reverse

Reverse Contents in Array

早过忘川 提交于 2019-12-17 12:17:14
问题 I have an array of numbers that I am trying to reverse. I believe the function in my code is correct, but I cannot get the proper output. The output reads: 10 9 8 7 6. Why can't I get the other half of the numbers? When I remove the "/2" from count, the output reads: 10 9 8 7 6 6 7 8 9 10 void reverse(int [], int); int main () { const int SIZE = 10; int arr [SIZE] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; reverse(arr, SIZE); return 0; } void reverse(int arr[], int count) { int temp; for (int i = 0;

How to Reverse a List?

大城市里の小女人 提交于 2019-12-17 11:08:52
问题 What is the function to a list in Scheme? It needs to be able to handle nested lists. So that if you do something like (reverse '(a (b c d) e)) you'll get (e (b c d) a) as the output. How should I approach this problem? I'm not just looking for an answer, but something that will help me learn. 回答1: (define (reverse1 l) (if (null? l) nil (append (reverse1 (cdr l)) (list (car l))) ) ) Explanation: Rules: 1. If list is empty, then reverse list is also empty 2. else behind reverse tail of the

Reverse a string without using reversed() or [::-1]?

倖福魔咒の 提交于 2019-12-17 10:25:30
问题 I came across a strange Codecademy exercise that required a function that would take a string as input and return it in reverse order. The only problem was you could not use the reversed method or the common answer here on stackoverflow, [::-1] . Obviously in the real world of programming, one would most likely go with the extended slice method, or even using the reversed function but perhaps there is some case where this would not work? I present a solution below in Q&A style, in case it is

Linked list recursive reverse

我与影子孤独终老i 提交于 2019-12-17 07:12:51
问题 I was looking at the code below from stanford library: void recursiveReverse(struct node** head_ref) { struct node* first; struct node* rest; /* empty list */ if (*head_ref == NULL) return; /* suppose first = {1, 2, 3}, rest = {2, 3} */ first = *head_ref; rest = first->next; /* List has only one node */ if (rest == NULL) return; /* put the first element on the end of the list */ recursiveReverse(&rest); first->next->next = first; /* tricky step -- see the diagram */ first->next = NULL; /* fix

How to get a reversed list view on a list in Java?

风流意气都作罢 提交于 2019-12-17 07:09:12
问题 I want to have a reversed list view on a list (in a similar way than List#sublist provides a sublist view on a list). Is there some function which provides this functionality? I don't want to make any sort of copy of the list nor modify the list. It would be enough if I could get at least a reverse iterator on a list in this case though. Also, I know how to implement this myself. I'm just asking if Java already provides something like this. Demo implementation: static <T> Iterable<T>

javascript reverse string algorithm

天大地大妈咪最大 提交于 2019-12-14 04:13:41
问题 I'm tying to solve how to reverse a string. I already figured out how to reverse an array so i'm trying to use that answer in this one. I figure I can convert the string to an array an then just go from there...Well this is what I have so far and tips or advice is welcome. function reverse(string){ var x = string.split(' '); for(i=0; i=x.length; i++){ var y= x.pop(); console.log(y); } } 回答1: See the fiddle : https://jsfiddle.net/1wknqn2d/1/ function reverse(string){ return string.split('')

Django NoReverseMatch url issue

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-14 02:28:06
问题 I'm getting the error "Reverse for 'recall' with arguments '('',)' and keyword arguments '{}' not found. 1 pattern(s) tried: [u'associate/recall/']" When I try to submit a form. Here is my html: <form action="{% url 'associate:recall' ordered_group %}" method="post"> {% csrf_token %} <div> <label for="recall">enter as many members of {{ ordered_group }} as you can recall </label> <input type="text" id="recall" name="recall"> </div> <div id="enter_button"> <input type="submit" value="enter"

Deep-reverse for trees in Scheme (Lisp)

五迷三道 提交于 2019-12-14 01:12:08
问题 I have a deep reverse for a basic tree data structure in Scheme (define (deep-reverse t) (cond ((null? t) '()) ((not (pair? t)) t) (else (cons (deep-reverse (cdr t)) (deep-reverse (car t)))))) (define stree (cons (list 1 2) (list 3 4))) 1 ]=> (deep-reverse stree) ;Value: (((() . 4) . 3) (() . 2) . 1) I feel like a cleaner, better result would be: (4 3 (2 1)) Can anyone provide some guidance as to where I'm going wrong in my deep-reverse function? Thank you. 回答1: It's better to split the task

Using edge.js is it possible for the .Net C# module to call the node.js part of the process, i.e. do the reverse call?

牧云@^-^@ 提交于 2019-12-14 01:01:35
问题 You can see the interop model for going from Node.js -> C#, here. What I want to know is, can the C# code then make a call to a method in the Node.js part of the process from the C#, before returning? Imagine if you had a call, like var webApi = edge.func('/MyDotNetApi.csx'); webApi(function (error, result) { log.('api started'); }); where the MyDotNetApi.csx returns, but leaves a socket listener thread running to handle HTTP requests. Now, if the Node.js part of the process holds (ever

Django 1.8.2 — Tutorial Chapter 3 — Error: NoReverseMatch at /polls/ — Python 3.4.3

蹲街弑〆低调 提交于 2019-12-13 18:13:29
问题 I've been following the official tutorial exactly. It's located here: https://docs.djangoproject.com/en/1.8/intro/tutorial03/ It's been going well, but suddenly I'm getting this error: Reverse for 'detail' with arguments '(1,)' and keyword arguments '{}' not found. 0 pattern(s) tried: [] It happened as soon as I changed this line: <li><a href="/polls/{{ question.id }}/">{{ question.question_text }}</a></li> to this new version: <li><a href="{% url 'detail' question.id %}">{{ question.question