sftp

问题 I got following error when using decodebyes. UnicodeDecodeError: 'utf-8' codec can't decode byte 0x9d in position 0: invalid start byte import pysftp import paramiko from paramiko.py3compat import decodebytes keydata = b"""4049a539f13cba06a874c4b6aadd0cc4""" key = paramiko.RSAKey(data=decodebytes(keydata)) cnopts = pysftp.CnOpts() cnopts.hostkeys.add('xxx.www.it', 'ssh-rsa', key) with pysftp.Connection('xxx.www.it', username='google', password='xxx', cnopts=cnopts) as sftp: sftp.get('remote

问题 I was experiencing a problem with a logic app which Used the Create SAS URI by path action to get a SAS-enabled URL for a blob in a storage account Used the SFTP copy file action to copy the file to an SFTP connector The process would fail roughly 50% of the time with an authorization error when trying to fetch the blob from storage. "actions": { "Create_SAS_URI_by_path": { "inputs": { "body": { "Permissions": "Read" }, "host": { "connection": { "name": "@parameters('$connections')['azureblob

问题 # create SSHClient instance ssh = paramiko.SSHClient() list = [] # AutoAddPolicy automatically adding the hostname and new host key ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy()) ssh.load_system_host_keys() ssh.connect(hostname, port, username, password) stdin, stdout, stderr = ssh.exec_command("cd *path*; ls") for i in stdout: list.append(i) sftp = ssh.open_sftp() for i in list: tempremote = ("*path*" + i).replace('\n', '') templocal = ("*path*" + i).replace('\n', '') try: #Get

问题 # create SSHClient instance ssh = paramiko.SSHClient() list = [] # AutoAddPolicy automatically adding the hostname and new host key ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy()) ssh.load_system_host_keys() ssh.connect(hostname, port, username, password) stdin, stdout, stderr = ssh.exec_command("cd *path*; ls") for i in stdout: list.append(i) sftp = ssh.open_sftp() for i in list: tempremote = ("*path*" + i).replace('\n', '') templocal = ("*path*" + i).replace('\n', '') try: #Get

问题 In the current stable release of WinSCP, it seems that using SshHostKeyFingerprint is mandatory and there are no ways to connect to SFTP server without that in SessionOptions . I can see that the ability to bypass is added to the beta (5.2) but I was wondering whether or not it's possible to connect without this fingerprint. 回答1: First, make sure you understand that you give-up any security , when you try to bypass SSH host key check. You effectively lose a protection against man-in-the

问题 I'm attempting to sync my local PHPStorm project from my Windows 7 PC with my Ubuntu server. When I try any kind of connection (e.g. "Test SFTP connection"), it fails with Invalid descendent file name "C:\nppdf32Log\debuglog.txt" the folder mentioned doesn't exist on my Windows machine, and of course not on my Ubuntu server. Even the most basic operation connecting to the Ubuntu server is failing because of this - Jetbrains support suggested asking here, so does anyone have a clue? 回答1: You

问题 I have a problem and hoping to get a solution. I also have written some code but it needs some modification. Problem: I have a SFTP server (for privacy purposes I will give dummy credentials) that I need to connect to. Server name: server-name port: 22 username: username password: password When I connect to the server, it automatically drops me in the "/FGV" directory. inside this directory are couple other folders. I need to grab a LIST of xml messages from the "/FGV/US/BS/" directory and

问题 We can write a simple get like this: import pysftp hostname = "somehost" user = "bob" password = "123456" filename = 'somefile.txt' with pysftp.Connection(hostname, username=user, private_key='/home/private_key_file') as sftp: sftp.get(filename) However, I want to specify a pattern in the filename, something like: '*.txt' Any idea on how to do this using pysftp ? 回答1: There's no function to download files matching a file mask in pysftp. You have to: list the directory, using listdir or

问题 I am facing a peculiar issue while trying to SFTP a file from Windows to Unix server. The error "stack trace" is - 4: Failure at com.jcraft.jsch.ChannelSftp.throwStatusError(ChannelSftp.java:2846) at com.jcraft.jsch.ChannelSftp.checkStatus(ChannelSftp.java:2459) at com.jcraft.jsch.ChannelSftp._sendCLOSE(ChannelSftp.java:2465) at com.jcraft.jsch.ChannelSftp._put(ChannelSftp.java:683) at com.jcraft.jsch.ChannelSftp.put(ChannelSftp.java:475) at com.jcraft.jsch.ChannelSftp.put(ChannelSftp.java

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . Why is 22 the default port number for SFTP? Is there any specific reason for this? 回答1: It's the default SSH port and SFTP is usually carried over an SSH tunnel. 回答2: Why is 21 the default port for FTP? Or 80 the default for HTTP? It is a convention. 回答3: From Wikipedia: Applications implementing common services