sorting

How can we calculate weighted cumulative sum of squares with prefix range updates by one?

被刻印的时光 ゝ 提交于 2020-05-10 06:45:11
问题 Given an array A with n elements which starts with all 0 s and another array W also with n elements (all greater than 0 ), we want to perform the following operation repeatedly; For a given k, increment A[0], A[1], .... A[k] each by 1, and report the value of A[0]^2 * W[0] + A[1]^2 * W[1] + ... + A[n-1]^2 * W[n-1] . Looking for an O(log n) solution (per query), or faster. 来源: https://stackoverflow.com/questions/61122170/how-can-we-calculate-weighted-cumulative-sum-of-squares-with-prefix-range

How to sort a dictionary based on a list in python

有些话、适合烂在心里 提交于 2020-05-10 04:08:57
问题 I have a dictionary a = {'ground': obj1, 'floor 1': obj2, 'basement': obj3} I have a list. a_list = ['floor 1', 'ground', 'basement'] I want to sort dictionary a using its keys based on the list. Is it possible to do that? i.e.: sort(a).based_on(a_list) #this is wrong. But I want something like this. The output doesn't have to be another dictionary, I don't mind converting the dictionary to tuples and then sort those. 回答1: The naive way, sorting the list of (key, value) tuples, using the

How to sort a dictionary based on a list in python

久未见 提交于 2020-05-10 04:04:40
问题 I have a dictionary a = {'ground': obj1, 'floor 1': obj2, 'basement': obj3} I have a list. a_list = ['floor 1', 'ground', 'basement'] I want to sort dictionary a using its keys based on the list. Is it possible to do that? i.e.: sort(a).based_on(a_list) #this is wrong. But I want something like this. The output doesn't have to be another dictionary, I don't mind converting the dictionary to tuples and then sort those. 回答1: The naive way, sorting the list of (key, value) tuples, using the

How to sort a dictionary based on a list in python

随声附和 提交于 2020-05-10 04:04:38
问题 I have a dictionary a = {'ground': obj1, 'floor 1': obj2, 'basement': obj3} I have a list. a_list = ['floor 1', 'ground', 'basement'] I want to sort dictionary a using its keys based on the list. Is it possible to do that? i.e.: sort(a).based_on(a_list) #this is wrong. But I want something like this. The output doesn't have to be another dictionary, I don't mind converting the dictionary to tuples and then sort those. 回答1: The naive way, sorting the list of (key, value) tuples, using the

composing two comparison functions?

落爺英雄遲暮 提交于 2020-05-09 18:39:12
问题 I'd like to sort by one property and then by another (if the first property is the same.) What's the idiomatic way in Haskell of composing two comparison functions, i.e. a function used with sortBy ? Given f :: Ord a => a -> a -> Ordering g :: Ord a => a -> a -> Ordering composing f and g would yield: h x y = case v of EQ -> g x y otherwise -> v where v = f x y 回答1: vitus points out the very cool instance of Monoid for Ordering . If you combine it with the instance instance Monoid b => Monoid

Access private variables outside of a class in Java using comparator [duplicate]

谁说我不能喝 提交于 2020-05-09 17:38:07
问题 This question already has answers here : How to sort a list by a private field? (10 answers) Closed 18 days ago . Struggling to figure out how to access private attributes outside of a class in Java, using comparator. I'm using some code online as reference. If you change the private to public it works, but I need to know how to make it work with the variables set as private. // Java program to demonstrate working of Comparator // interface import java.util.*; import java.lang.*; import java

Access private variables outside of a class in Java using comparator [duplicate]

亡梦爱人 提交于 2020-05-09 17:37:05
问题 This question already has answers here : How to sort a list by a private field? (10 answers) Closed 18 days ago . Struggling to figure out how to access private attributes outside of a class in Java, using comparator. I'm using some code online as reference. If you change the private to public it works, but I need to know how to make it work with the variables set as private. // Java program to demonstrate working of Comparator // interface import java.util.*; import java.lang.*; import java

How Sort A List<string> By A Part Of That String Desc

冷暖自知 提交于 2020-05-09 06:03:14
问题 i have a list like this : List<string> list_lines = new List<string>(); list_lines.add("name1__pass1__com__14__55"); list_lines.add("name2__pass2__com__14__5445"); list_lines.add("name3__pass3__com__14__456456"); list_lines.add("name4__pass4__com__14__1357"); list_lines.add("name5__pass5__com__14__20000"); list_lines.add("name6__pass6__com__14__25"); list_lines.add("name7__pass7__com__14__12"); and more... as you see there is a separator here -> "__" in every string in that list. mean :

Sorting non English names in Javascripts [duplicate]

霸气de小男生 提交于 2020-05-08 19:09:28
问题 This question already has answers here : How to compare Unicode strings in Javascript? (6 answers) Closed 5 years ago . I'm using the following script in order to sort (alphabetically) columns in HTML tables. The script works like a charm except that I don't have full control of non-English characters. If I have a word beginning with “Ü” for example, this is not treated like a “U” (as it should be). There is an easy way to transliterate characters before performing the sorting (like ü->u, ä-

Sorting non English names in Javascripts [duplicate]

三世轮回 提交于 2020-05-08 19:07:28
问题 This question already has answers here : How to compare Unicode strings in Javascript? (6 answers) Closed 5 years ago . I'm using the following script in order to sort (alphabetically) columns in HTML tables. The script works like a charm except that I don't have full control of non-English characters. If I have a word beginning with “Ü” for example, this is not treated like a “U” (as it should be). There is an easy way to transliterate characters before performing the sorting (like ü->u, ä-