strip

Is there a better way to use strip() on a list of strings? - python [duplicate]

纵然是瞬间 提交于 2019-12-03 22:37:27
This question already has answers here : Closed 2 years ago . Remove trailing newline from the elements of a string list (6 answers) For now i've been trying to perform strip() on a list of strings and i did this: i = 0 for j in alist: alist[i] = j.strip() i+=1 Is there a better way of doing that? You probably shouldn't be using list as a variable name since it's a type. Regardless: list = map(str.strip, list) This will apply the function str.strip to every element in list , return a new list, and store the result back in list . karthikr You could use list comprehensions stripped_list = [j

python: rstrip one exact string, respecting order

吃可爱长大的小学妹 提交于 2019-12-03 22:16:13
Is it possible to use the python command rstrip so that it does only remove one exact string and does not take all letters separately? I was confused when this happened: >>>"Boat.txt".rstrip(".txt") >>>'Boa' What I expected was: >>>"Boat.txt".rstrip(".txt") >>>'Boat' Can I somehow use rstrip and respect the order, so that I get the second outcome? You're using wrong method. Use str.replace instead: >>> "Boat.txt".replace(".txt", "") 'Boat' NOTE : str.replace will replace anywhere in the string. >>> "Boat.txt.txt".replace(".txt", "") 'Boat' To remove the last trailing .txt only, you can use

Prevent NGINX to remove the port

那年仲夏 提交于 2019-12-03 16:57:40
I want to keep the ServerName and Port dynamicly on my rewrite: Lets say the Firewall redirect port 8081 to 80. So, if i access the webserver for example with "192.168.1.123/frontend" or "my.domain.tld:8081/frontend" i should be redirect to "192.168.1.123/frontend/" or "my.domain.tld:8081/frontend/" If i use the normal redirect rewrite ^(.*[^/])$ $1/ permanent; and i access with the port 8081 the port got removed. (I already tried port_in_redirect off; ) I use almost the default configuration: server { listen 80 default_server; listen [::]:80 default_server; root /var/www/html; index index.php

How to detect at runtime whether symbols are stripped?

回眸只為那壹抹淺笑 提交于 2019-12-03 12:35:22
In my C++ program, how can I detect programmatically at runtime whether symbols have been stripped via the 'strip' gnu development tool on Linux? I'd like a function definition which returns true if stripped, otherwise false. Would using dlsym() on "main()" work to detect this reliably? I know the file command can tell the difference, so you could possibly look at its source to see what mechanism it uses. jschmier From a comment left for another answer : A stripped ELF will lack a .symtab entry. The file command traverses through all the ELF section headers until a symbol table section is

How to escape/strip special characters in the LaTeX document?

♀尐吖头ヾ 提交于 2019-12-03 09:51:56
问题 We implemented the online service where it is possible to generate PDF with predefined structure. The user can choose a LaTeX template and then compile it with an appropriate inputs. The question we worry about is the security, that the malicious user was not able to gain shell access through the injection of special instruction into latex document. We need some workaround for this or at least a list of special characters that we should strip from the input data. Preferred language would be

how to strip punctuation in php

两盒软妹~` 提交于 2019-12-03 09:06:24
问题 How can I strip punctuation except for these characters . = $ ' - € % 回答1: Since you need to match some Unicode characters ( € ) it would be sensible to use a regular expression. The pattern \p{P} matches any known punctuation, and the assertion excludes your desired special characters from vanishing: $text = preg_replace("/(?![.=$'€%-])\p{P}/u", "", $text); 回答2: Here's a neat way to do it: preg_replace("#[[:punct:]]#", "", $target); 回答3: <? $whatToStrip = array("?","!",",",";"); // Add what

How to decrease the size of generated binaries?

这一生的挚爱 提交于 2019-12-03 08:17:35
问题 I know that there is an option "-Os" to "Optimize for size", but it has little affect, or even increase the size on some occasion :( strip (or "-s" option) removes debug symbol table, which works fine; but it can only decrease only a small propotion of the size. Is there any other way to go furthur? 回答1: Apart from the obvious ( -Os -s ), aligning functions to the smallest possible value that will not crash (I don't know ARM alignment requirements) might squeeze out a few bytes per function.

How do you cut off text after a certain amount of characters in PHP?

家住魔仙堡 提交于 2019-12-03 06:59:43
问题 I have two string that i want to limit to lets say the first 25 characters for example. Is there a way to cut off text after the 25th character and add a ... to the end of the string? So '12345678901234567890abcdefg' would turn into '12345678901234567890abcde...' where 'fg' is cut off. 回答1: May I make a modification to pallan's code? $truncated = (strlen($string) > 20) ? substr($string, 0, 20) . '...' : $string; This doesn't add the '...' if it is shorter. 回答2: To avoid cutting right in the

为什么滴滴裁员2000人,被裁员工却像中奖一样开心?

前提是你 提交于 2019-12-03 06:14:16
![image](//upload-images.jianshu.io/upload_images/6415041-b8bdbe79b217be74.jpeg?imageMogr2/auto-orient/strip%7CimageView2/2/w/550/format/webp) > 2月15日,滴滴举办了阅读全员会,在滴滴的月度全员会上,滴滴CEO程维公开宣布公司将做好过冬准备。2019年对非主业进行“关停并转”,对业务重组带来的岗位重叠和绩效不达标的员工进行减员公司将进行优化减员,整体裁员比例占到全员的 15%,涉及 2000 人左右。 据《财经》报道,滴滴近日已给出裁员的具体赔偿方案:补偿一般为 N+1 个月,如果本周能确认,再额外给一个月补偿——这一个月补偿是滴滴给被裁员工留出找工作时间,即本周确认,三月份工资和五险一金滴滴照发。 对于此次裁员事件,有滴滴员工在某平台上评论称,被裁员工却像是中奖一样,满满的幸福感。 #### 史上最有幸福感的裁员 印象中,不管什么公司,每次裁员都像一场血洗。偷偷摸摸的,既要安抚被辞员工,又要稳定在职员工情绪,还要做好各种对外公关。而被辞退员工,要么呼天抢地,或者要死要活。 滴滴这次有点不一样。某种程度上,裁员本身就是一种不负责的行为,但在裁员时,却是满满的责任感。 要知道滴滴出行2018年持续巨额亏损,全年亏损高达109亿元。与此同时

Remove leading and trailing slash / in python

◇◆丶佛笑我妖孽 提交于 2019-12-03 06:11:15
问题 I am using request.path to return the current URL in Django, and it is returning /get/category . I need it as get/category (without leading and trailing slash). How can I do this? 回答1: >>> "/get/category".strip("/") 'get/category' strip() is the proper way to do this. 回答2: def remove_lead_and_trail_slash(s): if s.startswith('/'): s = s[1:] if s.endswith('/'): s = s[:-1] return s Unlink str.strip() , this is guaranteed to remove at most one of the slashes on each side. 回答3: Another one with