spinner | 易学教程

spinner expanding beyond screen bounds

阅读更多关于 spinner expanding beyond screen bounds

问题 I have a layout that contains a TableLayout with three rows. Each row has a TextView and a Spinner. The Spinners' column is set to stretch. My problem is that the Spinners are stretching off the edge of the screen when they contain a long string. I would like them to truncate the string instead. Here's a screenshot of the problem: http://www.comicfanboy.net/images/screenshot.png and here's the xml for the layout: <ScrollView xmlns:android="http://schemas.android.com/apk/res/android" android

How do I click the first item in a spinner using Robotium?

阅读更多关于 How do I click the first item in a spinner using Robotium?

问题 I am having problems scrolling up in a spinner to select the first item in a Robotium test case. Here is my code: int pos = solo.getCurrentSpinners().get(0).getSelectedItemPosition(); solo.pressSpinnerItem(0, 0 - pos); pos is 1 when I debug, but Robotium still presses the spinner on index 1 even though I order it to press on -1. What am I doing wrong? Thanks Markus 回答1: Seems they took those classes out now. Just ran into this myself but found a way to do this properly and generically. // 0

Android - How to display a spinner with value but display a different one

阅读更多关于 Android - How to display a spinner with value but display a different one

问题 For my Android app, I need to use a spinner which displays a XML tree. This tree is necesarry for the user to understand the level of the value he can select. Here is a picture of what I have right now: As you can see, I've put some little '>' and some spaces to simulate the tree. What I want now, is when the user select an entry, to display the value without those symbols. Today, the spinner displays the value like that: THe word is " > Supermarket" but what I want is "Supermarket", and only

Android Spinner: How to catch when user exits spinner leaving selected value as-is?

阅读更多关于 Android Spinner: How to catch when user exits spinner leaving selected value as-is?

问题 When a spinner comes up, it usually has a value preselected. If the users explicitly selects another item, my onClickItem handler is getting called. But i did not find a way to detect when the user wants to keep the the currently selected list_item as is? How is the user supposed to exit such a spinner when they like the current value? Could you add a close button or something to just let them exit without having to reselect the already selected item to exit? Also if they do reselect same

Spinner delete items

阅读更多关于 Spinner delete items

问题 I have developed an application in which i have one edit text value of edit text is entered in spinner on button clicked an the item i select to delete gets deleted but the problem is that when i delete the last item of spinner whole spinner list flushes . i want to delete only selected item(only last item) My code is as follows : @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); /////////////////////////////////////

Android - How to get all items in a Spinner?

阅读更多关于 Android - How to get all items in a Spinner?

How do I get all items in a Spinner? I was having trouble trying to search a way to get all items from a Spinner but I was not able to find an elegant solution. The only solution seems to be storing the items list before to add it to the Spinner Is there another better way to do this? A simple and elegant way to do this is, if you know the objects type that the spinner is storing: public class User { private Integer id; private String name; /** Getters and Setters **/ @Override public String toString() { return name; } } Given the previous class and a Spinner that contains a list of User you

Update spinner items based on the selected item of another spinner

阅读更多关于 Update spinner items based on the selected item of another spinner

I am trying to update a spinner by a selected item from another spinner. The following code block describes how I did it. I could successfully update the spinner3 using the if statement inside onItemSelected() method. But my problem is that it seems that a loop just keeps running which automatically selects value "5" from spinner2 (so the Toast just keeps spitting out "You've chosen 5"). When the activity is loaded, the Toast will display each selection from all three spinners. Does it mean that the first selection for each spinner is done when an adapter is set to a spinner? And does binding

Android Spinner Size very large

阅读更多关于 Android Spinner Size very large

I'm trying to get an ICS spinner like in my app, and playing around for hours, finally I'm using HoloEverywhere to get this, and it's working, but I have a little disign issue, is that the spinner is not wrapping its content as I set in the xml, and by default looks like this : Really I googled this for hours, and all I found is that how to resize spinner items and not the view itself, means that I want the spinner to be adjusted to the selected item size like this : Here is my XML: <RelativeLayout android:layout_width="match_parent" android:layout_height="40dp" android:orientation="horizontal

How can I manage the height of android spinner items?

阅读更多关于 How can I manage the height of android spinner items?

I have an android spinner that's populated by a list of strings using an ArrayAdapter and it operates fine, however because of the way the spinner is displayed I'm running into a display height problem with the list items. At first glance it would seem that the ArrayAdapter can use a single layout for displaying options which leads to the problem I'm having. When displaying the current item in the spinner (when the user is not selecting a new item from the list) the spinner pads the text so that the spinner is a reasonable size for clicking on. However when the user taps on it and brings up

JavaFX Spinner empty text nullpointerexception

阅读更多关于 JavaFX Spinner empty text nullpointerexception

问题 I have an issue where an editable JavaFX 8 Spinner causes an uncaught NullPointerException if one clears the editor text and commits and then clicks either the increment or decrement button. This is j8u60 j8u77. With some luck the increment/decrement button will get stuck in depressed state and the NPE's keep flowing locking up the application. The following code reproduces the issue for me: import javafx.application.Application; import javafx.scene.Scene; import javafx.scene.control.Spinner;