short-circuiting

In the code below: #include <stdio.h> int main() { int a = 1; int b = 1; int c = a || --b; int d = a-- && --b; printf("a = %d, b = %d, c = %d, d = %d", a, b, c, d); return 0; } i was expecting the output to be: a=0,b=1,c=1,d=0 because due to short circuiting in the line below, ie a-- returns 0 so the other part wont get executed right? int d = a-- && --b; The output is: a = 0, b = 0, c = 1, d = 0 can anyone please explain? int c = a || --b; In this line, the C standard requires the C implementation to evaluate a first and, if it is not zero, not to evaluate --b . Although -- has higher

I have a function handle that operates on 2d arrays of arbitrary size: R2T = @(DL1,DL2) arrayfun(@(DL1,DL2)... 1/(fzero(@(x)fFitObj1(x)./fFitObj2(x)-... DL1./DL2,[minLim maxLim])) ... ,DL1,DL2) - C1; Here's a bottom-up breakdown of what it does: fzero(@(x)fFitObj1(x)./fFitObj2(x)-DL1./DL2,[minLim maxLim]) - This bit looks for a zero of the considered function on the interval [minLim maxLim] , where fFitObj1 and fFitObj2 are function handles available from before, C1 is some known constant and DL1, DL2 are provided. @(DL1,DL2)1/(fzero(...)) - a wrapper for fzero that allows DL1 and DL2 to be

Do we have any operator in C# by which I can avoid short circuit evaluation and traverse to all the conditions. say if(txtName.Text.xyz() || txtLastName.Text.xyz()) { } public static bool xyz(this TextBox txt) { //do some work. return false; } It should evaluate all conditions irrespective of output obtained. And after evaluating last condition continues according to result obtained. ? Just use a single bar, this will evaluated both arguments regardless of the outcome of the first result. if(txtName.Text.xyz() | txtLastName.Text.xyz()) { } You can also do the same with AND, i.e. You can

I've found in the documentation of case statment that it uses short-circuit: Oracle Database uses short-circuit evaluation. That is, for a simple CASE expression, the database evaluates each comparison_expr value only before comparing it to expr, rather than evaluating all comparison_expr values before comparing any of them with expr. Consequently, Oracle never evaluates a comparison_expr if a previous comparison_expr is equal to expr. For a searched CASE expression, the database evaluates each condition to determine whether it is true, and never evaluates a condition if the previous condition

In other words, do the following two statements behave the same way? isFoobared = isFoobared && methodWithSideEffects(); isFoobared &= methodWithSideEffects(); I realize I could just write up a test, but someone might know this offhand, and others might find the answer useful. polygenelubricants No, |= and &= do not shortcircuit, because they are the compound assignment version of & and | , which do not shortcircuit. JLS 15.26.2 Compound Assignment Operators A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)) , where T is the type of E1 , except that

Quick question here about short-circuiting statements in C#. With an if statement like this: if (MyObject.MyArray.Count == 0 || MyObject.MyArray[0].SomeValue == 0) { //.... } Is it guaranteed that evaluation will stop after the "MyArray.Count" portion, provided that portion is true? Otherwise I'll get a null exception in the second part. Yes, this is guaranteed. C# Language Specification - 7.11 Conditional logical operators : The && and || operators are called the conditional logical operators. They are also called the "short-circuiting" logical operators. Therefore they will support logical

In Python we can do this: if True or blah: print("it's ok") # will be executed if blah or True: # will raise a NameError print("it's not ok") class Blah: pass blah = Blah() if blah or blah.notexist: print("it's ok") # also will be executed Can somebody point me to documentation on this feature? Is it an implementation detail or feature of the language? Is it good coding style to exploit this feature? The or and and short circuit , see the Boolean operations documentation: The expression x and y first evaluates x ; if x is false, its value is returned; otherwise, y is evaluated and the