sorting

问题 I use the uint64_t Radix sort provided by Louis Ricci (answered Aug 24 '15 at 18:00) Radix_Sort_Uint64. Amazingly fast. I have a data structure which contains 2, uint32_t items and want to sort a large array (20+ million) looking only at the first or last 32 bits, but I want the sort routine to move the entire 64 bit package as a unit. Is there a C language uint64 Radix sort which orders based on a subset of the entire 64 bit quanta as if the data were masked with 0X1111111100000000? 回答1:

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 25 days ago . #include <stdio.h> #include <conio.h> void ascending(int numbers[], int size); int main() { int size=10, numbers[size], i, order; for (i=0; i<10; i++) { printf("please enter a number:"); scanf("%d", &numbers[i]); } ascending(numbers[], size); } void ascending(int numbers[], int size) { int temp, i, sflag, count

问题 What is the best way to sort this: { abc: { string: 'lorem', date: 2 }, enc: { string: 'ipsum', date: 1 } } into this: [{ id: 'enc', string: 'ipsum', date: 1 }, { id: 'abc', string: 'lorem', date: 2 }] I need an array sorted by the date (Number) with a flat object. 回答1: First, you need to convert the original object into an array in the format you want: var arr = []; for (var key in obj) if (obj.hasOwnProperty(key)) { var o = obj[key]; arr.push({ id: key, string: o.string, date: o.date }); }

问题 What is the best way to sort this: { abc: { string: 'lorem', date: 2 }, enc: { string: 'ipsum', date: 1 } } into this: [{ id: 'enc', string: 'ipsum', date: 1 }, { id: 'abc', string: 'lorem', date: 2 }] I need an array sorted by the date (Number) with a flat object. 回答1: First, you need to convert the original object into an array in the format you want: var arr = []; for (var key in obj) if (obj.hasOwnProperty(key)) { var o = obj[key]; arr.push({ id: key, string: o.string, date: o.date }); }

问题 I have a list of 100 items and I want generate a ranked list, the user is asked to rate pairs of items, prompting: "Do you prefer item A or item B instead?". Since it would be really tiring asking every possible combination of those items. Eg. if item 1 is prefered over item 2, and item 2 is preferred over item 3, it's not necessary to compare item 1 and item 3. I'm looking for a algorithm that reduce such comparisons and will give a complete ranked list. If the number of comparisons would be

问题 I have a list of 100 items and I want generate a ranked list, the user is asked to rate pairs of items, prompting: "Do you prefer item A or item B instead?". Since it would be really tiring asking every possible combination of those items. Eg. if item 1 is prefered over item 2, and item 2 is preferred over item 3, it's not necessary to compare item 1 and item 3. I'm looking for a algorithm that reduce such comparisons and will give a complete ranked list. If the number of comparisons would be

问题 I have a Elastic Search server setup where am storing company names to be used for for company search, the way it works is: From company name, spaces and dots will be removed and stored in ES in a field called trimmedcompanyname, { "companyName" : "RECKON INFOSYSTEM PRIVATE LIMITED", "trimmedCompanyName" : "reckoninfosystemprivatelimited", "id" : "1079" } now when search comes to my server i remove the spaces and dots and then make request to ES server. The ES request in query format is: GET

问题 I have gone through Merge sort algorithm. I understood the logic, but I didn't get why we have to copy the b[] array again into the a[] array. What we have entered in the b[] array are sorted numbers only, right? But, if we print the b[] array, we are getting unsorted array. Once we copy it into the a[] array, we are getting the correct output. Can anyone explain why we have to copy the b[] array to the a[] array? Algorithm:: void MergeSort(int low, int high) { if (low < high) { int mid =

问题 I have gone through Merge sort algorithm. I understood the logic, but I didn't get why we have to copy the b[] array again into the a[] array. What we have entered in the b[] array are sorted numbers only, right? But, if we print the b[] array, we are getting unsorted array. Once we copy it into the a[] array, we are getting the correct output. Can anyone explain why we have to copy the b[] array to the a[] array? Algorithm:: void MergeSort(int low, int high) { if (low < high) { int mid =

问题 I have gone through Merge sort algorithm. I understood the logic, but I didn't get why we have to copy the b[] array again into the a[] array. What we have entered in the b[] array are sorted numbers only, right? But, if we print the b[] array, we are getting unsorted array. Once we copy it into the a[] array, we are getting the correct output. Can anyone explain why we have to copy the b[] array to the a[] array? Algorithm:: void MergeSort(int low, int high) { if (low < high) { int mid =