string-matching

Pandas Compare two dataframes and determine the matched values

拥有回忆 提交于 2019-12-06 14:59:28
I have the following dataframes: print(dfa) ID Value AA12 101 BB101 CC01 DE06 1 AA11 102 BB101 CC01 234 EE07 2 AA10 202 BB101 CC01 345 EE09 3 AA13 103 BB101 CC02 123 4 AA14 203 BB101 CC02 456 5 AA15 204 BB102 CC03 567 6 print(dfb) ID Value AA10 202 BB101 CC01 EE09 345 3 AA11 102 BB101 CC01 EE07 234 2 AA12 101 BB101 CC01 DE06 1 AA13 103 BB101 CC02 123 4 AA18 203 BB103 CC01 456 5 AA15 204 BB201 CC11 678 7 I would like to compare the string in (dfa.ID, dfa.Value) to the one in (dfb.ID, dfb.Value). If they match exactly (even when the order of substring is not identical), I would like to print

“Partial match” table (aka “failure function”) in KMP (on wikipedia)

倾然丶 夕夏残阳落幕 提交于 2019-12-06 12:11:33
I'm reading the KMP algorithm on wikipedia. There is one line of code in the "Description of pseudocode for the table-building algorithm" section that confuses me: let cnd ← T[cnd] It has a comment: (second case: it doesn't, but we can fall back) , I know we can fall back, but why T[cnd], is there a reason? Because it really confuses me. Here is the complete pseudocode fot the table-building algorithm: algorithm kmp_table: input: an array of characters, W (the word to be analyzed) an array of integers, T (the table to be filled) output: nothing (but during operation, it populates the table)

Hashing n-grams by cyclic polynomials - java implementation

白昼怎懂夜的黑 提交于 2019-12-06 12:10:33
问题 I'm solving some problem that involves Rabin–Karp string search algorithm. This algorithm requires rolling hash to be faster then naive search. This article describes how to implement rolling hash. I implemented "Rabin-Karp rolling hash" without problems and found few implementations implementations, but article also mentions computational complexity and that hashing n-grams by cyclic polynomials is prefered. It links to BuzHash implementation of such technique but I wonder how it can be used

How to improve PHP string match with similar_text()?

江枫思渺然 提交于 2019-12-06 11:50:53
问题 I am using PHP's similar_text() call to compare two strings, however, I am not getting good enough results, for example, the best I'm getting is 80.95% for a match that I'd like to see 100% on. What other functions can I use to get the strings down to the core? <!-- Overcast, Rain or Showers compared Overcast, Rain or Showers is 80.9523809524 --> <!-- Overcast, Risk of Rain or Showers compared Overcast, Rain or Showers is 86.2068965517 --> <!-- Overcast, Chance of Rain or Showers compared

Searching one Python dataframe / dictionary for fuzzy matches in another dataframe

我是研究僧i 提交于 2019-12-06 11:14:23
问题 I have the following pandas dataframe with 50,000 unique rows and 20 columns (included is a snippet of the relevant columns): df1 : PRODUCT_ID PRODUCT_DESCRIPTION 0 165985858958 "Fish Burger with Lettuce" 1 185965653252 "Chicken Salad with Dressing" 2 165958565556 "Pork and Honey Rissoles" 3 655262522233 "Cheese, Ham and Tomato Sandwich" 4 857485966653 "Coleslaw with Yoghurt Dressing" 5 524156285551 "Lemon and Raspberry Cheesecake" I also have the following dataframe (which I also have saved

Find common values within a column containing list of items

 ̄綄美尐妖づ 提交于 2019-12-06 06:36:19
问题 I have a dataset that contains a few columns that are a list of items. I have given an example below. I am trying to find the entries that have items within the list with a 100% match. I would like to find the ones that have 90% or lower. >>> df2 = pd.DataFrame({ 'ID':['1', '2', '3', '4', '5', '6', '7', '8'], 'Productdetailed': [['Phone', 'Watch', 'Pen'], ['Pencil', 'fork', 'Eraser'], ['Apple', 'Mango', 'Orange'], ['Something', 'Nothing', 'Everything'], ['Eraser', 'fork', 'Pencil'], ['Phone',

Difference between performance of the two sql queries?

眉间皱痕 提交于 2019-12-06 06:30:22
问题 I have a field in my table having text data type. Is there a difference in performance for the following two sql queries: select * from tablename where fieldname="xyz%"; select * from tablename where fieldname="%zyx"; If we were to implement the execution of these queries, this is what I think we would need to do: We have to match the two regexes (xyz* and *zyx). We will have to check the string chars one by starting from the beginning. For the first query we will have to read the first three

Efficient way to check if a given string is equivalent to at least one string in the given set of strings

女生的网名这么多〃 提交于 2019-12-06 05:38:15
问题 Given a set of strings, say "String1", "String2",..., "StringN" , what is the most efficient way in C++ to determine (return true or false ) whether given string s matches any of the strings in the above set? Can Boost.Regex be used for this task? 回答1: std::unordered_set would provide the most efficient look-up (amortized constant time). #include <unordered_set> #include <string> #include <cassert> int main() { std::unordered_set<std::string> s = {"Hello", "Goodbye", "Good morning"}; assert(s

Regex Counting By 3s

≯℡__Kan透↙ 提交于 2019-12-06 02:54:03
I'm teaching myself regular expressions, and found a quizzing site that has been helping me find more applications for them and has been helping me expand my knowledge of how they work. I found a question asking me to form a regex to match 10 digit numbers that are multiples of 3s. The only way I can think of doing this is by having the regex recognise numbers' values and be able to manipulate them mathematically. How is this possible? In other words, what regex would match 0003 0006 0351 1749 but not match 0005 0011 0361 4372 First you need to start with the rule that a number is divisble by

bash script to check file name begins with expected string

为君一笑 提交于 2019-12-06 02:32:46
问题 Running on OS X with a bash script: sourceFile=`basename $1` shopt -s nocasematch if [[ "$sourceFile" =~ "adUsers.txt" ]]; then echo success ; else echo fail ; fi The above works, but what if the user sources a file called adUsers_new.txt ? I tried: if [[ "$sourceFile" =~ "adUsers*.txt" ]]; then echo success ; else echo fail ; fi But the wildcard doesn't work in this case. I'm writing this script to allow for the user to have different iterations of the source file name, which must begin with