state

I'm working on a todo application. This is a very simplified version of the offending code. I have a checkbox: <p><input type="checkbox" name="area" checked={this.state.Pencil} onChange={this.checkPencil}/> Writing Item </p> Here's the function that calls the checkbox: checkPencil(){ this.setState({ pencil:!this.state.pencil, }); this.props.updateItem(this.state); } updateItem is a function that's mapped to dispatch to redux function mapDispatchToProps(dispatch){ return bindActionCreators({ updateItem}, dispatch); } My problem is that when I call the updateItem action and console.log the state

I plane to use static variables instead of Application state in ASP.NET and am wondering if this is correct approach: [Global.asax.cs] ... public class Global : System.Web.HttpApplication { void Application_Start(object sender, EventArgs e) { // Code that runs on application startup } ... private static Dictionary<string, object> cacheItems = new Dictionary<string, object>(); private static object locker = new object(); public static Dictionary<string, object> CacheItems { get { lock (locker) { return cacheItems; } } set { lock (locker) { cacheItems = value; } } } public static void

So I have this: let total = newDealersDeckTotal.reduce(function(a, b) { return a + b; }, 0); console.log(total, 'tittal'); //outputs correct total setTimeout(() => { this.setState({dealersOverallTotal: total}); }, 10); console.log(this.state.dealersOverallTotal, 'dealersOverallTotal1'); //outputs incorrect total newDealersDeckTotal is just an array of numbers [1, 5, 9] e.g. however this.state.dealersOverallTotal does not give the correct total but total does? I even put in a timeout delay to see if this solved the problem. any obvious or should I post more code? setState() is usually

From Stroustrup's TC++PL, 3rd Edition, Section 21.3.3: If we try to read into a variable v and the operation fails, the value of v should be unchanged (it is unchanged if v is one of the types handled by istream or ostream member functions). The following example appears to contradict the above quote. Based on the above quote, I was expecting the value of v to remain unchanged -- but it gets zeroed. What's the explanation for this apparent contradictory behaviour? #include <iostream> #include <sstream> int main( ) { std::stringstream ss; ss << "The quick brown fox."; int v = 123; std::cout <<