split

train,validation, test split model in CARET in R

南笙酒味 提交于 2021-02-11 08:35:59
问题 I would like to ask for help please. I use this code to run the XGboost model in the Caret package. However, I want to use the validation split based on time. I want 60% training, 20% validation ,20% testing. I already split the data, but I do know how to deal with the validation data if it is not cross-validation. Thank you, xgb_trainControl = trainControl( method = "cv", number = 5, returnData = FALSE ) xgb_grid <- expand.grid(nrounds = 1000, eta = 0.01, max_depth = 8, gamma = 1, colsample

train,validation, test split model in CARET in R

霸气de小男生 提交于 2021-02-11 08:35:28
问题 I would like to ask for help please. I use this code to run the XGboost model in the Caret package. However, I want to use the validation split based on time. I want 60% training, 20% validation ,20% testing. I already split the data, but I do know how to deal with the validation data if it is not cross-validation. Thank you, xgb_trainControl = trainControl( method = "cv", number = 5, returnData = FALSE ) xgb_grid <- expand.grid(nrounds = 1000, eta = 0.01, max_depth = 8, gamma = 1, colsample

Mulesoft 3 DataWeave - split a string by an arbitrary length

懵懂的女人 提交于 2021-02-11 07:09:04
问题 In Mule 3 DataWeave, how do I split a long string into multiple lines by a set length? For instance, I have the following JSON input: { "id" : "123", "text" : "There is no strife, no prejudice, no national conflict in outer space as yet. Its hazards are hostile to us all. Its conquest deserves the best of all mankind, and its opportunity for peaceful cooperation many never come again." } The input system can only accept strings of 40 characters or less, so the output XML needs to conform as

Mulesoft 3 DataWeave - split a string by an arbitrary length

删除回忆录丶 提交于 2021-02-11 07:08:50
问题 In Mule 3 DataWeave, how do I split a long string into multiple lines by a set length? For instance, I have the following JSON input: { "id" : "123", "text" : "There is no strife, no prejudice, no national conflict in outer space as yet. Its hazards are hostile to us all. Its conquest deserves the best of all mankind, and its opportunity for peaceful cooperation many never come again." } The input system can only accept strings of 40 characters or less, so the output XML needs to conform as

Mulesoft 3 DataWeave - split a string by an arbitrary length

十年热恋 提交于 2021-02-11 07:08:10
问题 In Mule 3 DataWeave, how do I split a long string into multiple lines by a set length? For instance, I have the following JSON input: { "id" : "123", "text" : "There is no strife, no prejudice, no national conflict in outer space as yet. Its hazards are hostile to us all. Its conquest deserves the best of all mankind, and its opportunity for peaceful cooperation many never come again." } The input system can only accept strings of 40 characters or less, so the output XML needs to conform as

Split a Path and take out only the last part (filename) Powershell

故事扮演 提交于 2021-02-10 19:58:55
问题 I'm very new to powershell and im currently trying to write a script that finds a referenced filepath in a file, takes out only the last part of the path (The filename) and moves it to the same destination like the folder containing it. I have a functional script that does what i want, the only thing left is that its not supposed to look for the whole path of the referenced file. Because the path isnt correct anymore. It should just look for the filename and find and move it. This is my

Python: split string by a multi-character delimiter unless inside quotes

梦想的初衷 提交于 2021-02-10 03:26:10
问题 In my case the delimiter string is ' ' (3 consecutive spaces, but the answer should work for any multi-character delimiter), and an edge case text to search in could be this: 'Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End' The solution should return the following strings: Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End I've looked for regex solutions, evaluating also the inverse problem ( match multi-character delimiter unless inside quotes ),

Python: split string by a multi-character delimiter unless inside quotes

喜欢而已 提交于 2021-02-10 03:25:43
问题 In my case the delimiter string is ' ' (3 consecutive spaces, but the answer should work for any multi-character delimiter), and an edge case text to search in could be this: 'Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End' The solution should return the following strings: Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End I've looked for regex solutions, evaluating also the inverse problem ( match multi-character delimiter unless inside quotes ),

Python: split string by a multi-character delimiter unless inside quotes

二次信任 提交于 2021-02-10 03:24:51
问题 In my case the delimiter string is ' ' (3 consecutive spaces, but the answer should work for any multi-character delimiter), and an edge case text to search in could be this: 'Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End' The solution should return the following strings: Coord="GLOB"AL Axis=X Type="Y ZR" Color="Gray Dark" Alt="Q Z"qz Loc=End I've looked for regex solutions, evaluating also the inverse problem ( match multi-character delimiter unless inside quotes ),

Walk through a list split function in Haskell

血红的双手。 提交于 2021-02-08 14:11:47
问题 This is a follow up to my previous question. I am trying to understand the list splitting example in Haskell from here: foldr (\a ~(x,y) -> (a:y,x)) ([],[]) I can read Haskell and know what foldr is but don't understand this code. Could you walk me through this code and explain it in more details ? 回答1: Let’s try running this function on a sample input list, say [1,2,3,4,5] : We start with foldr (\a ~(x,y) -> (a:y,x)) ([],[]) [1,2,3,4,5] . Here a is the first element of the list, and (x,y)