sample

A modern n-layer asp.net web application sample?

跟風遠走 提交于 2019-11-28 19:24:04
问题 So my asp.net is very very rusty, and i'm trying to get back into best practices and what not. So, I whip out google and start looking for examples and samples and tutorials, but what do I find? Old crusty stuff that tends to be written even before "the latest" technology was released back in the stone age. Sure, the concepts may still hold up. But the actual implementations are basically useless. I'm looking for something using Linq, n-layers (not tiers. Tiers can be a layer, but a layer is

How to incrementally sample without replacement?

一曲冷凌霜 提交于 2019-11-28 18:21:44
Python has my_sample = random.sample(range(100), 10) to randomly sample without replacement from [0, 100) . Suppose I have sampled n such numbers and now I want to sample one more without replacement (without including any of the previously sampled n ), how to do so super efficiently? update: changed from "reasonably efficiently" to "super efficiently" (but ignoring constant factors) Chronial Note to readers from OP: Please consider looking at the originally accepted answer to understand the logic, and then understand this answer. Aaaaaand for completeness sake: This is the concept of

WPF sample applications

十年热恋 提交于 2019-11-28 17:23:23
问题 Are there any WPF sample applications that showoff the 'coolness' of WPF? I'm hoping to see some examples of the UI capabilities etc., and general structure and best practices. (oh, and the install shouldn't be too elaborate hehe) 回答1: Family.Show is a great end-to-end reference sample ... done by Vertigo. I believe that Microsoft commissioned this sample application in order to demonstrate the power of WPF. It definitely shows off some best practices (e.g. how to skin an app, etc.). 回答2: I

Dataframe sample in Apache spark | Scala

元气小坏坏 提交于 2019-11-28 07:28:35
I'm trying to take out samples from two dataframes wherein I need the ratio of count maintained. eg df1.count() = 10 df2.count() = 1000 noOfSamples = 10 I want to sample the data in such a way that i get 10 samples of size 101 each( 1 from df1 and 100 from df2) Now while doing so, var newSample = df1.sample(true, df1.count() / noOfSamples) println(newSample.count()) What does the fraction here imply? can it be greater than 1? I checked this and this but wasn't able to comprehend it fully. Also is there anyway we can specify the number of rows to be sampled? Daniel de Paula The fraction

How do you extract a few random rows from a data.table on the fly

笑着哭i 提交于 2019-11-28 07:19:17
I have a large data.table (about 24000 rows and growing). I want to subset that datatable based on a couple of criteria and from that subset (ends up being about 3000 rows) I want to randomly sample just 4 rows. I do not want to create a named 3000 or so row data.table, count its rows and then sample based on row number. How can I do it on the fly? Or should I just suck it up by creating the table and then working on it, sampling it and then using rm() to get rid of it? Lets simulate my issue require(data.table) random.length <- sample(x = 15:30, size = 1) data.table(city=sample(c("Cape Town",

MediaScannerConnection produces android.app.ServiceConnectionLeaked

时间秒杀一切 提交于 2019-11-28 07:15:31
I'm using the MediaScannerConnection example code from the API Demos The snippet I'm using is: MediaScannerConnection.scanFile(context, new String[] { permFile.getAbsolutePath() }, null, new MediaScannerConnection.OnScanCompletedListener() { public void onScanCompleted(String path, Uri uri) { android.util.Log.i("ExternalStorage", "Scanned " + path + ":"); android.util.Log.i("ExternalStorage", "-> uri=" + uri); } }); When I run this code I get a FC dialog with the following from the LogCat: 4-20 23:17:45.988: ERROR/ActivityThread(3015): Activity com.my.package.name has leaked ServiceConnection

Firebase database getInstance crashes app

戏子无情 提交于 2019-11-28 04:12:47
问题 When running the sample after creating google-service.json, the app crashes when trying to get database reference in SignInActivity mDatabase = FirebaseDatabase.getInstance().getReference(); Crash log 05-21 09:27:27.644 488-488/com.google.firebase.quickstart.database D/AndroidRuntime: Shutting down VM 05-21 09:27:27.644 488-488/com.google.firebase.quickstart.database E/AndroidRuntime: FATAL EXCEPTION: main Process: com.google.firebase.quickstart.database, PID: 488 java.lang.RuntimeException:

Can Web Components be used to create custom input elements?

夙愿已清 提交于 2019-11-27 21:19:16
问题 How is it/(or just "is it?") possible to create a Web Component that can be placed inside a form and act just as any input element, that's sent to the server on submit? In other words, can Web Components be used to create custom input elements? 回答1: Use the following browser configuration options before testing: Chrome: about:flags => Enabled Experimental WebKit Features/Enable Experimental Web Platform Firefox: about:config => dom.registercomponents.enabled to enable document.registerElement

How to get a sample with an exact sample size in Spark RDD?

為{幸葍}努か 提交于 2019-11-27 20:43:55
Why does the rdd.sample() function on Spark RDD return a different number of elements even though the fraction parameter is the same? For example, if my code is like below: val a = sc.parallelize(1 to 10000, 3) a.sample(false, 0.1).count Every time I run the second line of the code it returns a different number not equal to 1000. Actually I expect to see 1000 every time although the 1000 elements might be different. Can anyone tell me how I can get a sample with the sample size exactly equal to 1000? Thank you very much. If you want an exact sample, try doing a.takeSample(false, 1000) But note

How to incrementally sample without replacement?

我只是一个虾纸丫 提交于 2019-11-27 20:16:46
问题 Python has my_sample = random.sample(range(100), 10) to randomly sample without replacement from [0, 100) . Suppose I have sampled n such numbers and now I want to sample one more without replacement (without including any of the previously sampled n ), how to do so super efficiently? update: changed from "reasonably efficiently" to "super efficiently" (but ignoring constant factors) 回答1: Note to readers from OP: Please consider looking at the originally accepted answer to understand the