reverse

问题 I need to create a program that will reverse a list destructively. For example lets say.. scm> (define L (list 1 2 3 4)) scm> (reverse! L) (4 3 2 1) scm> L (1) Where L becomes the last element of the reversed list. I know I am supposed to use set-cdr! somehow but cannot figure out how to implement it. 回答1: Because this looks like homework, I can't give you a straight answer. I'll show you the general structure of the solution, so you can figure out the details and fill-in the blanks: (define

问题 As the title says. How can I reverse the animation path in a pie (D3.js). As default, the pie renders clockwise with animation. How do I reverse it? See picture example. JS here: var pie = d3.layout.pie() .sort(null) .startAngle(1 * Math.PI) .endAngle(3 * Math.PI) .value(function (d) { return d.percentage; }); g.append("path") .attr("d", arc) .style("fill", function (d) { return d.data.color; }) .attr({ "fill": function (d) { return d.data.color; } }) .transition() .duration(1000) .attrTween(

问题 I'm trying to do a number system calculator but only using the control or repetitive structures. Here's my sample: int base = 0, given = 0, remainder = 0; // input given here System.out.print("The answer is: "); if (base == 2){ while(given != 0){ remainder = given % base; given /= base; System.out.print("" + remainder); } } And the output goes like this: Input: 32 The answer is: 000001 The question is, how would I reverse the output to 100000 since the binary of 32 is 100000 and not 000001?

问题 I am struggling with writing things like this: list(reversed(list(el.iterancestors()))) + [1,2,3] Where generators suck, because I am forced to consume the them into lists. Is there a way to simplify this? I think reversed() should accept an iterator, am I wrong? 回答1: Generators are not guaranteed to have a last item, so can't be reversed. What would be the output of the following? from itertools import cycle reversed(cycle('abc')) There is also the risk of accidentally eating all your memory

问题 given the following views.py return redirect('order-review', order=order.id) urls.py url(r'^review/$', 'checkout.views.review', {'order': '0'}, name="order-review"), aimed at views.py def review(request, order): is there a really obvious fix? I just can't see what i've got wrong and the django docco is slightly light on examples when passing a variable through. 回答1: It doesn't resolve, because your url pattern actually hard-codes the order value (it will always be '0'). You have to provide a

问题 My professor already got started on the code and it looks like... #include "stdafx.h" int main(int argc, char* argv[]) { int numchar; char mystring[] = "This is the string to be printed in reverse order"; numchar = reverseString(mystring); puts("Reversed String is "); puts(mystring); } int reverseString(char *mystring) { } Now I'm supposed to finish it and that's where I'm stuck. I've looked up countless example programs of reversing strings but all of them were done differently and I'm lost

问题 So I had my listview working perfectly then I decided to add a context menu. As soon as I did that whenever I normal clicked an item in my listview, the entire list gets inverted on the first click. Subsequent clicks do nothing to the order, but when the first item is de-selected again the list returns to normal. When I take out the context menu logic that I added, the list view problem does not go away. I've attached a debugger and the elements in my list adapter are never reordered, and the

问题 I am trying to pull the id from the newly created project object so I can redirect the user to the page containing the new project. Right now I get "'ProjectAddForm' object has no attribute 'id'". I have read online that this should work but for some reason it's not. if request.method == 'POST': form = ProjectAddForm(request.POST) if form.is_valid(): form.save() return HttpResponseRedirect(reverse('project.views.detail', args=(form.id))) Forms.py class ProjectAddForm(forms.ModelForm): class

问题 So I'm still shaky on how basic java works, and here is a method I wrote but don't fully understand how it works anyone care to explain? It's supposed to take a value of s in and return it in its reverse order. Edit: Mainly the for loop is what is confusing me. So say I input "12345" I would want my output to be "54321" Public string reverse(String s){ String r = ""; for(int i=0; i<s.length(); i++){ r = s.charAt(i) + r; } return r; } 回答1: We do a for loop to the last index of String a , add

问题 I have just started to learn assembly language and i am trying to print "hello world" in reverse order that means "dlrow olleh".the problem is i am getting only 1st letter as output and the order is still same no change at all!As a newbie many thing is unknown to me and i am doing lots of mistakes and i am unable to identify them due to lack of knowledge.So any answer with proper explanation will be appreciated!Here is my code: name "hi" ; can anybody explain what is the use of this? org 100h