rmi

Why Does Simple RMI Server Need Codebase?

依然范特西╮ 提交于 2019-12-02 03:57:15
OS: Windows 7 JDK: 1.8.0_05 I am working through some simple RMI tutorials including Oracle's "Compute" sample ( compute ). Starting my server should not require a codebase, and answers to questions similar to this one say that "the codebase is optional." Yet my server can't register a remote object unless its interface is in some codebase. I make sure my Compute interface is available to the web server running on localhost, start the registry server like this: set CLASSPATH= rmiregistry -J-Djava.rmi.server.codebase="http://localhost:80/" And everything works fine: Exporting stub Locating

Java RMI:Updating client side objects in the server

社会主义新天地 提交于 2019-12-02 03:27:09
I'm trying to implement a middle-ware for group communication in a distributed system using Java RMI. In there, I need to send an object to server and modify it. So that changes should be reflected in the client side. For example, I will give the most common tutorial in Oracle web site. X.java public class X implements Serializable, Remote{ public int x; // defined as public, just be simple. } Hello.java import java.rmi.Remote; import java.rmi.RemoteException; public interface Hello extends Remote { String sayHello(X c) throws RemoteException; } Server.java import java.rmi.registry.Registry;

Java RMI server and Objective C client

十年热恋 提交于 2019-12-02 03:06:17
I have a java rmi server and an objective C client. I want to use RMI to HTTP tunneling in order to encapsulate the RMI calls into HTTP requests where an RMI servlet handler can forward the call into the corresponding rmi server. However I'm facing an issue. Let's say for instance that I created the stub and bound the stub on the registry with a certain name (on the server side). Now in objective C, how can I locate the registry and lookup the stub? because in normal cases where we have an rmi client, it can be done this way: Registry registry = LocateRegistry.getRegistry(host); Hello stub =

RMI Question - Where do clients get a definition for remote classes that have not been added to registry?

霸气de小男生 提交于 2019-12-02 01:06:27
Ive managed to create an RMI application that does what i need it to do quite succesfully, but im having a bit of trouble getting my head around where client obtains definitions for remote objects. for example: I have a server that registers itself with the rmiregistry (allowing clients to call methods on it). UnicastRemoteObject.exportObject(new Server(), 0); running reg.list() confirms that my server has indeed been added to the registry. I have another remote object (rObj) running on the same JVM as the server. This is not added to the registry. In my client, i can get the definition of my

rmi java.lang.ClassNotFoundException: testrmi2.fileserverimpl_Stub

浪子不回头ぞ 提交于 2019-12-02 00:43:57
问题 Hi guys I'm programming a simple rmi application, but I have a problem. If I run the registry in the same directory, it works; but if i change the directory from which I run the registry does not. I think it's impossible this situation. The registry would work generically from another host, but only the change of directory stop his functionality. I'm working on this problem by 3 days without solution, I change also every possible configuration of the codebase parameter but nothing. I describe

RMI: Pass by Value or by Reference?

旧街凉风 提交于 2019-12-01 23:54:31
问题 I'm having trouble finding a clear answer to this question so I thought I'd ask here with my own specific example: I am creating a mulitplayer monopoly game. The actual monopoly code runs on the server and the client is essentially a GUI which accesses and control this code. The monopoly game is controlled by a class called 'Bank'. Say I did this in the main() of my client: Bank banker = server.getBank(); //gets the bank object from server bank.turn(); //moves the current player Would this

rmi java.lang.ClassNotFoundException: testrmi2.fileserverimpl_Stub

荒凉一梦 提交于 2019-12-01 21:32:44
Hi guys I'm programming a simple rmi application, but I have a problem. If I run the registry in the same directory, it works; but if i change the directory from which I run the registry does not. I think it's impossible this situation. The registry would work generically from another host, but only the change of directory stop his functionality. I'm working on this problem by 3 days without solution, I change also every possible configuration of the codebase parameter but nothing. I describe the situation and code with the directory: fileserver.java : `package testrmi2; import java.rmi.*;

Is it necessary/important to set a classpath in the RMI registry?

两盒软妹~` 提交于 2019-12-01 20:54:59
Is it necessary or important to set a class path in the registry for RMI to work correctly? Contrary to @Rahul's baseless assertion, it is indeed necessary to set a CLASSPATH for the RMI Registry, unless: You are starting the Registry from a directory which is also the head of a package structure of .class files. You are using the codebase feature, or You are starting the Registry in the same JVM as your RMI remote obects, via LocateRegistry.createRegistry(). If you don't do one of these four things, you will get a ServerException wrapping a ClassNotFoundException when you bind your remote

Java ArrayList / RMI

拟墨画扇 提交于 2019-12-01 17:57:39
问题 I've built a simple item class; class itemInfo{ int auctionID; int startPrice; int buyoutPrice; } I've created an ArrayList; ArrayList<itemInfo> itemSet = new ArrayList<itemInfo>(); I also have a method here that allows a user to create an item (the method is incomplete, I've only tried implementing choice == 1 so far!); public void auctionChoice(){ System.out.println("---- What would you like to do? ----\n"); System.out.println("1: List an item for auction\n"); System.out.println("2: Bid on

Why does java rmi keep connecting to 127.0.1.1. When ip is 192.168.X.X?

这一生的挚爱 提交于 2019-12-01 17:41:26
问题 I have a java rmi application i simply do: Client: Registry registry = LocateRegistry.getRegistry("localhost"); costApi = (CostApi) registry.lookup("server.CostApi"); Everything works fine when I host the server at localhost. When I start the same program at another machine withing the local network, at 192.168.x.x and change to: Client: Registry registry = LocateRegistry.getRegistry("192.168.x.x"); costApi = (CostApi) registry.lookup("server.CostApi"); it does not work anymore and it fails