schedule

Django: Running a process each day at specified user local time

感情迁移 提交于 2021-02-19 09:23:17
问题 I'm porting my site to python/django, and one of the main exercises involves a set of data where users can schedule an event in their local time, and have it happen every day. Currently i have a cron job (on another server) that hits up a method every e.g 5 minutes and see's if anything needs to be schedule over the next (let's say ) 10 minutes. I store a Time value, and the user's local timezone for each job What is the best way to do this? Right now I am working on a function that: Converts

How to start/stop a Python function within a time period (ex. from 10 am to 12:30pm)?

冷暖自知 提交于 2021-02-16 13:06:24
问题 I am trying to create a function (e.g. def startTime() ) that executes another function like def runFunc() that starts every day on execution with python script at 10 am and stops automatically (or script ends) at 12:30 pm. Example: startTime(start_time, stop_time,runFunc) Can anyone help me with that? I am trying to schedule startTime from 10 am to 12:30 pm. import threading import schedule import time def runFunc(interval, innerFunc, iterations = 0): if iterations != 1: threading.Timer

How to make @Schedule method to be called only once at a time

假如想象 提交于 2021-02-10 04:34:05
问题 We are using the @Schedule EJB annotation to start a scheduled job do a delta SOLR import every x seconds. Of course we want to have as less timeshift in indexing as possible. Currently I try to do the delta every 5 seconds. So my question is: Can I make sure the job is only called once? So let's say the indexing is lasting longer than 5 seconds, will the next schedules call wait until the previous is coming back? 回答1: Yes. You can make the bean a @Singleton and use @Lock(LockType.Write) to

How to make @Schedule method to be called only once at a time

情到浓时终转凉″ 提交于 2021-02-10 04:33:25
问题 We are using the @Schedule EJB annotation to start a scheduled job do a delta SOLR import every x seconds. Of course we want to have as less timeshift in indexing as possible. Currently I try to do the delta every 5 seconds. So my question is: Can I make sure the job is only called once? So let's say the indexing is lasting longer than 5 seconds, will the next schedules call wait until the previous is coming back? 回答1: Yes. You can make the bean a @Singleton and use @Lock(LockType.Write) to

Schedule a 6-day timetable for 5 days in python

落爺英雄遲暮 提交于 2021-02-07 10:11:45
问题 I'm creating an automation in Python, that will automatically navigate to my school's website, and join the online class, etc using selenium. I've completely finished that part, and it all works perfectly. Now, I'm trying to figure out how to schedule these actions. I was thinking of using schedule? It seems good for straightforward jobs, but I don't know if it would be any good for something like this. I have 10 classes in total. I have 6 classes in a day. My school week goes from Monday and

Schedule a 6-day timetable for 5 days in python

天涯浪子 提交于 2021-02-07 10:08:26
问题 I'm creating an automation in Python, that will automatically navigate to my school's website, and join the online class, etc using selenium. I've completely finished that part, and it all works perfectly. Now, I'm trying to figure out how to schedule these actions. I was thinking of using schedule? It seems good for straightforward jobs, but I don't know if it would be any good for something like this. I have 10 classes in total. I have 6 classes in a day. My school week goes from Monday and

Schedule a 6-day timetable for 5 days in python

可紊 提交于 2021-02-07 10:07:35
问题 I'm creating an automation in Python, that will automatically navigate to my school's website, and join the online class, etc using selenium. I've completely finished that part, and it all works perfectly. Now, I'm trying to figure out how to schedule these actions. I was thinking of using schedule? It seems good for straightforward jobs, but I don't know if it would be any good for something like this. I have 10 classes in total. I have 6 classes in a day. My school week goes from Monday and

What is an efficient way to get the max concurrency in a list of tuples?

有些话、适合烂在心里 提交于 2021-02-04 20:38:30
问题 I have been trying to solve this problem in an efficient way. The problem is: Problem Statement Given a list of tuples in the form [(start1, end1), (start2, end2), (start3, end3)....(startn, endn)] where start and end are positive integers. Each tuple is to represent a time window, for example: [(1, 3), (73, 80)...] . Find the time (integer) where max concurrency occurs and get the tuples where max concurrency occurs. Constraints: start and end are integers of time and are between 0 to n For

What is an efficient way to get the max concurrency in a list of tuples?

浪子不回头ぞ 提交于 2021-02-04 20:37:05
问题 I have been trying to solve this problem in an efficient way. The problem is: Problem Statement Given a list of tuples in the form [(start1, end1), (start2, end2), (start3, end3)....(startn, endn)] where start and end are positive integers. Each tuple is to represent a time window, for example: [(1, 3), (73, 80)...] . Find the time (integer) where max concurrency occurs and get the tuples where max concurrency occurs. Constraints: start and end are integers of time and are between 0 to n For

Schedule python clear jobs queue

自古美人都是妖i 提交于 2021-01-29 15:17:41
问题 I’m a trying to use schedule as follows: def job(): my code schedule.every().day.at("06:03").do(job) schedule.every().day.at("09:56").do(job) while True: schedule.run_pending() sleep(1) My job can’t take from 1 to 10 hours to finish executing. The problem that I’m having is this: Basically, when the first job runs (at 06:03) if the job takes around 10 hours, right when it ends it starts again because schedule runs all the jobs that it has been missing (in this case it missed the job at 09:56,