select

Split a dataframe into multilple dataframes by colums selection

由 心不动则不痛 提交于 2020-12-08 03:28:12
问题 These are my data frames: # data set.seed(1234321) # Original data frame (i.e. a questionnaire survey data) answer <- c("Yes", "No") likert_scale <- c("strongly disagree", "disagree", "undecided", "agree", "strongly agree") d1 <- c(rnorm(10)*10) d2 <- sample(x = c(letters), size = 10, replace = TRUE) d3 <- sample(x = likert_scale, size = 10, replace = TRUE) d4 <- sample(x = likert_scale, size = 10, replace = TRUE) d5 <- sample(x = likert_scale, size = 10, replace = TRUE) d6 <- sample(x =

Split a dataframe into multilple dataframes by colums selection

由 独自空忆成欢 提交于 2020-12-08 03:27:16
问题 These are my data frames: # data set.seed(1234321) # Original data frame (i.e. a questionnaire survey data) answer <- c("Yes", "No") likert_scale <- c("strongly disagree", "disagree", "undecided", "agree", "strongly agree") d1 <- c(rnorm(10)*10) d2 <- sample(x = c(letters), size = 10, replace = TRUE) d3 <- sample(x = likert_scale, size = 10, replace = TRUE) d4 <- sample(x = likert_scale, size = 10, replace = TRUE) d5 <- sample(x = likert_scale, size = 10, replace = TRUE) d6 <- sample(x =

Split a dataframe into multilple dataframes by colums selection

由 ≯℡__Kan透↙ 提交于 2020-12-08 03:26:20
问题 These are my data frames: # data set.seed(1234321) # Original data frame (i.e. a questionnaire survey data) answer <- c("Yes", "No") likert_scale <- c("strongly disagree", "disagree", "undecided", "agree", "strongly agree") d1 <- c(rnorm(10)*10) d2 <- sample(x = c(letters), size = 10, replace = TRUE) d3 <- sample(x = likert_scale, size = 10, replace = TRUE) d4 <- sample(x = likert_scale, size = 10, replace = TRUE) d5 <- sample(x = likert_scale, size = 10, replace = TRUE) d6 <- sample(x =

How to store sum(field_name) in a variable within MySql Select statement?

由 喜你入骨 提交于 2020-12-06 13:15:25
问题 I am trying to store the sum total of a particular field in a variable like @data := sum(field_name) within MySQL Select statement. Below is an exact example of my query: SELECT a.id, @data1:=sum(b.amount) amount, @data1 as returned_val FROM tbl_table1 a LEFT JOIN tbl_table2 b ON b.acount_id=a.id GROUP BY a.id Notice that I store the sum(b.amount) to a variable @data1 and tried to display it in another row but never work as what I'm expecting. Is there any other way doing this? 来源： https:/

Give placeholder to select in Angular 6

由 99封情书 提交于 2020-12-04 19:03:40
问题 I have a select option in which i want to give placeholder which says "select a category" <form role="form" class="form form-horizontal" (ngSubmit)="onSubmit()" #form="ngForm" ngNativeValidate> <div class="form-group row"> <div class="col-xl-4 col-lg-6 col-md-12"> <fieldset class="form-group"> <label for="customSelect">Categories:</label> <select class="custom-select d-block w-100" id="Category" [(ngModel)]="Category" name="Category" required> <option value=" ">Select one category </option>

Give placeholder to select in Angular 6

由 我的未来我决定 提交于 2020-12-04 19:00:17
问题 I have a select option in which i want to give placeholder which says "select a category" <form role="form" class="form form-horizontal" (ngSubmit)="onSubmit()" #form="ngForm" ngNativeValidate> <div class="form-group row"> <div class="col-xl-4 col-lg-6 col-md-12"> <fieldset class="form-group"> <label for="customSelect">Categories:</label> <select class="custom-select d-block w-100" id="Category" [(ngModel)]="Category" name="Category" required> <option value=" ">Select one category </option>

Give placeholder to select in Angular 6

由 自古美人都是妖i 提交于 2020-12-04 18:59:20
问题 I have a select option in which i want to give placeholder which says "select a category" <form role="form" class="form form-horizontal" (ngSubmit)="onSubmit()" #form="ngForm" ngNativeValidate> <div class="form-group row"> <div class="col-xl-4 col-lg-6 col-md-12"> <fieldset class="form-group"> <label for="customSelect">Categories:</label> <select class="custom-select d-block w-100" id="Category" [(ngModel)]="Category" name="Category" required> <option value=" ">Select one category </option>

Give placeholder to select in Angular 6

由 匆匆过客 提交于 2020-12-04 18:57:26
问题 I have a select option in which i want to give placeholder which says "select a category" <form role="form" class="form form-horizontal" (ngSubmit)="onSubmit()" #form="ngForm" ngNativeValidate> <div class="form-group row"> <div class="col-xl-4 col-lg-6 col-md-12"> <fieldset class="form-group"> <label for="customSelect">Categories:</label> <select class="custom-select d-block w-100" id="Category" [(ngModel)]="Category" name="Category" required> <option value=" ">Select one category </option>

SQL SELECT WHERE string ends with Column

由 流过昼夜 提交于 2020-12-04 15:33:02
问题 I have this table in SQL Server 2012: Id INT DomainName NVARCHAR(150) And the table have these DomainName values google.com microsoft.com othersite.com And this value: mail.othersite.com and I need to select the rows where the string ends with the column value, for this value I need to get the row no.3 othersite.com It's something like this: DomainName Like '%value' but in reverse ... 'value' Like %DomainName 回答1: You can use such query: SELECT * FROM TABLE1 WHERE 'value' LIKE '%' +

Mysql查询结果作为另一张表的更新内容

由 人走茶凉 提交于 2020-11-23 22:48:52
1、将查询结果中有用的数据用分隔符获取，更新到另一张表。 DELIMITER $$ DROP FUNCTION IF EXISTS `func_splitString` $$ CREATE FUNCTION `func_splitString` ( f_string VARCHAR(1000),f_delimiter VARCHAR(5),f_order INT) RETURNS VARCHAR(255) CHARSET utf8 BEGIN DECLARE result VARCHAR(255) DEFAULT ''; SET result = REVERSE(SUBSTRING_INDEX(REVERSE(SUBSTRING_INDEX(f_string,f_delimiter,f_order)),f_delimiter,1)); RETURN result; END$$ //更新表字段3min_document：cover_id int //查询表字段3min_document_video:video string (内容类似：xxxxxxx|12) UPDATE 3min_document d INNER JOIN 3min_document_video v ON d.id=v.id SET d.cover_id=func_splitString(v.video,'|',2
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