sorting

How to sort items in Qt QListview using Qt.UserRole

穿精又带淫゛_ 提交于 2020-01-06 01:51:54
问题 I'm having some problem sorting the items in my QListView using values in a field I specified. Basically what I'm trying to do is this: Detect faces in a collection of photos and display them in a QListView Cluster the faces (images) Update the view by placing items in the list (which are face images) belonging to the same cluster in together. Concretely, if item 1, 3, 5 are in one cluster and items 2, 4, 6 are in another, then items 1, 3, 5 should be displayed (in whatever permutations)

VBA Sort Macro not working

倾然丶 夕夏残阳落幕 提交于 2020-01-06 01:16:28
问题 The sort code is not working anymore. It worked the first time. Then I closed it and opened it and then it gave me an error. (I didn't change anything.) It gave me: Error 438: Object doesn't support this property or method On this line: DataWB.DataSheet.Sort.SortFields.Add Key:=Range(FNOrdCol), SortOn:=xlSortOnValues, _ Order:=xlAscending, DataOption:=xlSortNormal` Snippet of sort code: 'Alpahebtical order DataSheet.Range("A1").Select ActiveCell.Rows("1:1").EntireRow.Select Selection.Find

Quick Sort - Middle Pivot implementation strange behaviour

折月煮酒 提交于 2020-01-05 23:59:53
问题 I am trying to implement quick sort with pivot value as middle element of the vector using various tutorials available online. Even though it's working for some samples there's one where I am not able to get sorted vector. Example - Input {5,3,8,6,1,0,4} but output is {0,3,4,5,1,6,8} QuickSort implementation void quickSortMiddle(vector<int> &a, int left, int right) { if(left >=right) return; int leftI = left; int rightI = right; int pivot = left + (right - left)/2; while(leftI<=rightI) {

sort a SKSpriteNode array according to a specific element

流过昼夜 提交于 2020-01-05 21:17:20
问题 I have a SKSpriteNode array declared like this : class rgbNodes: SKSpriteNode { } var colorNode = [rgbNodes]() colorNode.append(rgbNodes(imageNamed: "Rectangle")) // every time we want to add a new element to this array And I would like to sort every element of this array according to their position.x value, for example, if : colorNode[0].position.x = 25 colorNode[1].position.x = 5 colorNode[2].position.x = 15 I want the array to be sorted like this : colorNode[0].position.x = 5 colorNode[1]

Understanding the Basics of Generics Sorting

时光毁灭记忆、已成空白 提交于 2020-01-05 20:28:50
问题 There are a number of question on Stack Overflow about sorting Generics; however, I am interested in sorting Generics in the simplest way: nothing nested. The code I have below is an attempt to sort a generic set - or, list - of elements. List<E> l = new LinkedList<>(arbSet); Collections.sort(l); arbSet is just a set of elements: Set<E> arbSet . Clearly, this is problematic - it shouldn't work. To make sure I know this, Eclipse gives me the following for my attempt to call .sort : Bound

Does not work correctly in browsers jquery sorting (Opera, Chrome)

╄→尐↘猪︶ㄣ 提交于 2020-01-05 19:47:26
问题 Not working properly sorting the list (class = "ytube_date") in other browsers (Opera, Chrome, IE). Works correctly only in firefox v22.0. Tell me how to do the sorting by date video? My code is in jsfiddle. Some values ​​ class = "ytube_date" - empty jquery: function sortDescending(a, b) { var date1 = $(a).find(".ytube_date").text(); date1 = date1.split('-'); var date2 = $(b).find(".ytube_date").text(); date2 = date2.split('-'); return date1 < date2; }; $(document).ready(function() { $('#all

Does not work correctly in browsers jquery sorting (Opera, Chrome)

你说的曾经没有我的故事 提交于 2020-01-05 19:47:21
问题 Not working properly sorting the list (class = "ytube_date") in other browsers (Opera, Chrome, IE). Works correctly only in firefox v22.0. Tell me how to do the sorting by date video? My code is in jsfiddle. Some values ​​ class = "ytube_date" - empty jquery: function sortDescending(a, b) { var date1 = $(a).find(".ytube_date").text(); date1 = date1.split('-'); var date2 = $(b).find(".ytube_date").text(); date2 = date2.split('-'); return date1 < date2; }; $(document).ready(function() { $('#all

Sorting a hash based on an array representing order

空扰寡人 提交于 2020-01-05 15:46:02
问题 I have a hash like this: data = {"Blood Group"=>"A", "Next Review Date"=>"22/06/2016", "Tourniquet Time"=>"23", "BMI"=>"21"} I have a sorting order in an array: sorting_order = [1, 0, 2, 3] I want to rearrange the hash according to the sorting order array so that the hash becomes: data = {"Next Review Date"=>"22/06/2016", "Blood Group"=>"A", "Tourniquet Time"=>"23", "BMI"=>"21"} I tried: sorted_hash = sorting_order.map{|x| data[x]} It returns: NoMethodError: undefined method `[]' for #

Sorting a hash based on an array representing order

自作多情 提交于 2020-01-05 15:45:23
问题 I have a hash like this: data = {"Blood Group"=>"A", "Next Review Date"=>"22/06/2016", "Tourniquet Time"=>"23", "BMI"=>"21"} I have a sorting order in an array: sorting_order = [1, 0, 2, 3] I want to rearrange the hash according to the sorting order array so that the hash becomes: data = {"Next Review Date"=>"22/06/2016", "Blood Group"=>"A", "Tourniquet Time"=>"23", "BMI"=>"21"} I tried: sorted_hash = sorting_order.map{|x| data[x]} It returns: NoMethodError: undefined method `[]' for #

sort() returns None

元气小坏坏 提交于 2020-01-05 15:38:14
问题 Code: import math import time import random class SortClass(object): def sort1(self, l): if len(l)==1: return l elif len(l)==2: if l[0]<l[1]: return l else: return l[::-1] else: pivot=math.floor(len(l)/2) a=l[pivot:] b=l[:pivot] a2=self.sort1(a) b2=self.sort1(b) if a2==None or b2==None: a2=[] b2=[] return (a2+b2).sort() return [] Sort=SortClass() x=[20,19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1] print(Sort.sort1(x)) The code outputs None even though it should return an empty list in two