settings

问题 I want to print a long string to the RStudio console so that it does not get truncated. > paste(1:300, letters, collapse=" ") [1] "1 a 2 b 3 c 4 d 5 e 6 f 7 g 8 h 9 i ... 181 y 182 z 183 a 184 b... <truncated> I supposed this should be fairly simple, but I cannot figure out how. I tried options(max.print = 10000) and looked through the args on the print help pages. Still no luck. What parameter / settings to I have to change to achieve this? 回答1: This is an RStudio-specific feature, intended

问题 I have created a custom Settings.app bundle using the standard root.plist approach for the iPhone. I'm wondering if there's a way to determine when the user changes those settings in my app... 回答1: You can listen for NSUSerDefaultsDidChange-notifications with this: [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(defaultsChanged) name:NSUserDefaultsDidChangeNotification object:nil]; Whenever the NSUserDefaults changes, defaultsChanged will be called. Don't forget to

问题 I have created a custom Settings.app bundle using the standard root.plist approach for the iPhone. I'm wondering if there's a way to determine when the user changes those settings in my app... 回答1: You can listen for NSUSerDefaultsDidChange-notifications with this: [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(defaultsChanged) name:NSUserDefaultsDidChangeNotification object:nil]; Whenever the NSUserDefaults changes, defaultsChanged will be called. Don't forget to

问题 I know an app can launch other apps by using this code: [[UIApplication sharedApplication] openURL:appUrl]; . And I know the scheme of URL to open safari and mail, but I did some searches and found nothing about the scheme of settings.app. 回答1: You can open settings apps programmatically try this(works only from iOS8 onwards). If you are using Swift: UIApplication.sharedApplication().openURL(NSURL(string: UIApplicationOpenSettingsURLString)) If you are using Objective-C [[UIApplication

问题 I know an app can launch other apps by using this code: [[UIApplication sharedApplication] openURL:appUrl]; . And I know the scheme of URL to open safari and mail, but I did some searches and found nothing about the scheme of settings.app. 回答1: You can open settings apps programmatically try this(works only from iOS8 onwards). If you are using Swift: UIApplication.sharedApplication().openURL(NSURL(string: UIApplicationOpenSettingsURLString)) If you are using Objective-C [[UIApplication

问题 I'm creating a simple windows Forms application using C# express 2008. I'm an experienced C++ developer, but I am pretty much brand new to C# and .NET. I'm currently storing some of my simple application settings using the settings designer and code like this: // Store setting Properties.Settings.Default.TargetLocation = txtLocation.Text; ... // Restore setting txtLocation.Text = Properties.Settings.Default.TargetLocation; Now I'd like to store either an array of ints ( int[] ), or possibly a

问题 I am trying to implement a feature in an App that shows an alert when the internet connection is not available. The alert has two actions (OK and Settings), whenever a user clicks on settings, I want to take them to the phone settings programmatically. I am using Swift and Xcode. 回答1: Using UIApplication.openSettingsURLString Update for Swift 5.1 override func viewDidAppear(_ animated: Bool) { let alertController = UIAlertController (title: "Title", message: "Go to Settings?", preferredStyle:

问题 So I have this port that I'm opening and saving the name of the port in a setting of my application. When I load the form it tries to open the port however fails to do so. Only after clicking on my "open port" button that has the EXACT same code does the port open. And then If I click my "close port" button and reopen the form it works! It automatically opens the port for me. However it's only if I'm fast enough. If I leave the application closed (and thus port closed) for say 10-15 seconds

问题 As per my requirement I have to clear default browser cache from my application. I want to open browser settings from my application, so that user can clear the cache. By using following code. startActivityForResult(new Intent(android.provider.Settings.ACTION_MANAGE_ALL_APPLICATIONS_SETTINGS), 0); I'm able to open all manage applications. Is there any way to open browser settings directly? Thanks 回答1: Settings of an application is stored in Shared Preferances of the application and each

问题 I have a very big handsontable. I have dropdown columns defined, but, the values for the sources are retrieved with AJAX. How can I set the "source" property of a "column" of type "dropdown" dynamically? Regards! 回答1: You can, and should, use: hotInstance.updateSettings({ columns: getNewColumns() }) Where getNewColumns() would return an array of columns with the data and new source (or make the AJAX call from in here). That should do it! 回答2: Thank you for the answer ZekeDroid. I was able to