reset

I want a debug function to do this, but I'm unaware of whether one already exists. Going through and using 'drop table' for each of my tables will be a pain. Help appreciated. Since the database is just one file, you can indeed just erase it. If you want something more automatic, you can use the following to do it all programmatically: Recover your schema: SELECT group_concat(sql,';') FROM sqlite_master; Disconnect from the database Delete the database file Create your schema again with what was returned from the above query If you used any particular options for your original database (page

I have built a nice piece of code, some animation and some click/hover events, quite a small row of them. I intend to use it on multiple html-documents (it is a game, you have to get right answer and proceed with next question), built together in another html with full-page-slider (I don't want to load DOM multiple times, makes no sense): the unsolved question is: how to reset the code without actually reloading it? how to make it to clear everything so far and start over? I am a beginner, building stuff upon others snippets. I guess it must be something so easy and basic that nobody answered

git在本地环境中存在三个区域：工作区------------------暂存区----------------------------commit区（叫法不标准） 在使用git reset时有三个级别：head---------------------mixed(默认级别)-------------------------------soft head:会将指定的内容覆盖工作区、暂存区、commit区 mixed:会将指定的内容覆盖暂存区、commit区，工作区内容不变 soft:会将指定的内容覆盖commit区，暂存区和工作区内容不变 并且执行这些操作时对远程的分支是没有影响的，需要改变远程时需要使用push 来源： https://www.cnblogs.com/zhaolei1996/p/11894559.html

Why is it that git allows me to reset a file? I thought I understood reset , in the sense that it was moving the HEAD ... clearly I was wrong. So, git reset sha file seems to do the same as git checkout sha file , with the exception that I see file in the index and in the working directory. It doesn't make sense to me. Can someone please explain the difference? manojlds tl;dr git reset COMMIT FILE changes only index, git checkout COMMIT FILE will change both index and working tree. git reset has very important flags of --soft , --hard and --mixed ( and --keep and --merge ) http://git-scm.com

参考 https://git-scm.com/book/zh/v2/Git-%E5%B7%A5%E5%85%B7-%E9%87%8D%E7%BD%AE%E6%8F%AD%E5%AF%86 https://git-scm.com/book/en/v2/Git-Tools-Reset-Demystified https://git-scm.com/docs/git-reset https://www.liaoxuefeng.com/wiki/896043488029600/897013573512192 前言 在使用git的时候，我们一般提倡是不允许回滚。对于问题的追踪和项目的发展历程而言历史记录都是有用的。并且为了节省一点存储空间而丢失宝贵的代码信息是不值当的。但是我们开发中，肯定会遇到特殊情况需要回退。比如确实操作错了一步历史提交，导致仓库混乱污染或是内容丢失，我们需要回退到干净的一次提交，重新操作。 在git等所有的版本管理软件中，删除操作，只是增加一次记录，内容并不会被删掉，我们可以大胆的操作，这也符合版本仓库的逻辑。只有特殊情况才需要真正的删除，做这种操作的时候需要特别注意，因为一旦失误，无法挽回。 从历史记录中删除 参考 https://www.cnblogs.com/studywithallofyou/p/11772684.html https://www.cnblogs

I've encountered a problem where I had to load more than 200 new users into my django app and right away send them a password reset email. This had to happen only once, done only by me and run quietly on backend. Surfing the internet brought me only to one more or less right answer: Trigger password reset email in django without browser? . The only problem was is that this post was about 4 years old and of course when I tried the solution, it didn't work... Two most valuable points from the link I mentioned: 1) In more recent version of Django we need to call form.is_valid() 2) Sending of

I accidentally removed all the privileges from my MySQL root user, Is there some way I can restore this user to its original state (with all privileges)? i m using my sql work bench 6.0 please let me know soultion step by step as i m new in my sql. First try GRANT ALL ON *.* TO 'root'@'localhost'; if that does not work then do the following Stop mysqld service with this ( on UNix-like systems) sudo mysqld stop Restart it with the --skip-grant-tables option. Connect to the mysql with just: mysql (i.e. no -p option, and username may not be required). Use the following in the mysql client: UPDATE

I have a problem resetting Oracle Sequence to have MIN VALUE = 1 and starting next number used is 1. I have followed through the answer of this question: How do I reset a sequence in Oracle? create or replace procedure reset_seq( p_seq_name in varchar2 ) is l_val number; begin execute immediate 'select ' || p_seq_name || '.nextval from dual' INTO l_val; execute immediate 'alter sequence ' || p_seq_name || ' increment by -' || l_val || ' minvalue 0'; execute immediate 'select ' || p_seq_name || '.nextval from dual' INTO l_val; execute immediate 'alter sequence ' || p_seq_name || ' increment by

Trying to find an elegant solution to reset a webform (or more specifically two INPUT Type='hidden' fields) if a user goes BACK after the form is submitted. I understand that BACK button does not trigger an onload event. But is there any way of dealing with this? when the back button is pressed, onbeforeunload event is fired so you can try something like jQuery: $('#form_id').submit(function(){ $(window).unload(function () { $('input[type="hidden"]').val("reset_value"); } }); javascript: <form onsubmit="call_function();"> in between script tag: function call_function(){ window.onbeforeunload =

I am setting a cookie Request.Cookies("TemplateName").value on one of my pages(page 3) of my application. Now I can navigate from page 3 to page 4 and page 2 and retain the value of the cookie. But now when I logout and login again it still has the value, how can I reset the value of the cookie to be blank "" when I start a new instance? I tried: Request.Cookies("TemplateName").Expires = Now Request.Cookies("TemplateName").value = "" On my homepage, but the cookie still retains the value on page 2 and 3. You need to use the Response not the Request Response.Cookies["TemplateName"].Value = "";