smt

Efficiency of constraint strengthening in SMT solvers

陌路散爱 提交于 2019-11-30 22:08:49
One way to solve optimisation problems is to use an SMT solver to ask whether a (bad) solution exists, then to progressively add tighter cost constraints until the proposition is no longer satisfiable. This approach is discussed in, for example, http://www.lsi.upc.edu/~oliveras/espai/papers/sat06.pdf and http://isi.uni-bremen.de/agra/doc/konf/08_isvlsi_optprob.pdf . Is this approach efficient , though? i.e. will the solver re-use information from previous solutions when attempting to solve with additional constraints? Leonardo de Moura The solver can reuse lemmas learned when trying to solve

smt工艺制作流程图详解

折月煮酒 提交于 2019-11-30 19:28:30
SMT(Surface Mounted Technology)是一项综合的系统工程技术,其涉及范围包括基板、设计、设备、元器件、组装工艺、生产辅料和管理等。随着SMT技术的产生、发展,SMT在90年代得到迅速普及,并成为电子装联技术的主流。其密度化,高速化,标准化等特点在电路组装技术领域占了绝对的优势。对于推动当代信息产业的发展起了重要的作用,并成为制造现代电子产品必不可少的技术之一。   有两类最基本的工艺流程,一类为锡膏回流焊工艺,另一类是贴片—波峰焊工艺。在实际生产中,应根据所用元器件和生产装备的类型以及产品的需求选择不同的工艺流程   SMT流程介绍:由于SMA有单面安装和双面安装,元器件有全部表面安装及表面安装与通孔插装的混合安装;焊接方式可以是再流焊、波峰焊、或两种方法混合使用,目前采用的方式有几十种之多,下面仅介绍通常采用的几种形式。   锡膏—回流焊工艺,该工艺流程的特点是简单,快捷,有利于产品体积的减小。焊锡膏的印刷是SMT中第一道工序,焊锡膏的印刷涉及到三项基本内容——焊锡膏,模板和印刷机,三者之间合理组合,对膏质量地实现焊锡膏的定量分配是非常重要的,焊锡膏前面已说过,现主要说明的是模块及印刷机。   表面安装组件的类型:   1.全表面安装(Ⅰ型):    1)单面组装 :来料检测 --》 丝印焊膏(点贴片胶)--》 贴片 --》 烘干(固化) --》

Use Z3 and SMT-LIB to get a maximum of two values

余生长醉 提交于 2019-11-30 18:23:32
问题 How do I get the maximum of a formula using smt-lib2? I want something like this: (declare-fun x () Int) (declare-fun y () Int) (declare-fun z () Int) (assert (= x 2)) (assert (= y 4)) (assert (= z (max x y)) (check-sat) (get-model) (exit) Of course, 'max' is unknown to smtlibv2. So, how can this be done? 回答1: In Z3, you can easily define a macro max and use it for getting maximum of two values: (define-fun max ((x Int) (y Int)) Int (ite (< x y) y x)) There is another trick to model max using

Interpretation of Z3 Statistics

时光毁灭记忆、已成空白 提交于 2019-11-30 14:25:47
I obtained several statistics from runs of Z3. I need to understand what these mean. I am rather rusty and non up to date for the recent developments of sat and SMT solving, for this reason I tried to find explanations myself and I might be dead wrong. So my questions are mainly: 1) What do the measures' names mean? 2) If wrong, can you give me pointers to understand better to what they refer to? Other observations are made below and conceptually belong to the two questions above. Thanks in advance! My interpretation follows. DPLL . All the metrics below refer to the jargon of the DPLL

SMT自动贴标机业务梳理

为君一笑 提交于 2019-11-30 05:27:57
1-业务背景   -SMT自动贴标机旁边配备一台条码打印机,SMT自动贴标机根据Mes条码规则,自动生成标贴并打印标贴,自动贴标代替人工贴标贴,并完成母子条码Link绑定;   -由于SMT自动贴标机自动生成标贴并打印,问题较多,出于生产效率考虑,放弃这一步; 2-现有业务逻辑   -标贴房根据Mes条码规则,预先打印好工单所有条码;   -然后拉长拿一卷卷条码去SMT自动贴标机安装;   -SMT自动贴标机,完成自动贴标,并调用Mes的Service接口将一组组条码完成条码自动Link绑定; 来源: https://www.cnblogs.com/turnip/p/11561775.html

How incremental solving works in Z3?

给你一囗甜甜゛ 提交于 2019-11-30 02:39:47
I have a question regarding how Z3 incrementally solves problems. After reading through some answers here, I found the following: There are two ways to use Z3 for incremental solving: one is push/pop(stack) mode, the other is using assumptions. Soft/Hard constraints in Z3 . In stack mode, z3 will forget all learned lemmas in global ( am I right? ) scope even after one local "pop" Efficiency of constraint strengthening in SMT solvers In assumptions mode (I don't know the name, that is the name that comes to my mind), z3 will not simplify some formulas, e.g. value propagation. z3 behaviour

Defining a Theory of Sets with Z3/SMT-LIB2

…衆ロ難τιáo~ 提交于 2019-11-30 02:07:50
问题 I'm trying to define a theory of sets (union, intersection etc.) for Z3 using the SMTLIB interface. Unfortunately, my current definition hangs z3 for a trivial query, so I guess I'm missing some simple option/flags. here's the permalink: http://rise4fun.com/Z3/JomY (declare-sort Set) (declare-fun emp () Set) (declare-fun add (Set Int) Set) (declare-fun cup (Set Set) Set) (declare-fun cap (Set Set) Set) (declare-fun dif (Set Set) Set) (declare-fun sub (Set Set) Bool) (declare-fun mem (Int Set)

y=1/x, x=0 satisfiable in the reals?

自古美人都是妖i 提交于 2019-11-29 15:46:40
In SMT-LIB: (declare-fun y () Real) (declare-fun x () Real) (assert (= 0.0 x)) (assert (= y (/ 1.0 x))) (check-sat) Should this model be SAT or UNSAT? In SMT-LIB 2.0 and 2.5, all functions are total, so this example is SAT in SMT-LIB. Both Z3 and CVC4 do indeed return SAT for the example in the question. I found this counter-intuitive. I think it would be mathematically more well justified to say that y=1/x, x=0 is unsatisfiable in the reals. In Mathematica, the equivalent code returns an empty list, indicating that no solution exists, i.e., FindInstance[Element[x, Reals] && Element[y, Reals]

Z3: Extracting existential model-values

核能气质少年 提交于 2019-11-29 15:42:22
I'm playing around with Z3's QBVF solver, and wondering if it's possible to extract values from an existential assertion. To wit, let's say I have the following: (assert (exists ((x (_ BitVec 16))) (forall ((y (_ BitVec 16))) (bvuge y x)))) This basically says that there is a "least" 16-bit unsigned value. Then, I can say: (check-sat) (get-model) And Z3-3.0 happily responds: sat (model (define-fun x!0 () (_ BitVec 16) #x0000) ) Which is really cool. But what I want to do is to be able to extract pieces of that model via get-value. Unsurprisingly, none of the following seem to work (get-value

Z3 Theorem Prover: Pythagorean Theorem (Non-Linear Artithmetic)

旧巷老猫 提交于 2019-11-29 12:02:02
Wherefore? The usecase context in which my problem occures I define 3 random item of a triangle. Microsoft Z3 should output: Are the constraints satisfiabe or are there invalid input values? A model for all the other triangle items where all the variables are assigned to concrete values. In order to constrain the items i need to assert triangle equalities - i wanted to start out with the Pythagorean Theorem ( (h_c² + p² = b²) ^ (h_c² + q² = a²) ). The Problem I know that Microsoft Z3 has only limited capabilities to solve non-linear arithematic problems. But even some hand calculators are able