rounding | 易学教程

Check where number 1 is in decimal number

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问题 I am having hundreds of numbers like: 0.00100000 0.01000000 0.01000000 1.00000000 0.00001000 0.00000100 I need to check where the number 1 is in those number, so basicly 1.00000000 = 1 0.10000000 = 2 0.01000000 = 3 I tried Round() function, but it sometimes prints numbers like 1.E-6 or something like that, I need exact location of number 1. Thank you very much for help. 回答1: I wouldn't rely too much on the approach you posted in your answer. Use the following function instead: function index

javascript math.round and math.floor work fine in IE and Opera but not Chrome, Safari or Firefox. Getting NaN

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问题 Take a look at this fiddle: http://jsfiddle.net/gD3ax/1/ or here's the full markup <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Calculator</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <style type="text/css"> .header { font-size: 10pt; color: white; font-weight: 700; text-decoration: none; text-underline-style: none; text-line

Can I implement round half to even?

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问题 I need to do round half to even on floats, i.e., if the value is half-way between two integers (tie-breaking, fraction part of y is exactly 0.5) round to the nearest even integer, else, standard round (which is Round to nearest Integer in Ruby). These are some results, for example: 0.5=>0 1.49=>1 1.5=>2 2.5=>2 2.51=>3 3.5=>4 回答1: I would reopen the Float class to create a round_half_to_even function : class Float def round_half_to_even(precision) if self % 1 == 0.5 floor = self.to_i.to_f

How to Perform Tuckerman Rounding for Floating Point Square Root

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问题 I am trying to perform a Tuckerman Rounding Test in order to determine the correctly rounded to nearest result. I created a program in C++ to compare two solutions to a square root of a number and perform a tuckerman test on them. However, the C++ math library solution fails to pass the tuckerman test, so I'm wondering what could be wrong? Here is my output: Square root program started Input value is 62a83003 ===Tuckerman Test with MATLAB result=== Square root result from MATLAB = 5112b968 g*

How to fix 'Unrecognized expression $round' while applying it to stored data in pipeline using mongodb $and condition with $lookup

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问题 I have applied precision to the data coming from DB, while viewing it in browser using Angular 7. Front End: Angular 7 Back End: Java and Mongodb before precision (in db): 100.9999 after precision visible to user(2 after decimal): 101.00 There is a search functionality on UI in which a user can write any amount range. Scenario 1: User inpu t: 100 to 100 Result: no records found (expected) Scenario 2: User input: 101 to 101 Result: no records found (should have found 1 record according to user

Oracle SQL - Round - Half

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问题 Oracle ROUND function rounds "half up" by default : select 3.674 my_number, round(3.674,2) round_on_number from dual union select 3.675 my_number, round(3.675,2) round_on_number from dual union select 3.676 my_number, round(3.676,2) round_on_number from dual ; MY_NUMBER ROUND_ON_NUMBER ---------- --------------- 3,674 3,67 3,675 3,68 3,676 3,68 I need to round "half down", which essentially means that I should get the following result instead : MY_NUMBER EXPECTED_ROUND_ON_NUMBER ---------- --

Do I have a rounding error? Perl

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问题 My script is supposed to do following. It takes an old list of scalars and makes a new, corresponding list of numbers. The old list is referred to as @oldMarkers and the new list as @newMarkers. Sample input is like: chr1, chr2, IMP, chr3, IMP, IMP, IMP, chr4 Sample output is like: 1, 2, 2.1, 3, 3.1, 3.2, 3.3, 4 The point of the script is to read the list of @oldMarkers and output a list where for each instance of an element containing the letters "chr," an integer is pushed into the array

Why is JavaScript's number display for large numbers inaccurate?

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问题 So in JavaScript, 111111111111111111111 == 111111111111111110000. Just type any long number – at least about 17 digits – to see it in action ;-) That is because JavaScript uses double-precision floating-point numbers, and certain very long numeric literals can not be expressed accurately. Instead, those numbers get rounded to the nearest representable number possible. See e.g. What is JavaScript's highest integer value that a Number can go to without losing precision? However, doing the math

round() breaks when PHP precision is set to 18+

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问题 When I set PHP's precision setting to values 18 or higher (whether in php.ini or at runtime), the round() function yields unexpected results. Is this a bug; or what am I missing? Results for e.g. rounding the float 12.4886724321 to 4 decimal precision are as follows: 14: 12.4887 ... 17: 12.4887 18: 12.4886999999999997 19: 12.48869999999999969 20: 12.48869999999999969 21: 12.4886999999999996902 22: 12.4886999999999996902 23: 12.488699999999999690203 24: 12.4886999999999996902034 Test case as

DATEDIFF with minute does not return expected value

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问题 Say, I have the following SQL Server 2008 table with data: CREATE TABLE tbl (dtIn DATETIME2, dtOut DATETIME2) INSERT tbl VALUES ('9/10/2012 5:14:10 AM', '9/10/2012 5:15:09 AM'), ('9/10/2012 5:16:12 AM', '9/10/2012 5:18:12 AM'), ('9/10/2012 5:18:43 AM', '9/10/2012 5:23:04 AM'), ('9/10/2012 5:25:17 AM', '9/10/2012 5:26:05 AM'), ('9/10/2012 5:26:57 AM', '9/10/2012 5:29:19 AM'), ('9/10/2012 5:31:41 AM', '9/10/2012 5:32:41 AM'), ('9/10/2012 5:33:16 AM', '9/10/2012 5:34:08 AM'), ('9/10/2012 5:35:25