social-networking

I've a problem. I'm making a game with LibGDX. Now I want to implement Google Sign-In. I searched everywhere, but can't find anything. What I need is a Resolver to abstract code for specific platform, but I don't know how to do it. Can someone help? EDIT Here's the code, this is my Android Resolver: public GoogleResolverAndroid(final Context context) { handler = new Handler(); this.context = context; GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN) .requestEmail() .build(); mGoogleApiClient = new GoogleApiClient.Builder(this.context) .addApi(Auth

I cannot figure a way get friends only with profile photos. I could use multi-query to check whether every friend has a photo, but that would incur heavy traffic. Are there any alternatives? Although Gajus’ suggested query might work right now, it’ll break once Facebook changes the URL of the default picture on their CDN. (Might happen, might not happen.) So I’d suggest this for improvement: The profile_pic table has a field called is_silhouette , which is a boolean for whether the user has their own profile picture set or not. So to get only those of your friends, that have a profile picture

I am working on app that contains facebook login .After login with face book I need to go to native application & app should display user name & image that was there in face book .But when I am logining with facebook It is showing "SECURITY WARNING:"Please treat the URL above as you would your password and do not share it with anyone. in ios" ,& not coming back to my native app .Can any one sort this issue.I am using Facebook Graph api for face book. In AppDelegate: -(BOOL)application:(UIApplication *)application handleOpenURL:(NSURL *)url{ return [[_viewController facebook] handleOpenURL:url]

I need view (drawn or plot) the communities structure in networks I have this: import igraph from random import randint def _plot(g, membership=None): layout = g.layout("kk") visual_style = {} visual_style["edge_color"] = "gray" visual_style["vertex_size"] = 30 visual_style["layout"] = layout visual_style["bbox"] = (1024, 768) visual_style["margin"] = 40 for vertex in g.vs(): vertex["label"] = vertex.index if membership is not None: colors = [] for i in range(0, max(membership)+1): colors.append('%06X' % randint(0, 0xFFFFFF)) for vertex in g.vs(): vertex["color"] = str('#') + colors[membership

I am using these below lines of code for G+ sign-in android integration. In app build.gradle : compile 'com.google.android.gms:play-services-auth:8.4.0' compile 'com.google.android.gms:play-services-plus:8.4.0' In MainActivity : GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN) .requestEmail() .requestIdToken("xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx.com") .requestProfile() .build(); AppCompatActivity appCompatActivity = (AppCompatActivity) context; googleApiClient = new GoogleApiClient.Builder(context) .enableAutoManage(appCompatActivity, this)

I tried to use networkx in python to turn an adjacent matrix into a graph. My "weighted" graph has about 8000 nodes and 14000 edges. Is there a great layout form or other packages, tools to make my graph become more beautiful? I hope the outcome is that the edge weight higher the nodes become closer. So that I could analyze the cluster nodes. I had tried all the layout provided in networkx document. I also tried to use gephi and it still a little bit not satisfied with my ideal. This is how it look in networkx. It can show out all the cluster but it looks a little bit terrible for someone who

I have this problem. Given a users table that consists of users' username in a social network and friends table that contain a user's name and a user's friendname like below... username friendname John Thomas Chris James ... I'm trying to write an SQL statement that will if a user is in my network. In other words is that user a friend or friend of friends? I've been dancing around this problem and could only come up with this query: SELECT f2.username, f2.friendname FROM friends f2 WHERE f2.username IN ( SELECT f1.friendname FROM friends f1 WHERE f1.username = 'Thomas') AND f2.friendname <>