strip

How do I strip all attributes from HTML tags in a string, except "alt" and "src" using Java? And further.. how do I get the content from all "src" attributes in the string? :) You can: Implement a SAX parser ; Built a document with a DOM parser , walk it and prune it and then convert back to HTML; or Use an identity transform in XSLT (assuming your HTML is in XHTML format or can be converted to that with, say, JTidy ) with some additional cases to remove attributes you don't want. Whatever you do, don't try and do it with regular expressions. OK, solved this somehow. Used the HTMLCleaner

Given an example dataframe with the 2nd and 3rd columns of free text, e.g. >>> import pandas as pd >>> lol = [[1,2,'abc','foo\nbar'], [3,1, 'def\nhaha', 'love it\n']] >>> pd.DataFrame(lol) 0 1 2 3 0 1 2 abc foo\nbar 1 3 1 def\nhaha love it\n The goal is to replace the \n to (whitespace) and strip the string in column 2 and 3 to achieve: >>> pd.DataFrame(lol) 0 1 2 3 0 1 2 abc foo bar 1 3 1 def haha love it How to replace newlines with spaces for specific columns through pandas dataframe? I have tried this: >>> import pandas as pd >>> lol = [[1,2,'abc','foo\nbar'], [3,1, 'def\nhaha', 'love it\n

I have a string like this: la lala 135 1039 921\r\n And I can't remove the \r\n . Initially this string was a bytes object but then I converted it to string I tried with .strip("\r\n") and with .replace("\r\n", "") but nothing... The issue is that the string contains a literal backslash followed by a character. Normally, when written into a string such as .strip("\r\n") these are interpreted as escape sequences, with "\r" representing a carriage return (0x0D in the ASCII table) and "\n" representing a line feed (0x0A). Because Python interprets a backslash as the beginning of an escape

I got weird behavior from ruby (in irb): irb(main):002:0> pp " LS 600" "\302\240\302\240\302\240\302\240LS 600" irb(main):003:0> pp " LS 600".strip "\302\240\302\240\302\240\302\240LS 600" That means (for those, who don't understand) that strip method does not affect this string at all, same with gsub('/\s+/', '') How can I strip that string (I got it while parsing Internet page)? The string "\302\240" is a UTF-8 encoded string ( C2 A0 ) for Unicode code point A0 , which represents a non breaking space character. There are many other Unicode space characters. Unfortunately the String#strip

This minimal code crashes my Python. (Setting: pandas 0.13.0, python 2.7.3 AMD64, Win7.) import pandas as pd input_file = r"c3.csv" input_df = pd.read_csv(input_file) for col in input_df.columns: # strip whitespaces from string values if input_df[col].dtype == object: input_df[col] = input_df[col].apply(lambda x: x.strip()) print 'start' for idx in range(len(input_df)): input_df['LL'].iloc[idx] = 3 print idx print 'finished' Output: start 0 Process finished with exit code -1073741819 What prevents the crash: Removing lines from c3.csv. Removing .strip() from the code. Changing c3.csv changes

I have a question regarding strip() in Python. I am trying to strip a semi-colon from a string, I know how to do this when the semi-colon is at the end of the string, but how would I do it if it is not the last element, but say the second to last element. eg: 1;2;3;4;\n I would like to strip that last semi-colon. Thanks Strip the other characters as well. >>> '1;2;3;4;\n'.strip('\n;') '1;2;3;4' >>> "".join("1;2;3;4;\n".rpartition(";")[::2]) '1;2;3;4\n' how about replace? string1='1;2;3;4;\n' string2=string1.replace(";\n","\n") >>> string = "1;2;3;4;\n" >>> string.strip().strip(";") "1;2;3;4"

iperf是一个基于Client/Server的网络性能测试工具，可以测试TCP、UDP和SCTP带宽质量，能够提供网络吞吐率信息，以及震动、丢包率，最大段和最大传输单元大小等统计信息，帮助我们测试网络性能，定位网络瓶颈。其中抖动和丢包率适应于UDP测试，二带宽测试适应于TCP和UDP。 一、介绍 iperf是一个基于Client/Server的网络性能测试工具，可以测试TCP、UDP和SCTP带宽质量，能够提供网络吞吐率信息，以及震动、丢包率，最大段和最大传输单元大小等统计信息，帮助我们测试网络性能，定位网络瓶颈。其中抖动和丢包率适应于UDP测试，二带宽测试适应于TCP和UDP。 Iperf可以说是嵌入式设备里网络接口测试的一个利器。这里的网络接口不但可以是一般的以太网，也可以是无线网络，还可以是4G模块; 官方提供的公网服务器:iperf-servers。不过测试过速度有点捉鸡，还是自己建个测试爽。 二、交叉编译 Step1. 下载 下载地址:http://downloads.es.net/pub/iperf/。本文以 iperf-3.0.1.tar.gz 版本为例。 Step2. 配置./configure --host=arm- linux --prefix=$PWD/xxx_install 其中， --host: 指定交叉编译工具，一般为arm-none-linux

I have string such as <p> <style type="text/css"> P { margin-bottom: 0.21cm; direction: ltr; color: rgb(0, 0, 0); }P.western { font-family: "Times New Roman",serif; font-size: 12pt; }P.cjk { font-family: "Arial Unicode MS",sans-serif; font-size: 12pt; }P.ctl { font-family: "Tahoma"; font-size: 12pt; } </style> </p> <p align="CENTER" class="western" style="margin-bottom: 0cm"> <font size="5" style="font-size: 20pt"><u><b> TEXT I WANT TO GET </b></u></font></p> How can i strip html, css and get only text? Im aware of strip_tags() , and I can write function with preg_replace , but is there a