strip

Is there a fast way (without having to explicitly looping through each character in a string) and either stripping or keeping it. In Visual FoxPro, there is a function CHRTRAN() that does it great. Its on a 1:1 character replacement, but if no character in the alternate position, its stripped from the final string. Ex CHRTRAN( "This will be a test", "it", "X" ) will return "ThXs wXll be a es" Notice the original "i" is converted to "X", and lower case "t" is stripped out. I looked at the replace for similar intent, but did not see an option to replace with nothing. I'm looking to make some

I am looking for an objective C function (custom or built-in) that strips html tags from a string, similar to PHP's version that can be found here: http://php.net/manual/en/function.strip-tags.php Any help would be appreciated! This just removes < and > characters and everything between them, which I suppose is sufficient: - (NSString *) stripTags:(NSString *)str { NSMutableString *ms = [NSMutableString stringWithCapacity:[str length]]; NSScanner *scanner = [NSScanner scannerWithString:str]; [scanner setCharactersToBeSkipped:nil]; NSString *s = nil; while (![scanner isAtEnd]) { [scanner

I'm having issues in reading a file into a list, When I do it only creates one item from the entire file rather than reading each element into its own field. I'm using \n as the thing to strip on, but I can't get it to work correctly. temp = open('drugs') drugs = [temp.read().strip("\n")] temp.close Result: ['40 Stimpak\n53 Mentats\n87 Buffout\n109 Rad-X\n125 Booze\n260 Jet Antidote\n311 Roentgen Rum\n424 Monument Chunk\n480 Bonus +1 Agility\n525 Hypo \n48 RadAway\n71 Fruit\n103 Iguana-on-a-stick\n110 Psycho\n144 Super Stimpak\n273 Healing Powder\n334 Poison\n469 Rot Gut\n481 Bonus +1

本文已获得原作者授权同意，翻译以及转载 原文链接： Build your Android app Faster and Smaller than ever 作者： Jirawatee 译文链接： Gradle更小、更快构建APP的奇淫技巧 翻译人： MrTrying 上个月，我有机会在 LINE DEVELOPER DAY 2018 发表演讲。对我来说是特殊的时刻，因为这是我第一次在日本演讲。在成为演讲者之前，LINE 活动的工作人员必须向全球团队提交他们的演讲。 我提交的主题是关于如何更快构建 Android App，以及如何生成更小的 APK 的一些技巧。这些提示来自于我的经验和 Google I/O，特别是在 Developer Build Clinic 中收集到的。Developer Build Clinic 是 Android Studio 团队为改进构建性能方面提供的一对一咨询。 在本文中，我想与你分享这些技巧和 app，给你带来的 app 是 LINE MAN Driver。 对于不知道 LINE MAN 是什么的人来说，它是一个按需助理提供专业服务的 app，包括食物配送、便利店货物配送、信使服务、包裹服务和出租车服务，随时满足所有泰国用户的需求。 请注意，实际结果可能会有所不同，因为它取决于您的项目特征和构建环境，例如项目规模、资源、依赖关系和机器性能。

I am getting an error in my code because I tried to make a dataframe by calling an element from a csv. I have two columns I call from a file: CompanyName and QualityIssue. There are three types of Quality issues: Equipment Quality, User, and Neither. I run into problems trying to make a dataframe df.Equipment Quality, which obviously doesn't work because there is a space there. I want to take Equipment Quality from the original file and replace the space with an underscore. input: Top Calling Customers, Equipment Quality, User, Neither, Customer 3, 2, 2, 0, Customer 1, 0, 2, 1, Customer 2, 0,

I need to turn HTML into plain text. There's a nice function that does that in ActionView's SanitizeHelper, but I have trouble understanding how I can reference it and use it in a simple test.rb file. http://api.rubyonrails.org/classes/ActionView/Helpers/SanitizeHelper.html I would like to be able to call strip_tags("<b>lol</b>") => "lol" The question is quite old, but I had the same problem recently. I found a simple solution: gem sanitize . It's light, works fine and has additional options if you need them. Sanitize.clean("<b>lol</b>") #=> "lol" ActiveSupport is the only Rails framework that

I have some text file like this, with several 5000 lines: 5.6 4.5 6.8 "6.5" (new line) 5.4 8.3 1.2 "9.3" (new line) so the last term is a number between double quotes. What I want to do is, using Python (if possible), to assign the four columns to double variables. But the main problem is the last term, I found no way of removing the double quotes to the number, is it possible in linux? This is what I tried: #!/usr/bin/python import os,sys,re,string,array name=sys.argv[1] infile = open(name,"r") cont = 0 while 1: line = infile.readline() if not line: break l = re.split("\s+",string.strip(line)