convert struct pointer to interface{}

问题

If I have:

   type foo struct{
   }

   func bar(baz interface{}) {
   }

The above are set in stone - I can't change foo or bar. Additionally, baz must converted back to a foo struct pointer inside bar. How do I cast &foo{} to interface{} so I can use it as a parameter when calling bar?

回答1:

To turn *foo into an interface{} is trivial:

f := &foo{}
bar(f) // every type implements interface{}. Nothing special required

In order to get back to a *foo, you can either do a type assertion:

func bar(baz interface{}) {
    f, ok := baz.(*foo)
    if !ok {
        // baz was not of type *foo. The assertion failed
    }

    // f is of type *foo
}

Or a type switch (similar, but useful if baz can be multiple types):

func bar(baz interface{}) {
    switch f := baz.(type) {
    case *foo: // f is of type *foo
    default: // f is some other type
    }
}

回答2:

use reflect

reflect.ValueOf(myStruct).Interface().(newType)

回答3:

Not fully-related, but I googled the question "convert interface struct to pointer" and get here.

So, just make a note: to convert an interface of T to interface of *T:

//
// Return a pointer to the supplied struct via interface{}
//
func to_struct_ptr(obj interface{}) interface{} {
    vp := reflect.New(reflect.TypeOf(obj))
    vp.Elem().Set(reflect.ValueOf(obj))
    return vp.Interface()
}

来源：https://stackoverflow.com/questions/24422810/convert-struct-pointer-to-interface