sha1

修改sshd的配置文件 /etc/ssh/sshd_config 在配置文件中添加： Ciphers aes128-cbc,aes192-cbc,aes256-cbc,aes128-ctr,aes192-ctr,aes256-ctr,3des-cbc,arcfour128,arcfour256,arcfour,blowfish-cbc,cast128-cbc MACs hmac-md5,hmac-sha1,umac-64@openssh.com,hmac-ripemd160,hmac-sha1-96,hmac-md5-96 KexAlgorithms diffie-hellman-group1-sha1,diffie-hellman-group14-sha1,diffie-hellman-group-exchange-sha1,diffie-hellman-group-exchange-sha256,ecdh-sha2-nistp256,ecdh-sha2-nistp384,ecdh-sha2-nistp521,diffie-hellman-group1-sha1,curve25519-sha256@libssh.org 重启sshd服务后，即可正常连接。 导致此问题的原因是ssh升级后，为了安全，默认不再采用原来一些加密算法，我们手工添加进去即可。 来源： oschina 链接：

I want to get hash of a binary file whose name I have. I have tried the following, but then realized that SHA1() is returning hash value for the string ( name of the file). But I want to run it on the file itself. Any pointers on how to do that would be great. char *fileName = "/bin/ls" unsigned char hash[SHA_DIGEST_LENGTH]; SHA1((unsigned char *)fileName, strlen(fileName),hash); Thanks to everyone's comments I solved the problem. I am posting the code here, so others might find it beneficial. void getFileHash(char *fileName){ unsigned char result[2*SHA_DIGEST_LENGTH]; unsigned char hash[SHA

I have a database where every password is passed via SHA1. Sometimes, I want to go to the users dashboard and look how it feels like. Is there a way, I could convert SHA1 to normal form just for testing purposes? Thank You If by "normal form" you mean "can I retrieve the string that created a given hash", the answer is no. And it should be NO, because that's the whole point of secure hashes: make it very easy to create, extremely complicated (ideally impossible) to revert, otherwise, why on Earth would you make a secure hash? If you are trying to hack on the user's accounts, then I suggest you

/* * 哈希算法MD5和SHA1的C#实现 * * * 夏春涛 Email:xChuntao@163.com * Blog:http://bluesky521.cnblogs.com * 运行环境：.net2.0 framework */ /* * 关于哈希函数： * 哈希函数将任意长度的二进制字符串映射为固定长度的小型二进制字符串。 * 加密哈希函数有这样一个属性：在计算上不大可能找到散列为相同的值的两个 * 不同的输入；也就是说，两组数据的哈希值仅在对应的数据也匹配时才会匹配。 * 数据的少量更改会在哈希值中产生不可预知的大量更改。 * * MD5 算法的哈希值大小为 128 位。 * SHA1 算法的哈希值大小为 160 位。 */ using System; using System.Collections.Generic; using System.Text; using System.Security.Cryptography; namespace MD5_App { class Program { static void Main(string[] args) { string strSrc = "How are you?"; Console.WriteLine("原文：" + strSrc); Console.WriteLine(); Console

using System; using System.IO; using System.Text; using System.Windows.Forms; using System.Security.Cryptography; using System.Web; using System.Text.RegularExpressions; namespace Crypto { public partial class Form1 : Form { public Form1() { InitializeComponent(); } private void button7_Click(object sender, EventArgs e)//md5选择文件 { OpenFileDialog openFile1 = new OpenFileDialog(); openFile1.RestoreDirectory = true; if (openFile1.ShowDialog() == DialogResult.OK) { textBox3.Text = openFile1.FileName.ToString(); } } private void button10_Click(object sender, EventArgs e)//sha1选择文件 { OpenFileDialog

I'm confused as to why the following return separate sHA1s $ perl -MDigest::SHA1 -E'say Digest::SHA1::sha1_hex("http://i.aultec.com/v/8066/Originals/1FTVX12585NA9832010.jpg");' e1133fa3b7ea0bfb8ffa4d877932ed6c6fa10cef $ echo "http://i.aultec.com/v/8066/Originals/1FTVX12585NA9832010.jpg" | sha1sum 5c3731e83ae0184ed93b595b9f5604863dd331e6 - Which one is right? Am /I/ doing it wrong? $ perl -MDigest::SHA -E'say Digest::SHA::sha1_hex("http://i.aultec.com/v/8066/Originals/1FTVX12585NA9832010.jpg");' e1133fa3b7ea0bfb8ffa4d877932ed6c6fa10cef You can see the digest is right in the successor ( Digest:

点开是一段PHP的代码，先来审计一波代码。 发现将uname和passwd用sha1进行了加密，那么我们只要绕过这个函数构造相等就可以了。 可以使这两个值sha1的值相等，但他们本身的值又不等。（想详细了解sha1函数绕过的可以看我的这篇博客） 构造 http://120.24.86.145:8002/web7/?uname[]=1&id=margin 并用发送passwd[]=2的请求即可。 便可成功得到flag 来源： https://www.cnblogs.com/lzlzzzzzz/p/11692811.html