stream

问题 I have a relatevely small file (some hundreds of kilobytes) that I want to be in memory for direct access for the entire execution of the code. I don't know exactly the internals of NodeJs, so I'm asking if a fs open is enough or I have to read all file and copy to a Buffer ? 回答1: Basically, you need to use the readFile or readFileSync function from the fs module. They return the complete content of the given file, but differ in their behavior (asynchronous versus synchronous). If blocking

问题 I was surprised when I encountered it, and wrote a console application to check it and make sure I wasn't doing anything else. Can anyone explain this? Here's the code: using System; using System.Collections.Generic; using System.IO; using System.Linq; using System.Text; using System.Xml; using System.Xml.Serialization; namespace ConsoleApplication1 { public class Program { static void Main(string[] args) { var o = new SomeObject { Field1 = "string value", Field2 = 8 }; Console.WriteLine(

问题 I was surprised when I encountered it, and wrote a console application to check it and make sure I wasn't doing anything else. Can anyone explain this? Here's the code: using System; using System.Collections.Generic; using System.IO; using System.Linq; using System.Text; using System.Xml; using System.Xml.Serialization; namespace ConsoleApplication1 { public class Program { static void Main(string[] args) { var o = new SomeObject { Field1 = "string value", Field2 = 8 }; Console.WriteLine(

问题 I want to convert a youtube url into an mp3 file. Currently, I download the mp4 using node's ytdl module, like so: fs = require 'fs' ytdl = require 'ytdl' url = 'http://www.youtube.com/watch?v=v8bOTvg-iaU' mp4 = './video.mp4' ytdl(url).pipe(fs.createWriteStream(mp4)) Once the download is complete, I convert the mp4 into mp3 using the fluent-ffmpeg module, like so: ffmpeg = require 'fluent-ffmpeg' mp4 = './video.mp4' mp3 = './audio.mp3' proc = new ffmpeg({source:mp4}) proc.setFfmpegPath('

问题 After three days of intensive googleing and stackoverflowing I more or less got my program to work. I tried a lot of stuff and found a lot of answers somehow connected to my problem, but no working solution. Sry should I have missed the right page!! I'm looking forward to comments and recommendations. Task: Send binary data (floats) from python to C++ program, get few floats back Data is going to be 20ms soundcard input, latency is a bit critical Platform: Windows (only due to drivers for the

问题 I'm working with ASP.NET, and am importing an XML file from a form. Right now I convert that into a Stream : Stream inputStream = XmlFileUploadControl.PostedFile.InputStream; because I may need this version later. I'd like to first check to make make sure that the XML file has the correct format, and, if it is, then display some information: if (CorrectFileFormat(inputStream)) { DisplayLicenseInfo(inputStream); } else { StatusLabel.Text = "Selected file is not a LicensingDiag XML file"; } The

问题 How to completely kill the WebRTC media stream? MediaStream.stop() is not working anymore. Testing in Chrome 47, Mac OS 10.11. 回答1: Use stream.getTracks().forEach(track => track.stop()); . stream.stop() was deprecated. 回答2: For all browsers if (microphone_data.media_stream) { microphone_data.media_stream.getTracks().forEach(function (track) { track.stop(); }); } 来源： https://stackoverflow.com/questions/34966809/stop-kill-webrtc-media-stream

问题 In Swift 3.x, we usually handle binary data using Data ; from it you can generate most other important types, and there are useful functions on it. But how do I create a Data from an InputStream ? Is there a nice way? 回答1: I could not find a nice way. We can create a nice-ish wrapper around the unsafe stuff: extension Data { init(reading input: InputStream) throws { self.init() input.open() defer { input.close() } let bufferSize = 1024 let buffer = UnsafeMutablePointer<UInt8>.allocate

问题 I have a log file that continually logs short lines. I need to develop a service that reacts (or polls, or listens to) to new lines added to that file, a sort of unix' tail program, so that my service is always up to date reguarding the file. I don't think that opening a read stream and keeping it opened is a good idea. Maybe I should use the FileSystemWatcher class. Long story short, I need to parse in real time every new line added to this file. Any idea help or indication is really

问题 In our project we use the c++ stream operator (<<) in our object model to print out an easy readible format of the data. A simplified example is this: std::ostream& operator<<(std::ostream & oStream, const OwnClass& iOwnClass) { oStream << "[SomeMember1: " << iOwnClass._ownMember1 << "]\n"; oStream << "[SomeMember2: " << iOwnClass._ownMember2 << "]\n"; } Resulting in this in the logging: [SomeMember1: foo] [SomeMember2: bar] What we want now is to be able to indent the result of that operator