stdout

How to have an in-place string that updates on stdout

心不动则不痛 提交于 2019-12-03 01:19:39
问题 I want to output to stdout and have the output "overwrite" the previous output. For example; if I output On 1/10 , I want the next output On 2/10 to overwrite On 1/10 . How can I do this? 回答1: stdout is a stream ( io.Writer ). You cannot modify what was already written to it. What can be changed is how that stream's represented in case it is printed to a terminal. Note that there's no good reason to assume this scenario. For example, a user could redirect stdout to a pipe or to a file at will

How can I redirect STDERR to STDOUT, but ignore the original STDOUT? [duplicate]

北慕城南 提交于 2019-12-03 01:09:35
问题 This question already has answers here : How to pipe stderr, and not stdout? (12 answers) Closed 3 years ago . I have a program whose STDERR output I want to inspect and run grep on etc. So I could redirect it to STDOUT and use grep, but the problem is, I do not want the original STDOUT content. So, this one won't do cmd 2>&1 | grep pattern because it will mix the original STDOUT and STDERR. And this one doesn't work since grep doesn't read the STDERR output: cmd 1>/dev/null | grep pattern

Is it safe to disable buffering with stdout and stderr?

独自空忆成欢 提交于 2019-12-02 23:54:02
Sometimes we put some debug prints in our code this way printf("successfully reached at debug-point 1\n"); some code is here printf("successfully reached at debug-point 2"); After the last printf a segmentation fault occurs. Now in this condition only debug-point1 will be print on stdio debug-point 2 print was written to stdio buffer but its not flushed because it didn't get \n so we thinks that crash occur after debug-point1. To over come from this, if I disable buffering option with stdio and stderr stream like this way setvbuf(stdout, NULL, _IONBF, 0); setvbuf(stderr, NULL, _IONBF, 0); Then

Catching/hijacking stdout in haskell

徘徊边缘 提交于 2019-12-02 23:40:27
How can I define 'catchOutput' so that running main outputs only 'bar'? That is, how can I access both the output stream (stdout) and the actual output of an io action separately? catchOutput :: IO a -> IO (a,String) catchOutput = undefined doSomethingWithOutput :: IO a -> IO () doSomethingWithOutput io = do (_ioOutp, stdOutp) <- catchOutput io if stdOutp == "foo" then putStrLn "bar" else putStrLn "fail!" main = doSomethingWithOutput (putStr "foo") The best hypothetical "solution" I've found so far includes diverting stdout, inspired by this , to a file stream and then reading from that file (

Redirecting stdout/stderr to multiple files

早过忘川 提交于 2019-12-02 23:28:28
I was wondering how to redirect stderr to multiple outputs. I tried it with this script, but I couldn't get it to work quite right. The first file should have both stdout and stderr, and the 2nd should just have errors. perl script.pl &> errorTestnormal.out &2> errorTest.out Is there a better way to do this? Any help would be much appreciated. Thank you. perl script.pl 2>&1 >errorTestnormal.out | tee -a errorTestnormal.out > errorTest.out Will do what you want. This is a bit messy, lets go through it step by step. We say what used to go to STDERR will now go STDOUT We say what used to go to

ffmpeg: which file formats support stdin usage?

余生颓废 提交于 2019-12-02 22:37:11
I know ffmpeg is able to read data from stdin rather than reading from disk using ffmpeg -i - . Is this supported for all file formats? If it is not, is there a list which file formats are supported? Serge You need to run ffmpeg -protocols to determine if the pipe protocol (the read and write from stdin and stdout) supported in your version of ffmpeg and then ffmpeg -formats to see the list of supported formats. In the excerpt below you will see the note on output pipe that it must be seekable for some protocols. For input protocols it has no such restriction. From man ffmpeg-protocols :

Read from stdin write to stdout in C

老子叫甜甜 提交于 2019-12-02 21:27:38
I am trying to write a cat clone to exercise C, I have this code: #include <stdio.h> #define BLOCK_SIZE 512 int main(int argc, const char *argv[]) { if (argc == 1) { // copy stdin to stdout char buffer[BLOCK_SIZE]; while(!feof(stdin)) { size_t bytes = fread(buffer, BLOCK_SIZE, sizeof(char),stdin); fwrite(buffer, bytes, sizeof(char),stdout); } } else printf("Not implemented.\n"); return 0; } I tried echo "1..2..3.." | ./cat and ./cat < garbage.txt but I don't see any output on terminal. What I am doing wrong here? Edit: According to comments and answers, I ended up doing this: void copy

How do I read the standard output from a child process in VB6?

◇◆丶佛笑我妖孽 提交于 2019-12-02 20:01:20
问题 When creating a process in VB6 (related to this question:), I'm using the following struct: Private Type STARTUPINFO cb As Long lpReserved As String lpDesktop As String lpTitle As String dwX As Long dwY As Long dwXSize As Long dwYSize As Long dwXCountChars As Long dwYCountChars As Long dwFillAttribute As Long dwFlags As Long wShowWindow As Integer cbReserved2 As Integer lpReserved2 As Long hStdInput As Long hStdOutput As Long hStdError As Long End Type Before I start my process, what needs to

Batch script: save stdout and have the output in the console too

杀马特。学长 韩版系。学妹 提交于 2019-12-02 18:28:20
问题 By default the output of commandline applications is presented in console window and I know that using > or >> we can re-wrire/append the stdout to an external file but what if the commandline application doesn't have internal logging facility to save the output. I want the stdout to be both in the console and be saved in an external file. Is such a thing possible? 回答1: Try something like this: @echo off echo hello > log.txt & type log.txt pause But using this you can only have one command

Why does 2>&1 need to come before a | (pipe) but after a “> myfile” (redirect to file)?

て烟熏妆下的殇ゞ 提交于 2019-12-02 16:51:07
When combining stderr with stdout, why does 2>&1 need to come before a | (pipe) but after a > myfile (redirect to file)? To redirect stderr to stdout for file output: echo > myfile 2>&1 To redirect stderr to stdout for a pipe: echo 2>&1 | less My assumption was that I could just do: echo | less 2>&1 and it would work, but it doesn't. Why not? A pipeline is a |-delimited list of commands . Any redirections you specify apply to the constituent commands (simple or compound), but not to the pipeline as a whole. Each pipe chains one command's stdout to the stdin of the next by implicitly applying a