sorting

问题 I'm trying to sort an array that sometimes has Infinity or NaN . When I use a standard JavaScript array.sort() it seems to sort until it reaches a NaN and then I get random results after that. var array =[.02,.2,-.2,Nan,Infinity,20]; Is there a way to still sort this so that the end result is from negative to positive and still have NaN or Infinity at the end. -.2,.02,.2,20,NaN,Infinity 回答1: You can catch NaN and Infinity using JavaScript's built-in utility functions for those cases: let

问题 I use below command to sort the pods by age kubectl get pods --sort-by={metadata.creationTimestamp} It shows up pods in descending order. How can we select sorting order like ascending? 回答1: Sorted kubectl output and awk provide the table view with a header. Installation of extra tools is not needed. # kubectl get pods --sort-by=.status.startTime | awk 'NR == 1; NR > 1 {print $0 | "tac"}' An approach with JSON processor offered by paulogrell works also but could require more effort: for some

问题 I use below command to sort the pods by age kubectl get pods --sort-by={metadata.creationTimestamp} It shows up pods in descending order. How can we select sorting order like ascending? 回答1: Sorted kubectl output and awk provide the table view with a header. Installation of extra tools is not needed. # kubectl get pods --sort-by=.status.startTime | awk 'NR == 1; NR > 1 {print $0 | "tac"}' An approach with JSON processor offered by paulogrell works also but could require more effort: for some

问题 I am new to Javascript, I have an array which contains numbers. var arr = [2,4,8,1,5,9,3,7,6]; How can i sort it using native For Loop in javascript. I know sort function is available but i want it through for loop. output should be- var res = [1,2,3,4,5,6,7,8,9]; 回答1: I would do something like that... var input = [2,3,8,1,4,5,9,7,6]; var output = []; var inserted; for (var i = 0, ii = input.length ; i < ii ; i++){ inserted = false; for (var j = 0, jj = output.length ; j < jj ; j++){ if

问题 I am new to Javascript, I have an array which contains numbers. var arr = [2,4,8,1,5,9,3,7,6]; How can i sort it using native For Loop in javascript. I know sort function is available but i want it through for loop. output should be- var res = [1,2,3,4,5,6,7,8,9]; 回答1: I would do something like that... var input = [2,3,8,1,4,5,9,7,6]; var output = []; var inserted; for (var i = 0, ii = input.length ; i < ii ; i++){ inserted = false; for (var j = 0, jj = output.length ; j < jj ; j++){ if

问题 Let's say I have a list like this: time type value 80 1A 10 100 1A 20 60 18 56 80 18 7 80 2A 10 100 2A 10 80 28 10 100 28 20 and I need to change it to be like this: time type 60 80 100 1A 10 20 1B 56 7 2A 10 10 2B 10 20 So far what I did is just basic sorting of the column: target_column = 0 book = open_workbook('result.xls') sheet = book.sheets()[0] data = [sheet.row_values(i) for i in range(sheet.nrows)] labels = data[0] data = data[1:] data.sort(key= lambda x: x[target_column]) bk = xlwt

问题 Let's say I have a list like this: time type value 80 1A 10 100 1A 20 60 18 56 80 18 7 80 2A 10 100 2A 10 80 28 10 100 28 20 and I need to change it to be like this: time type 60 80 100 1A 10 20 1B 56 7 2A 10 10 2B 10 20 So far what I did is just basic sorting of the column: target_column = 0 book = open_workbook('result.xls') sheet = book.sheets()[0] data = [sheet.row_values(i) for i in range(sheet.nrows)] labels = data[0] data = data[1:] data.sort(key= lambda x: x[target_column]) bk = xlwt

问题 I am using Twitter typeahead.js 0.10.5 as a suggestion engine. It works great, with one exception, I can't sort the list of suggestions the way I want. As an example: var data =[{"id":1,"value":"no need"}, {"id":2,"value":"there is no need"}, {"id":3,"value":"in the need of"}, {"id":4,"value":"all I need"}, {"id":5,"value":"need"}, {"id":6,"value":"needs"}, {"id":7,"value":"all he needs"}, {"id":8,"value":"he needs"}, {"id":9,"value":"they need"}, {"id":10,"value":"you need"}] var suggestion

问题 When implementing Insertion Sort, a binary search could be used to locate the position within the first i - 1 elements of the array into which element i should be inserted. How would this affect the number of comparisons required? How would using such a binary search affect the asymptotic running time for Insertion Sort? I'm pretty sure this would decrease the number of comparisons, but I'm not exactly sure why. 回答1: Straight from Wikipedia: If the cost of comparisons exceeds the cost of

问题 I would like to sort my matrix A by column 2 then 3. A = round.(randn(100,4)) Maybe something like: sort(A,(0,2:3)) 100x4 Array{Float64,2}: 0.0 -2.0 -2.0 -1.0 -1.0 -2.0 -1.0 1.0 1.0 -2.0 -1.0 2.0 -1.0 -2.0 0.0 0.0 -1.0 -2.0 0.0 -1.0 -0.0 -2.0 0.0 -1.0 1.0 -2.0 0.0 0.0 1.0 -2.0 1.0 -1.0 -0.0 -2.0 2.0 -1.0 -0.0 -1.0 -2.0 1.0 ⋮ -0.0 1.0 0.0 1.0 1.0 1.0 1.0 1.0 0.0 1.0 1.0 -1.0 -0.0 1.0 2.0 0.0 -0.0 2.0 -1.0 0.0 -2.0 2.0 -1.0 1.0 2.0 2.0 -0.0 -1.0 -1.0 2.0 -0.0 -1.0 1.0 2.0 0.0 2.0 -1.0 2.0 2.0 0