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It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center . Closed 6 years ago . How can I show a thumbnail from a fixed image path in an ImageView? you can create Image thumbnail from the image path as: public Bitmap getbitpam(String path){ Bitmap imgthumBitmap=null; try { final int THUMBNAIL_SIZE = 64; FileInputStream fis = new FileInputStream(path); imgthumBitmap = BitmapFactory

Greetings I need to display images stored in BLOB database fields in a LISTVIEW or similar widget from Yii2 I have the actionCreate that saves the image in table named honra as a BLOB public function actionCreate() { $model = new Honra(); if ($model->load(Yii::$app->request->post()) && $model->save()) { $file = UploadedFile::getInstance($model,'binaryfile'); $model->binaryfile=$file; return $this->redirect(['view', 'id' => $model->id]); } else { return $this->render('create', [ 'model' => $model, ]); } } I also have the model named Honra class Honra extends \yii\db\ActiveRecord{ public static

It may be that I am missing something obvious, but I can't work out how to reveal a hidden image/DIV slowly, so that it is shown from top to bottom. If you look at this jsfiddle you will see the image that I am trying to reveal using 'show' in jQuery: http://jsfiddle.net/nickharambee/Lj7z9/13/ The trouble with 'show' is that it grows the image from top left. What I am looking for is an effect that hopefully is clear from these images: i.e. the red 'home' image/DIV is gradually revealed from top to bottom so that it overlays the brown 'home' image. Is it possible to achieve an effect like this

I have the following code: <fieldset> <legend>Do you currently have SolidWorks</legend> <ul> <li><label for=""><input type="radio" name="solidworks" value="Yes" id="rdYes" /> Yes</label></li> <li><label for=""><input type="radio" name="solidworks" value="No" id="rdNo" /> No</label></li> </ul> </fieldset> <fieldset id="boxReseller" style="display:none;"> <legend>Who is your SolidWorks reseller?</legend> <ul> <li><label for=""><input type="radio" name="reseller" value="Cad Connect" /> Cad Connect</label></li> <li><label for=""><input type="radio" name="reseller" value="Cadtek" /> Cadtek</label><

I'm trying to show the #subscribe-pop div once a link is clicked and hide it when clicking anywhere outside it. I can get it to show and hide if I change the: $('document').click(function() { TO $('#SomeOtherRandomDiv').click(function() { HTML: <div id="footleft"> <a href="#" onclick="toggle_visibility('subscribe-pop');">Click here to show div</a> <div id="subscribe-pop"><p>my content</p></div> </div> Script: <script type="text/javascript"> function toggle_visibility(id) { var e = document.getElementById("subscribe-pop"); if(e.style.display == 'block') e.style.display = 'none'; else e.style

I have found a great tutorial on how to show and hide a certain div on a page. I got the code working fine, but I would like to extend is to that the show/hide is remembered on page loads. I've looked for a solution jQuery cookie was the answer.. if I'd knew how to write the actual code that is.. Here's the current snippet: <script type="text/javascript"> jQuery(document).ready(function() { // hides the group_desciption as soon as the DOM is ready // (a little sooner than page load) jQuery('#group_desciption').hide(); // shows the group_desciption on clicking the noted link jQuery('a#slick

I want to override the default integer constructors in Haskell so they produce strings (mostly for curiosity, but temporarily to make a nice input alternative for LaTeX's \frac{}{} inconvenience). I wanted to be able to use the language itself, instead of a special parser, but I guess that's probably not going to work out... module Main where import Prelude hiding ((+)) newtype A = A Int deriving (Eq, Show, Num) default (A) (+) :: A -> (A -> String) (A a) + (A b) = (show a) ++ " + " ++ (show b) main2 = 3+4 main :: IO () main = putStrLn main2 The problem with the above is that the + function