routes

问题 I have a route like this: // Open New Subscription page Route::get('/account/subscriptions/create/{menu}', ['uses' => 'Subscriptions\SubscriptionController@create', 'as' => 'subscription.create']); In my blade template I use the named route like this: <a href="{!! route('organisations.index') . "/p11-c3" !!}"> But this format does not work. How do I pass the variable menu a value while still using the named route (rather than hard coding a url in the href )? 回答1: You can pass your route

问题 I am calling a static method within my business logic layer that, for purposes I won't mention here, needs to do the redirecting itself rather returning information back to the controller to do the redirect. I figure I need to use the HttpContext object but am struggling with creating the route. I can't simply do context.Response.Redirect("someController/someMethod) because I need to include parameters for the action controller that I"m sending the user to. Assuming this is correct:

问题 I'm trying to test routes with rspec. The following gives an error of "Expected block to return true value". I'm not sure what I am missing. Through a browser I can post to this url and it is successful. Any ideas? Thanks! Routes resources :forum_topics do resources :forum_sub_topics end Test: it "recognizes and generates nested #create" do { :post => "/forum_topics/1/forum_sub_topics" }.should route_to(:controller => "forum_sub_topics", :action => "create", :forum_topic_id => 1) end 回答1:

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . I have configured a openvpn connection from my debian pc to my remote debian server, and it works. In fact, I can ping 10.0.0.1 (address in vpn of the server). Now I want to share this connection. I want my other clients on lan can access the server without openvpn client. How can I do it? My lan standard

问题 need next: I use codeigniter 2.02 I removes index.php with htaccess I have controller post and with route $route['(:any)'] = "post/index/$1"; And I get what I want: domain.com/14 in place of domain.com/post/14 BUT now I have next controllers that I want like: login, member etc. But if I go to domain.com/login I'm redirected to domain.com ... so if someone can get me solution so I can go to login controller... with some regular expression with routes! this is my routes: $route['default

问题 I have a route for addresses: namespace :carts do resources :address Yet it generates a mispelling for the new path, addres . Is this a bug in Rails 3.2.14? carts_address GET /carts/address(.:format) refinery/carts/address#index POST /carts/address(.:format) refinery/carts/address#create new_carts_addres GET /carts/address/new(.:format) refinery/carts/address#new edit_carts_addres GET /carts/address/:id/edit(.:format) refinery/carts/address#edit carts_addres GET /carts/address/:id(.:format)

问题 I m trying to achive route like that: http://mysite.com/portfolio/landscape http://mysite.com/portfolio/friends etc... so I wrote that: public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "DefaultIndex", // Route name "{controller}/{id}", // URL with parameters new { action = "Index", id = UrlParameter.Optional } // Parameter defaults ); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL

问题 my routes: routes.MapRoute( "Tag", "tag/{t}/{action}", new { controller = "tag", action = "unsolved" } ); the link like: <a href="/tag/@(Uri.EscapeDataString(tagName))/unsolved">@tagName</a> if the tagName not contain "+",all work well , else ,like "http://www.test.com/tag/c%2B%2B/unsolved"(%2B come from @(Uri.EscapeDataString("+")),i get the error: HTTP error 404.11 - Not Found who can help me? thanks! 回答1: You may try allowing double escaping in the <system.webServer> section of your web

问题 I am getting the same data when I am clicking on the next button of pagination in CodeIgniter with the following code public function view($slug){ $data['title']= $slug; $data['description']= "None"; $postdatacount = $this->Constant_model->snippettagscount($slug); $checktags= $this->Constant_model->gettags($slug); if($checktags>0){ if ($postdatacount>0) { $config = array(); $config["base_url"] = base_url() ."tags/".$slug; $config["total_rows"] = $postdatacount; $config["per_page"] = 6;

问题 This question already has answers here : Trailing slash triggers 404 in Flask path rule (3 answers) Closed 5 months ago . While testing my Flask-based web app on various browsers, I found out that Chrome browser appends a "/" after one of of my routes and only one. This behavior results in a page not found error since my routes is like this: /dictionary But Chrome renders is like this: /dictionary/ Which according to flask is not the same thing. Here is my /dictionary route and method: @app