application design, but I'm having some beginner difficulties. I know those generally don't go over well in the StackOverflow format for being opinion-based, but I think there are best-practices here that are probably not particularly subjective. I understand all the theoretical benefits of structs, about avoiding shared mutable state, the copying behaviour that makes it easy to implement "undo", etc., but I have a hard time using it in

问题 I'm trying to edit an array (as a pointer) of structs by filling in the default values with new structs that I initialize. Doing so seems to cause some really bizarre problems. I'm learning how to use structs with pointers, so any help is appreciated. Snippet from the main function (player just saves the startLoc without changing it) Location** near; startLoc = initLocation("Base", 5); player = initPlayer(startLoc); near = &(startLoc->near); *near = initLocation("Zero", 0); *(near + 1) =

问题 I'm trying to create a struct of arrays with arrays inside and load them onto the GPU. I think I followed the steps to do this correctly. Create a struct on the CPU using malloc. cudamalloc the arrays to the struct. Create a struct on the GPU using cudamalloc Copy the CPU struct onto the GPU struct. When I run this code, it will correctly work as long as I don't change the value p[i].c[0] in the kernel function. If I delete the line p[i].c[0] = 3.3; then it outputs the expected results. When

问题 I have the following nested struct definition: typedef struct { int count; float cash; char item[50];//switch between array and pointer for testing initializers //char *item; }Purchase; typedef struct { int accnt; char acct_name[50]; Purchase purch; } Acct; Where for the Purchase struct by itself, the following initializer works: //Uses member names: /* 1 */Purchase p = {.count = 4, .cash = 12.56, .item = "thing"}; // Note: this member: ^^^^^^^^^^^^^^^ And for the nested struct Acct the

问题 I have an array each of whose elements could be either uint16_t or a pair of uint8_t. Its elements are defined as a union of a uint16_t and a sub-array of 2 uint8_t. Unfortunately, the compiler (MicroChip XC16) allocates twice as much memory as it should for the array. typedef union { uint16_t u16; // As uint16_t uint8_t u8[2]; // As uint8_t } my_array_t; my_array_t my_array[1]; // 1 word array, for testing my_array[0].u8[0] = 1; my_array[0].u8[1] = 2; uint8_t byte_0 = my_array[0].u8[0]; //

问题 I have an array each of whose elements could be either uint16_t or a pair of uint8_t. Its elements are defined as a union of a uint16_t and a sub-array of 2 uint8_t. Unfortunately, the compiler (MicroChip XC16) allocates twice as much memory as it should for the array. typedef union { uint16_t u16; // As uint16_t uint8_t u8[2]; // As uint8_t } my_array_t; my_array_t my_array[1]; // 1 word array, for testing my_array[0].u8[0] = 1; my_array[0].u8[1] = 2; uint8_t byte_0 = my_array[0].u8[0]; //

问题 I have an array each of whose elements could be either uint16_t or a pair of uint8_t. Its elements are defined as a union of a uint16_t and a sub-array of 2 uint8_t. Unfortunately, the compiler (MicroChip XC16) allocates twice as much memory as it should for the array. typedef union { uint16_t u16; // As uint16_t uint8_t u8[2]; // As uint8_t } my_array_t; my_array_t my_array[1]; // 1 word array, for testing my_array[0].u8[0] = 1; my_array[0].u8[1] = 2; uint8_t byte_0 = my_array[0].u8[0]; //

问题 It is possible to know the name of a struct in swift ? I know this is possible for class : Example class Example { var variable1 = "one" var variable2 = "2" } printing this class name, I would simply do: NSStringFromClass(Example).componentsSeparatedByString(".").last! but can I do something similar for struct ? Example If i have a struct : struct structExample { var variable1 = "one" var variable2 = "2" } how can I get the name " structExample " of this struct ? Thanks. 回答1: If you need the