smtplib

Here's my script: #!/usr/bin/python import smtplib msg = 'Hello world.' server = smtplib.SMTP('smtp.gmail.com',587) #port 465 or 587 server.ehlo() server.starttls() server.ehlo() server.login('myname@gmail.com','mypass') server.sendmail('myname@gmail.com','somename@somewhere.com',msg) server.close() I'm just trying to send an email from my gmail account. The script uses starttls because of gmail's requirement. I've tried this on two web hosts, 1and1 and webfaction. 1and1 gives me a 'connection refused' error and webfaction reports no error but just doesn't send the email. I can't see anything

I am trying to edit a text file then send it as email body using a python script but im getting the unicode encoding error. After some research i found the solution as using the method .encode('utf-8') but this doesn't serve me as the sendmail() method only sends strings Here is the python code snippet Im using: irtem = open('irtemplate.txt') data = irtem.read().replace('(name)', eng_name).replace('(customer)', cu_name).replace('(sr)', SR_num).replace('(problem)', prob_description).replace('(email)', eng_email).replace('(details)', details_req).replace('(tele)', eng_tele) message_text = data

I am trying to use the hotmail smtp server from python. However, my login attempt gives rise to an apparent SSL3 version number error. How can I change the version I am using and how do I even investigate this? >> s.connect('smtp.live.com:587') (220, 'BLU0-SMTP46.phx.gbl Microsoft ESMTP MAIL Service, Version: 6.0.3790.4675 ready at Tue, 2 Jul 2013 12:15:57 -0700') >> s.ehlo() (250, 'BLU0-SMTP46.phx.gbl Hello [123.456.789.01]\nTURN\nSIZE 41943040\nETRN\nPIPELINING\nDSN\nENHANCEDSTATUSCODES\n8bitmime\nBINARYMIME\nCHUNKING\nVRFY\nTLS\nSTARTTLS\nOK') s.starttls() (220, '2.0.0 SMTP server ready') >

I have written a script that writes a message to a text file and also sends it as an email. Everything goes well, except the email finally appears to be all in one line. I add line breaks by \n and it works for the text file but not for the email. Do you know what could be the possible reason? Here's my code: import smtplib, sys import traceback def send_error(sender, recipient, headers, body): SMTP_SERVER = 'smtp.gmail.com' SMTP_PORT = 587 session = smtplib.SMTP('smtp.gmail.com', 587) session.ehlo() session.starttls() session.ehlo session.login(sender, 'my password') send_it = session

I'm wondering if I can send out a matplotlib pyplot through smtplib. What I mean is, after I plot this dataframe: In [3]: dfa Out[3]: day imps clicks 70 2013-09-09 90739468 74609 69 2013-09-08 90945581 72529 68 2013-09-07 91861855 70869 In [6]: dfa.plot() Out[6]: <matplotlib.axes.AxesSubplot at 0x3f24da0> I know I can see the plot using plt.show() but where is the object itself stored? Or am I misunderstanding something about matplotlib? Is there a way to convert it to a picture or html within python so I can send it through smtplib? Thanks! thegrinner You can use figure.savefig() to save your

I am writing a program that sends an email using Python. What I have learned from various forums is the following piece of code: #!/usr/bin/env python import smtplib sender = "sachinites@gmail.com" receivers = ["abhisheks@cse.iitb.ac.in"] yourname = "Abhishek Sagar" recvname = "receptionist" sub = "Testing email" body = "who cares" message = "From: " + yourname + "\n" message = message + "To: " + recvname + "\n" message = message + "Subject: " + sub + "\n" message = message + body try: print "Sending email to " + recvname + "...", server = smtplib.SMTP('smtp.gmail.com:587') username = 'XYZ

I'm writing a simple smtp-sender with authentification. Here's my code SMTPserver, sender, destination = 'smtp.googlemail.com', 'user@gmail.com', ['reciever@gmail.com'] USERNAME, PASSWORD = "user", "password" # typical values for text_subtype are plain, html, xml text_subtype = 'plain' content=""" Hello, world! """ subject="Message Subject" from smtplib import SMTP_SSL as SMTP # this invokes the secure SMTP protocol (port 465, uses SSL) # from smtplib import SMTP # use this for standard SMTP protocol (port 25, no encryption) from email.MIMEText import MIMEText try: msg = MIMEText(content, text