sorting

How to find indices of a reordered numpy array?

让人想犯罪 __ 提交于 2020-06-10 03:53:29
问题 Say I have a sorted numpy array: arr = np.array([0.0, 0.0], [0.5, 0.0], [1.0, 0.0], [0.0, 0.5], [0.5, 0.5], [1.0, 0.5], [0.0, 1.0], [0.5, 1.0], [1.0, 1.0]) and suppose I make a non trivial operation on it such that I have a new array which is the same as the old one but in another order: arr2 = np.array([0.5, 0.0], [0.0, 0.0], [0.0, 0.5], [1.0, 0.0], [0.5, 0.5], [1.0, 0.5], [0.0, 1.0], [1.0, 1.0], [0.5, 1.0]) The question is: how do you get the indices of where each element of arr2 are placed

Custom sorting on a laravel relationship collection

心不动则不痛 提交于 2020-06-10 03:44:30
问题 I'm a little stuck on something that usually is quite straight forward. I need to sort records from a hasMany relationship into a custom order based on a certain value and an 'sort order' array. My code below doesn't work because I'm passing uSort() a eloquent collection and I'm not sure how to get around it. $go = $this->hasMany('Product')->orderBy('colour','DESC'); $order = array('RED', 'GREEN', 'BLUE', 'YELLOW'); usort($go, function ($a, $b) use ($order) { $pos_a = array_search($a->colour,

Python Pandas sorting after groupby and aggregate

旧街凉风 提交于 2020-06-10 03:35:32
问题 I am trying to sort data (Pandas) after grouping and aggregating and I am stuck. My data: data = {'from_year': [2010, 2011, 2012, 2011, 2012, 2010, 2011, 2012], 'name': ['John', 'John1', 'John', 'John', 'John4', 'John', 'John1', 'John6'], 'out_days': [11, 8, 10, 15, 11, 6, 10, 4]} persons = pd.DataFrame(data, columns=["from_year", "name", "out_days"]) days_off_yearly = persons.groupby(["from_year", "name"]).agg({"out_days": [np.sum]}) print(days_off_yearly) After that I have my data sorted:

Python Pandas sorting after groupby and aggregate

一世执手 提交于 2020-06-10 03:34:56
问题 I am trying to sort data (Pandas) after grouping and aggregating and I am stuck. My data: data = {'from_year': [2010, 2011, 2012, 2011, 2012, 2010, 2011, 2012], 'name': ['John', 'John1', 'John', 'John', 'John4', 'John', 'John1', 'John6'], 'out_days': [11, 8, 10, 15, 11, 6, 10, 4]} persons = pd.DataFrame(data, columns=["from_year", "name", "out_days"]) days_off_yearly = persons.groupby(["from_year", "name"]).agg({"out_days": [np.sum]}) print(days_off_yearly) After that I have my data sorted:

Generating Ascending Sequence 2^p*3^q

…衆ロ難τιáo~ 提交于 2020-06-09 10:26:41
问题 I was interested in implementing a specific Shellsort method I read about that had the same time complexity as a bitonic sort. However, it requires the gap sequence to be the sequence of numbers [1, N-1] that satisfy the expression 2^p*3^q for any integers p and q. In layman's terms, all the numbers in that range that are only divisible by 2 and 3 an integer amount of times. Is there a relatively efficient method for generating this sequence? 回答1: Numbers of that form are called 3-smooth.

Generating Ascending Sequence 2^p*3^q

点点圈 提交于 2020-06-09 10:26:30
问题 I was interested in implementing a specific Shellsort method I read about that had the same time complexity as a bitonic sort. However, it requires the gap sequence to be the sequence of numbers [1, N-1] that satisfy the expression 2^p*3^q for any integers p and q. In layman's terms, all the numbers in that range that are only divisible by 2 and 3 an integer amount of times. Is there a relatively efficient method for generating this sequence? 回答1: Numbers of that form are called 3-smooth.

Sort an array according to a property which may be null

喜欢而已 提交于 2020-06-08 19:58:31
问题 I ve an array of objects : let items = [ { name: 'eric', value: 1 }, { name: 'bob', value: 4 }, { name: 'michael', value: 0 }, { name: 'john', value: 3 }, { name: 'brad', value: null }, { name: 'martin', value: 2 }, { name: 'chris', value: null } ]; i want to sort my array so that the objects can be sorted by the "value" attribute , and if it's null , make the object in the bottom of the array : { name: 'michael', value: 0 }, { name: 'eric', value: 1 }, { name: 'martin', value: 2 }, { name:

Change sorting of WooCommerce My account customer orders

大憨熊 提交于 2020-06-08 19:42:31
问题 In WooCommerce, customers can log in to their account and see the order history. By default the orders are displaying with the newest order date first. I want to turn this around, so the order with the oldest date shows first. I can't find any place to change ordering from ASC/DESC, looking in the template file woocoommerce/myaccount/orders.php file. <table class="woocommerce-orders-table woocommerce-MyAccount-orders shop_table shop_table_responsive my_account_orders account-orders-table">

Change sorting of WooCommerce My account customer orders

∥☆過路亽.° 提交于 2020-06-08 19:42:06
问题 In WooCommerce, customers can log in to their account and see the order history. By default the orders are displaying with the newest order date first. I want to turn this around, so the order with the oldest date shows first. I can't find any place to change ordering from ASC/DESC, looking in the template file woocoommerce/myaccount/orders.php file. <table class="woocommerce-orders-table woocommerce-MyAccount-orders shop_table shop_table_responsive my_account_orders account-orders-table">

Sort one array the same way as another array JavaScript

◇◆丶佛笑我妖孽 提交于 2020-06-08 07:40:45
问题 I have 2 arrays: [2, 4, -2, 4, 1, 3] ["a", "b", "c", "d", "e", "f"] and I want them to be sorted by the numerical array: // output [-2, 1, 2, 3, 4, 4] // <-sorted by numerical order ["c", "e", "a", "f", "b", "d"] // sorted exactly the same order as the first array while its actually not important if "b" or "d" comes first (they both have 4 in this example) I found many questions about this online but none of them worked for me can anyone help me with that? 回答1: You could sort the keys of the