sortedmap

问题 My List is being sorted by the alphabetical order after sorting by date while I am adding extra 4-5 items in my List with different names. I want to sort my List by date and time only. here I have shared my code please help me to do so. thanks in advance. // Filters All patient to keep only single latest record of each patient id private List<PatientData> filterPatients(List<PatientData> allPatientData) throws ParseException { HashMap<String ,Pair<PatientData,Date>> filtered = new HashMap<>()

问题 My List is being sorted by the alphabetical order after sorting by date while I am adding extra 4-5 items in my List with different names. I want to sort my List by date and time only. here I have shared my code please help me to do so. thanks in advance. // Filters All patient to keep only single latest record of each patient id private List<PatientData> filterPatients(List<PatientData> allPatientData) throws ParseException { HashMap<String ,Pair<PatientData,Date>> filtered = new HashMap<>()

问题 My Task In my JavaScript code i'm often using objects to "map" keys to values so i can later access them directly through a certain value. For example: var helloMap = {}; helloMap.de = "Hallo"; helloMap["en"] = "Hello"; helloMap.es = "Hola"; So i build up the map object step by step in my source code using the two available notations object style and array style . Later i can then access the values i added through helloMap["de"] for example. So thats all fine if i don't have to care about the

问题 One can iterate through a SortedMap by using the iterator from myMap.entrySet().iterator() . But does this iterator preserve the ordering of the sorted map object ? The SortedMap interface has no own methods to iterate through the entries. What is the standard way to iterate ordered through the entries ? 回答1: The standard iterator is guaranteed to keep the iteration order exactly the same as the natural order of the keys, for both keys and entries. This is stated in the documentation and can

问题 I have a list of objects I need to sort according to properties of one of their fields. I've heard that SortedMap and Comparators are the best way to do this. Do I implement Comparable with the class I'm sorting, or do I create a new class? How do I instantiate the SortedMap and pass in the Comparator? How does the sorting work? Will it automatically sort everything as new objects are inserted? EDIT: This code is giving me an error: private TreeMap<Ktr> collection = new TreeMap<Ktr>(); (Ktr

问题 I have a list of objects I need to sort according to properties of one of their fields. I've heard that SortedMap and Comparators are the best way to do this. Do I implement Comparable with the class I'm sorting, or do I create a new class? How do I instantiate the SortedMap and pass in the Comparator? How does the sorting work? Will it automatically sort everything as new objects are inserted? EDIT: This code is giving me an error: private TreeMap<Ktr> collection = new TreeMap<Ktr>(); (Ktr

问题 This question already has answers here : Closed 6 years ago . Possible Duplicate: Java: SortedMap, TreeMap, Comparable? How to use? I am using the Java JungI graph package and Netbeans 7. I am getting the following error from Java: Exception in thread "main" java.lang.ClassCastException: graphvisualization.MyVertex cannot be cast to java.lang.Comparable at java.util.TreeMap.put(TreeMap.java:542) Here is the code associated with the error: SortedMap<MyVertex, Double> vMap = new TreeMap

问题 I would like to use HashMaps<String, V> where the value type V should be a two dimensional int array ( int[][] ). Map<String,int[][]> map = new HashMap<>(); int[][] a = new int[][]{ {1, 2} }; map.put("test", a); System.out.println("Test:" + map.containsKey("test")); // Test: true System.out.println("key ==== " + map.get("test")); // Key === [[I@19a8942 I am trying to have a key that access a unique value i.e. a 2-dimensional array, the size of the array is fixed array[1][3] , this is constant

问题 I'm working with these two groups of key value pairs, which is being returned by another function. I'd like to write a function that will always find the highest key and return its corresponding value. In this example, I'd be returning 2 because 499 is the highest key. The data that I am working with is ({-99 0, 99 0} {-99 2, 499 2}) When I call (type ({-99 0, 99 0} {-99 2, 499 2})) Within the function that is responsible for returning that data it, I get back (clojure.lang.PersistentTreeMap

问题 I have an val it:Iterator[(A,B)] and I want to create a SortedMap[A,B] with the elements I get out of the Iterator . The way I do it now is: val map = SortedMap[A,B]() ++ it It works fine but feels a little bit awkward to use. I checked the SortedMap doc but couldn't find anything more elegant. Is there something like: it.toSortedMap or SortedMap.from(it) in the standard Scala library that maybe I've missed? Edit : mixing both ideas from @Rex's answer I came up with this: SortedMap(it.to:_*)