sorting

Sorting table rows based on column class names using jquery

懵懂的女人 提交于 2021-01-06 08:46:59
问题 Very similair to this question: Sort table rows based on their Class Names Consider the following table: <table> <thead> <th>A column</th> </thead> <tbody> <tr> <td class="x">A</td> </tr> <tr> <td class="c">B</td> </tr> <tr> <td class="">C</td> </tr> </tbody> </table> I would like to sort rows based on the first (in this case only) column class name. Some td don't have a class specified. So the desired effect would be: A-B-C -> C-B-A or B-A-C (I don't care where the classless tds are placed).

Javascript sort array by key descending Google Chrome

我的梦境 提交于 2021-01-05 13:16:44
问题 I have an array and need to sort it in descending order by the key. All working good in Firefox but in Chrome it's showing in the original order [["0", 0], ["1", 0.9], ["2", 597.5344192965547], ["3", 991.0326954186761], ["4", 1257.2580315846578], ["5", 1293.5250901880618], ["6", 2197.1091224116512], ["7", 2225.0422585266947], ["8", 3964.1307816747044], ["9", 6914.072436146399]] This is the code I am using sortable.sort(function(a,b){return b-a}) So in Firefox it returns the correct result [[

Javascript sort array by key descending Google Chrome

心已入冬 提交于 2021-01-05 13:14:43
问题 I have an array and need to sort it in descending order by the key. All working good in Firefox but in Chrome it's showing in the original order [["0", 0], ["1", 0.9], ["2", 597.5344192965547], ["3", 991.0326954186761], ["4", 1257.2580315846578], ["5", 1293.5250901880618], ["6", 2197.1091224116512], ["7", 2225.0422585266947], ["8", 3964.1307816747044], ["9", 6914.072436146399]] This is the code I am using sortable.sort(function(a,b){return b-a}) So in Firefox it returns the correct result [[

How to sort an array with respect to another array if there are duplicates?

大城市里の小女人 提交于 2021-01-05 08:51:11
问题 I could sort an array with respect to another if there is unique value. But since i am trying sort the below given array: initial fuel[]={1,9,9,2,9,9}; initial cost[]={2,6,5,4,3,1}; I wanted to sort fuel array then again wanted to sort cost array with respect to fuel array. I wanted output like given below: final fuel[]={1,2,9,9,9,9}; final cost[]={2,4,6,5,3,1}; Below is my code: public static void sort(List<Integer> c, List<Integer> f) { List<Integer> cc = new ArrayList<>(c); Collections

How to sort an array with n elements in which k elements are out of place in O(n + k log k)?

大城市里の小女人 提交于 2021-01-04 06:44:04
问题 I was asked this in an interview today, and am starting to believe it is not solvable. Given a sorted array of size n , select k elements in the array, and reshuffle them back into the array, resulting in a new "nk-sorted" array. Find the k (or less) elements that have moved in that new array. Here is (Python) code that creates such arrays, but I don't care about language for this. import numpy as np def __generate_unsorted_array(size, is_integer=False, max_int_value=100000): return np.random

Grouping, splitting and picking top rows in a dataframe

我与影子孤独终老i 提交于 2021-01-04 05:59:07
问题 Problem In the following dataframe df : import random import pandas as pd random.seed(999) sz = 50 qty = {'one': 1, 'two': 2, 'three': 3} thing = (random.choice(['one', 'two', 'three']) for _ in range(sz)) order = (random.choice(['ascending', 'descending']) for _ in range(sz)) value = (random.randint(0, 100) for _ in range(sz)) df = pd.DataFrame({'thing': thing, 'order': order, 'value': value}) ... I would like to: Group by thing Split it by order Sort it by value for the thing per its order

Grouping, splitting and picking top rows in a dataframe

折月煮酒 提交于 2021-01-04 05:58:54
问题 Problem In the following dataframe df : import random import pandas as pd random.seed(999) sz = 50 qty = {'one': 1, 'two': 2, 'three': 3} thing = (random.choice(['one', 'two', 'three']) for _ in range(sz)) order = (random.choice(['ascending', 'descending']) for _ in range(sz)) value = (random.randint(0, 100) for _ in range(sz)) df = pd.DataFrame({'thing': thing, 'order': order, 'value': value}) ... I would like to: Group by thing Split it by order Sort it by value for the thing per its order

Grouping, splitting and picking top rows in a dataframe

旧巷老猫 提交于 2021-01-04 05:58:21
问题 Problem In the following dataframe df : import random import pandas as pd random.seed(999) sz = 50 qty = {'one': 1, 'two': 2, 'three': 3} thing = (random.choice(['one', 'two', 'three']) for _ in range(sz)) order = (random.choice(['ascending', 'descending']) for _ in range(sz)) value = (random.randint(0, 100) for _ in range(sz)) df = pd.DataFrame({'thing': thing, 'order': order, 'value': value}) ... I would like to: Group by thing Split it by order Sort it by value for the thing per its order

Sorting an array of classes based only on field name

时间秒杀一切 提交于 2021-01-04 05:43:52
问题 I have an application where a user provides me with the name of a field, e.g name or costInCents , and I have to sort by that field. I have ways of guaranteeing that the field name will be correct. This application causes the complication that I simply cannot make my class Comparable and implement a specific compareTo() , since with a custom implementation of compareTo() I need to know which fields / methods to use at implementation time. So to achieve this goal, I am trying to use reflection

Sorting an array of classes based only on field name

你说的曾经没有我的故事 提交于 2021-01-04 05:43:08
问题 I have an application where a user provides me with the name of a field, e.g name or costInCents , and I have to sort by that field. I have ways of guaranteeing that the field name will be correct. This application causes the complication that I simply cannot make my class Comparable and implement a specific compareTo() , since with a custom implementation of compareTo() I need to know which fields / methods to use at implementation time. So to achieve this goal, I am trying to use reflection