spring-ws

Decrypting Message with a Spring Web Service Client

99封情书 提交于 2019-12-03 06:11:00
350 Bounty and waffles to the person who can help me! I have been struggling with Spring Web Service encryption for days and I can't figure out how to get Spring's encryption on the message body to work. Whenever I have the server encrypt the resulting message the client doesn't seem to be decrypting it before it attempts to validate it against the Schema ( XSD ). Here is the server side configuration The server's xwss security configuration The client's Spring configuration Client's xwss configuration What I can do is encrypt the user token and decrypt it successfully. I do that when sending

No adapter for endpoint; Is your endpoint annotated with @Endpoint, or does it implement a supported interface like MessageHandler or PayloadEndpoint?

*爱你&永不变心* 提交于 2019-12-03 01:57:25
I am struggling with an Spring-WS with JMS example. I set the Spring-WS and JMS wiring as per the Spring recommendations. But I kept getting following error. I dont know how to bypass this issue, any help will be highly appreciated: [org.springframework.ws.soap.server.endpoint.SoapFaultAnnotationExceptionResolver] - Resolving exception from endpoint [org.springframework.ws.samples.mtom.ws.ImageRepositoryEndpoint@1c8b0b1]: java.lang.IllegalStateException: No adapter for endpoint [org.springframework.ws.samples.mtom.ws.ImageRepositoryEndpoint@1c8b0b1]: Is your endpoint annotated with @Endpoint,

How to use direct streaming for SOAP with Spring-WS?

主宰稳场 提交于 2019-12-03 01:56:18
We want to enable direct streaming of our payload in webservice endpoints. We have to process a large amount of data and want to stream the data while processing. We use spring-ws-core, in version 2.0.0 and use the PayloadRootQNameEndpointMapping as endpoint mapper. As message factory we are using the AxiomSoapMessageFactory . We implement the StreamingPayload and the corresponding writeTo(XMLStreamWriter writer) method, which we use to write our payload (According to the spring-ws JIRA ticket, SWS-352 ). This works fine without any errors, but we wanted to stream directly! This is apparently

Convert StreamResult to string or xml

我是研究僧i 提交于 2019-12-02 20:24:47
Using spring ws to get the StreamResult as below StreamSource source = new StreamSource(new StringReader(MESSAGE)); StreamResult result = new StreamResult(System.out); webServiceTemplate.sendSourceAndReceiveToResult("http://someUri", source, new SoapActionCallback("someCallBack"), result); return result; I get the result, But I want to extract it to some sort of xml or even as a string (Just want to see the contents in order to generate the response). How can I do this? Asif Bhutto Try this one: try { StreamSource source = new StreamSource(new StringReader("<xml>blabla</xml>")); StringWriter

Spring WS - step by step in STS (from WSDL) [closed]

会有一股神秘感。 提交于 2019-12-02 19:35:14
I am trying to create a new Spring webservice project in Spring Tool Suite (STS). I checked this link http://static.springsource.org/spring-ws/site/reference/html/tutorial.html But this doesn't tell the steps very clearly. Can anyone please share links to some useful resources that show step-by-step how to create a Spring WS project? I found this small article on how to create a simple web service using Spring . This is in line with Spring tutorial. Perhaps this will help. http://codereq.com/spring-web-service-part-1/ Thanks, Tejas. Maybe these links will be helpful: Step by step Spring-WS

InaccessibleWSDLException error from SOAP generated client in JAVA

一个人想着一个人 提交于 2019-12-02 13:43:24
问题 We are working with service provider's wsdl which is not discoverable due to security reason and they provide us a bunch of files including wsdl ,xsd etc.We need to access the provider's api. For these reason we have done these following things: We have generated a web service client using netbean 8.0 form desktop location (Local File ) Using generated client code we have called the api using these following code URL url = new URL("http://serverip:port/payment/services/MgrService");

Spring-WS WSA header contains hardcoded mustUnderstand attribute

我与影子孤独终老i 提交于 2019-12-02 12:28:27
When sending WSA headers with Spring-WS, the wsa:To field always contains the attribute mustUnderstand="true". By looking at the source code, I found that this attribute is hardcoded in AbstractAddressingVersion.java. Based on the W3 standard the mustUnderstand attribute is not mandatory I think. Is there a reason why Spring-WS hardcodes it? We have difficulties when integrating Spring-WS with some other SOAP stacks because of this attribute. If you file a JIRA here , we can make it customizable. 来源: https://stackoverflow.com/questions/29648586/spring-ws-wsa-header-contains-hardcoded

Spring-ws: How to create Wsdl from an xsd with no “Request” element

北城余情 提交于 2019-12-02 08:49:45
问题 Trying to implement a SOAP Webservice for a client and I need a wsdl file to test the service by soapUI. But as you can see below, this xsd has no Request and Response methods, all requests and responses are defined as a a "type" in a base ServiceProvider element. So when I try to auto generate my wsdl file by spring-ws it does not generate a proper wsdl, because Spring-ws requires all requests and responses element names should end with "Request" "Response". What can I do? <xs:schema xmlns

Spring-ws: How to create Wsdl from an xsd with no “Request” element

二次信任 提交于 2019-12-02 05:36:37
Trying to implement a SOAP Webservice for a client and I need a wsdl file to test the service by soapUI. But as you can see below, this xsd has no Request and Response methods, all requests and responses are defined as a a "type" in a base ServiceProvider element. So when I try to auto generate my wsdl file by spring-ws it does not generate a proper wsdl, because Spring-ws requires all requests and responses element names should end with "Request" "Response". What can I do? <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified"

How to consume third party WSDL services in Spring MVC

血红的双手。 提交于 2019-12-02 04:26:48
问题 I wrote some services (used by an Android app) which takes a request and sends th response in json. Now I have a scenario where I have to consume a third party web service, through a provided WSDL file. I don't know how to do this, can anyone help? This is my dispatcher-servlet.xml: <?xml version="1.0" encoding="UTF-8"?> <beans "> <context:property-placeholder location="classpath:jdbc.properties" /> <context:component-scan base-package="com.srihari" /> <tx:annotation-driven transaction