replace

问题 I need you help. I have a log.txt file with various data in it which I have to anonymize. I would like to retrieve all these "strings" matching a predefined patterns, and replace these by another values for each of them. What is important is that each new string from the same pattern (and with different value from the previous) should be replaced by the predefined value increased by +1 (e.g. "orderID = 123ABC" becomes "orderID = order1" and "orderID=456ABC" becomes "orderID=order2"). The

问题 How can I replace all cells in a boolean dataframe (True/False) with the index name of that cell, when "True"? For example: df = pd.DataFrame( [ [False, True], [True, False], ], index=["abc", "def"], columns=list("ab") ) comes out as: df = pd.DataFrame( [ [False, abc], [def, False], ], index=["abc", "def"], columns=list("ab") ) 回答1: Use df.mask: Replace values where the condition is True. df.mask(df,df.index) a b abc False abc def def False 来源： https://stackoverflow.com/questions/60703065

问题 How can I replace all cells in a boolean dataframe (True/False) with the index name of that cell, when "True"? For example: df = pd.DataFrame( [ [False, True], [True, False], ], index=["abc", "def"], columns=list("ab") ) comes out as: df = pd.DataFrame( [ [False, abc], [def, False], ], index=["abc", "def"], columns=list("ab") ) 回答1: Use df.mask: Replace values where the condition is True. df.mask(df,df.index) a b abc False abc def def False 来源： https://stackoverflow.com/questions/60703065

问题 I have a table with misspelling words. I need to correct those using from the words more similar to that one, the one that have more frequency. For example, after I run aggregate(CustomerID ~ Province, ventas2, length) I get 1 2 AMBA 29 3 BAIRES 1 4 BENOS AIRES 1 12 BUENAS AIRES 1 17 BUENOS AIRES 4 18 buenos aires 7 19 Buenos Aires 3 20 BUENOS AIRES 11337 35 CORDOBA 2297 36 cordoba 1 38 CORDOBESA 1 39 CORRIENTES 424 So I need to replace buenos aires, Buenos Aires, Baires, BUENOS AIRES, with

问题 I have this HTML template on a page: <div id="bid_wrapper_[[bid_id]]_[[template]]"> <div class="form_item_block" id="bid_wrapper_[[bid_id]]_[[template]]"> <div id="bid_delete_[[bid_id]]_[[template]]"><img src="/images/icons/cross.png"></div> <div id="bid_label_wrapper_[[bid_id]]_[[template]]">Bid #1</div> <div><input type="text" name="bid_summary" id="bid_summary_[[bid_id]]_[[template]]"></div> <div><input name="bid_price" id="bid_price_[[bid_id]]_[[template]]"></div> </div> </div> I'm trying

问题 I have k:v dictionary of hostname: IP that I want to use in a lookup from another dictionary to replace entries matching key from 1st dictionary and replacing it with the corresponding value in 2nd dictionary; 1st: "nb_console_ip": { "office-con01": "10.20.30.100", 2nd: "nb_console_port": [ { "console": "office-con01", "hostname": "office-core01", "port": "con1" }, { "console": "office-con01", "hostname": "office-core02", "port": "con2" }, { "console": "office-con01", "hostname": "office-fw01

问题 Want to rename the (known) 3th folder within a (unknown) file path from a string, when positioned on 3th level while separator is / Need a one-liner explicitly for sed. Because i later want use it for tar --transform=EXPRESSION string="/db/foo/db/bar/db/folder" echo -e "$string" | sed 's,db,databases,' sed replace "db" only on 3th level expected result /db/foo/databases/bar/db/folder 回答1: You could use a capturing group to capture /db/foo/ and then match db . Then use use the first caputring

问题 I am replacing smile character like :) to images. If I use only var yorum4 = "hello :)"; yorum4 = yorum4.replace(/(:\))/g, "<img class='smileys' src='smile.png' \/>"); It replaces correctly. However, when I use this for multiple replaces, yorum4 = yorum4.replace(/(:\))/g, "<img class='smileys' src='smile.png' \/>"); yorum4 = yorum4.replace(/(:\()/g, "<img class='smileys' src='smile1.png' \/>"); yorum4 = yorum4.replace(/(;\))/g, "<img class='smileys' src='smile2.png' \/>"); It corrupts and

问题 I'm trying to replace values across values with NA across multiple columns if a condition is met. Here's a sample dataset: library(tidyverse) sample <- tibble(id = 1:6, team_score = 5:10, cent_dept_test_agg = c(1, 2, 3, 4, 5, 6), cent_dept_blue_agg = c(15:20), num_in_dept = c(1, 1, 2, 5, 100, 6)) I want the columns that contain cent_dept_.*_agg to be NA when num_in_dept is 1, so it looks like this: library(tidyverse) solution <- tibble(id = 1:6, team_score = 5:10, cent_dept_test_agg = c(NA,

问题 I use a simple line to break an indexed image 256 color into palette using import numpy as np from PIL import Image im = Image.open('') palette = np.array(im.getpalette(),dtype=np.uint8).reshape((256,3)) ##################### Printed result [[ 1 3 0] [ 2 4 1] [ 28 0 4] [ 20 2 26] [ 24 5 18] [ 33 7 22] [ 36 7 12] [ 0 20 18] [ 42 15 16] [ 43 18 30] ... etc Printing 'palette' lists the colors as RGB values as listed from index 0 onward. Index 0 is often dark color or black. In some engines it is