serialization

ClassCastException: cannot assign instance of scala.collection.immutable.List$SerializationProxy in instance of org.apache.spark.rdd.MapPartitionsRDD

走远了吗. 提交于 2020-01-06 04:33:08
问题 I have a spring boot microservice talking to a remote spark cluster with 3 nodes, and executing the following logic: Dataset<Row> df = sparkSession.read().json("/opt/enso/test.json"); StructType schema = df.schema(); JavaPairRDD<Row, Long> zippedRows = df.toJavaRDD().zipWithIndex(); JavaPairRDD<Row, Long> filteredRows = zippedRows.filter(new Function<Tuple2<Row,Long>,Boolean> () { @Override public Boolean call(Tuple2<Row,Long> v1) throws Exception { return v1._2 >= 1 && v1._2 <= 5; } });

Android Context not serializable dilemma for class that implements Iteratable

為{幸葍}努か 提交于 2020-01-06 04:27:28
问题 Here is my situation. I have written a Playlist class that stores a context. Playlist has 9 child classes. Unfortunately, to pass Playlist between intents, it must implement Serializable. This is a problem because Playlist stores a context, so that the Iterator can work, as the Iterator method that must be Overridden from Iterator can not accept any parameters. Therefore, I must store Context somewhere as it is needed to determine the size of the Playlist. Here is the (simplified) code.

NSKeyedArchiver/NSKeyedUnarchiver compatibility on different iOS versions

点点圈 提交于 2020-01-06 04:12:10
问题 In an iOS app, we are using serialization of complex objects through NSKeyedArchiver/NSKeyedUnarchiver to store info and data. So the app will include such a serialized object in the app bundle, and this file will be created under one specific iOS version (let's say iOS 5.0) As the app will be running on different iOS versions (> 5.0) and even in future versions to come, we want to be sure that the original serialized object included in the app bundle will be perfectly readable on every other

How to read and write a xml file into the same location?

断了今生、忘了曾经 提交于 2020-01-06 03:18:21
问题 I have prepared xml files with some content and want to load it while playing on iOS device but also I want to change loaded data and serialize it in the same file again. In Unity Editor (Windows) it works perfectly, but when I test it on iOS device it seems that I can read from StreamingAssets using WWW class, but I can't write into it. Also I have found that I can read and write into path created by Application.persistentDataPath. But it seems that location somewhere in device and I can't

Deserialize a nested struct with MongoDB C# driver

天大地大妈咪最大 提交于 2020-01-06 02:34:56
问题 I serialize this Kontejner class without problems. public struct Dimenzije { public double duzina, sirina, visina; public Dimenzije(double d, double s, double v) { duzina = d; sirina = s; visina = v; } } public class Kontejner { [BsonId] public string Id { get; set; } public string Opis { get; set; } public Dimenzije Dimenzije { get; set; } [BsonElement] public double Zapremina { get { return Dimenzije.duzina * Dimenzije.sirina * Dimenzije.visina; } } public bool Cvrsti { get; set; } public

Serialization with CodeDomSerializer - How to Initialize Manager Object?

笑着哭i 提交于 2020-01-06 02:29:09
问题 There are numerous examples on the web that show how to use the CodeDomSerializer. Most of them show how to override the Serialize and Deserialize methods of that class. The problem is that this Serialize method takes a manager argument of type IDesignerSerializationManager. I cannot figure out how to create an instance of that type... Here's what I tried: var root = new Form(); root.Controls.Add(new TextBox() { Text = "hello" }); Type rootSerializerType = Type.GetType("System.ComponentModel

Why is my JSON Response not being Deserialized on my Client into the same Generic List Type as the Origin IEnumerable Type on the Web API server?

孤人 提交于 2020-01-06 01:30:08
问题 If I understand Ufuk Hacıoğulları here I can simplify this code: using (var webResponse = (HttpWebResponse)webRequest.GetResponse()) { if (webResponse.StatusCode == HttpStatusCode.OK) { var reader = new StreamReader(webResponse.GetResponseStream()); string s = reader.ReadToEnd(); var arr = JsonConvert.DeserializeObject<JArray>(s); if (arr.Count <= 0) break; foreach (JObject obj in arr) { id = obj.Value<int?>("Id") ?? 0; var _deptId = obj.Value<int?>("deptId") ?? 0; var _subdeptId = obj.Value

Why is my JSON Response not being Deserialized on my Client into the same Generic List Type as the Origin IEnumerable Type on the Web API server?

一曲冷凌霜 提交于 2020-01-06 01:30:06
问题 If I understand Ufuk Hacıoğulları here I can simplify this code: using (var webResponse = (HttpWebResponse)webRequest.GetResponse()) { if (webResponse.StatusCode == HttpStatusCode.OK) { var reader = new StreamReader(webResponse.GetResponseStream()); string s = reader.ReadToEnd(); var arr = JsonConvert.DeserializeObject<JArray>(s); if (arr.Count <= 0) break; foreach (JObject obj in arr) { id = obj.Value<int?>("Id") ?? 0; var _deptId = obj.Value<int?>("deptId") ?? 0; var _subdeptId = obj.Value

jQuery to PHP - serialized strings

喜夏-厌秋 提交于 2020-01-05 17:48:11
问题 I'm currently AJAX'ing a login form. var data = $(this).serialize(); This is the data I'm sending, I get this with PHP using Codeigniter like so: $ajax = $this->input->post('data'); This returns username=john&password=doe as you'd expect. How do I turn that into an array? I've tried doing unserialize() and I get null. 回答1: I believe you can use PHP's parse_str() function: http://php.net/manual/en/function.parse-str.php <?php $str = "first=value&arr[]=foo+bar&arr[]=baz"; parse_str($str); echo

GSON de/serialization of wrapper class

守給你的承諾、 提交于 2020-01-05 15:16:03
问题 I have a convenience class wrapper for a Map, that looks something like this: class MapWrapper { private Map<String, Integer> wrapped = new HashMap<>(); public void add(String key, Integer count) {/*implementation*/} // Other modifiers } The reason that I'm not using a Map directly but rather the wrapper is because I need to use the methods to access the Map indirectly. When I de/serialize this object, I would like the JSON to serialize as if the wrapper class wasn't there. E.G. I want: {