scale

I'm using the PHP function uniqid() on my server. It should be something like a microtime. So I think it is unique FOR ONE server. Is it correct? How can I get a unique id if I scale my server with a loadbalancer? I need a string with less than 31 characters. Thanks I would suggest combining multiple sources of entropy. This way you wouldn't rely on some assumptions (local IP address being different) or luck (two servers won't do the same thing exactly at the same nanotime). Things that come to my mind (and are pretty portable, not platform specific): nanotime, open temp directory in file

I ve tried all (yes all!!!) the solutions from this question and nothing seems to be working with iOS 11.3? Did someone had success with preventing pinch to zoom with ios 11.3? PS: I know that there are good reasons not to prevent pinch zooming... . But I have no choice. Many Thanks in Advance and sorry for my English. Note that most of these options break lots of functionality and are bad for accessibility etc, etc, but some applications, in particular multi-touch PWAs need to disable these features. Use at own risk. With regards to the parent comment that they've tried all the solutions in

i don't want to use the scale as classic zoom, instead i want to change the form of quadrates to a rectangle for example. After a lot of trying i'm that far that my fingers are the corners of the rectangle. So but if i start a new pinch gesture inside my view gets smaller to my fingers instead of getting bigger like the normal scale does. if ([gestureRecognizer numberOfTouches] >1) { //getting width and height between gestureCenter and one of my finger float x = [gestureRecognizer locationInView:self].x - [gestureRecognizer locationOfTouch:0 inView:self].x; if (x<0) { x *= -1; } float y =

Okay I need some Help... I got a bluetooth-le-weight-scale. I can connect my Raspberry Pi to this scale and get some data. But its not easy for me to read my values in this hex-salad. After every measurement I get two lines of Information, which should contain my values (I simulated all measurements ... Person 5 is just me pushing my hands on the scale .. Person 2 + 3 is me wearing socks on the scale, so no need to give me some medical advices if you find some unrealistic values :D ) Scale: starts with 5.0kg(officaly, but i can see a 4.9 as starting point), Max 180kg (this could be just a

I have issues to load 512x512px tiles in MKMapKit. The Server provides 512x512 .jpeg tiles. I could not find any solution or sample implementation for custom retina tiles in MKMapView. What I do: When I load them into MKMapView with overlay = [[MKTileOverlay alloc] initWithURLTemplate:template]; overlay.tileSize = CGSizeMake(512.0f, 512.0f); [_mapView insertOverlay:overlay atIndex:MAP_OVERLAY_INDEX_TILE level:MKOverlayLevelAboveLabels]; … tiles are scaling correct but only half of them is loaded (not only visually - i sniffed the requests and the tiles are missing) with overlay = [

Im attempting to build a series of thumbnails that enlarge on hover. My preliminary build accomplishes the enlarge/zoom part by using CSS3 transform:scale and ease-in-out. The problem is that they overlap each other because they share a single z-axis. Can anyone assist me in creating a javascript addition to this scenario that correctly positions each thumbnail in a z-axis that makes sense, i.e. each enlarged image resizes to be on top of each other image. Demonstration on my website here: demo Updated: Solved Preview of code: html: <div style="position: absolute;" class="item hover"> <a href=

I have written a function module that takes the argument of two variables. To plot, I had x, y = pylab.ogrid[0.3:0.9:0.1, 0.:3.5:.5] z = np.zeros(shape=(np.shape(x)[0], np.shape(y)[1])) for i in range(len(x)): for j in range(len(y[0])): z[i][j] = fancyFunction(x[i][0], y[0][j]) pylab.imshow(z, interpolation="gaussian") The image I get is the following: But when I tried rescaling the x and y axis to match the ranges of [0.3:0.9:0.1, 0.:3.5:.5] thru pylab.imshow(z, interpolation="gaussian", extent=[.3,.9,0.,3.5]) I get I've been googling for hours but still couldn't find a way to make a square