How to recursively take the last argument of a macro?
问题 Using a simple recursive macro like the example below, its common to take the first argument, then glob the rest. macro_rules! count_tts { () => {0usize}; ($_head:tt $($tail:tt)*) => {1usize + count_tts!($($tail)*)}; } Is there a way to recursively take the last argument? This makes it possible to: Handle the arguments in reverse. Take all the previous arguments into account (count them for example, see related question) Something like ($($head:tt)* $tail:tt) ... but this doesn't work. 回答1: