sorting

问题 I have an array of characters String a = "badabcde"; char[] chArr = a.toCharArray(); // 'b','a','d','a','b','c','d','e' What's the easiest way to sort only a section of the array, given a start and end index? // 'b','a','d','a','b','c','d','e' subSort(array, startIndex, endIndex); Ex: subSort(chArr, 2, 5); // 'b','a','a','b','c','d','d','e' // sorts indices 2 to 5 回答1: I think public static void sort(char[] a, int fromIndex, int toIndex) answers your question. String a = "badabcde"; char[]

问题 How i can use python to sort the list format format=["12 sheet","4 sheet","48 sheet","6 sheet", "busrear", "phonebox","train"] like this way format =["4 sheet", "6 sheet", "12 sheet", "48 sheet", "busrear", "phonebox", "train"] whose answer is here Python sort array of string with integers inside but If the array is a list of list then how can we do that like this one format=[[1, '12 sheet', 0],[2, '4 sheet', 0], [3, '48 sheet', 0], [4, '6 sheet', 0 [5, 'Busrear', 0], [6, 'phonebox', 0], [7,

问题 Is there a way to implement back pagination with firestore? I am struggling to implement pagination with firestore, and there are limited firestore queries for it. Forward pagination can be made by startAt and limit method, that is ok. But back pagination can't be easily done, because we only have endBefore , and endAt method, and how can we get last n elements from given document? I know realtime database have method limitToLast . Is there any query like this for firestore? (Also I need to

问题 i wants to separate an array with two groups (odd and even) sequentially. but when i try this: var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9]; for (var i = 0; i < arr.length; i++) { if (arr[i]%2 == 0) { arr.push(arr.splice(i, 1)[0]); } } console.log(arr); console.log(arr); // [1, 3, 5, 7, 9, 4, 8, 6, 2] why 4,8,6,2 instead of 2,4,6,8? 回答1: Because you move every found even value to the end of the array: 0: 1 2 3 4 5 6 7 8 9 ^-------------v 1: 1 3 4 5 6 7 8 9 2 3 is not checked, because of the

问题 does any one have any idea how to sort a list of words in the order of their frequency (least to greatest) using the built in collection.sort and a comparator<string> interface? I already have a method that gets the count of a certain word in the text file. Now, I just need to create a method that compares the counts of each word and then puts them in a list sorted by the least frequency to the greatest. Any ideas and tips would be very much appreciated. I'm having trouble getting started on

问题 does any one have any idea how to sort a list of words in the order of their frequency (least to greatest) using the built in collection.sort and a comparator<string> interface? I already have a method that gets the count of a certain word in the text file. Now, I just need to create a method that compares the counts of each word and then puts them in a list sorted by the least frequency to the greatest. Any ideas and tips would be very much appreciated. I'm having trouble getting started on

问题 I want to sort an ArrayList<String> but the problem is my native language characters - my alphabet is like this: a, ą, b, c, č, d, e, f ... z, ž . As you see z character is second from the end and ą is second in alphabet, so after I sort my array it is sorted incorrectly. All my native language characters are moved to the end of array. Example: package lt; import java.util.ArrayList; import java.util.Collections; public class test { public static void main(String[] args) { List<String> items

问题 Does anyone know what the function is to perform a natural order sort using the usort function in PHP on an object. Lets say the object ($obj->Rate)has a range of values in $obj->10 $obj->1 $obj->2 $obj->20 $obj->22 What is I am trying to get the sort function to return $obj->22 $obj->20 $obj->10 $obj->2 $obj->1 As my current standard sort function function MySort($a, $b) { if ($a->Rate == $b->Rate) { return 0; } return ($a->Rate < $b->Rate) ? -1 : 1; } is returning $obj->1 $obj->10 $obj->2

问题 Does anyone know what the function is to perform a natural order sort using the usort function in PHP on an object. Lets say the object ($obj->Rate)has a range of values in $obj->10 $obj->1 $obj->2 $obj->20 $obj->22 What is I am trying to get the sort function to return $obj->22 $obj->20 $obj->10 $obj->2 $obj->1 As my current standard sort function function MySort($a, $b) { if ($a->Rate == $b->Rate) { return 0; } return ($a->Rate < $b->Rate) ? -1 : 1; } is returning $obj->1 $obj->10 $obj->2

问题 Suppose I have a Javascript array, like so: var test = ['b', 'c', 'd', 'a']; I want to sort the array. Obviously, I can just do this to sort the array: test.sort(); //Now test is ['a', 'b', 'c', 'd'] But what I really want is an array of indices that indicates the position of the sorted elements with respect to the original elements. I'm not quite sure how to phrase this, so maybe that is why I am having trouble figuring out how to do it. If such a method was called sortIndices(), then what I