replace

Replace nth occurrence of substring in string

由 ☆樱花仙子☆ 提交于 2019-12-28 01:24:08
问题 I want to replace the n'th occurrence of a substring in a string. There's got to be something equivalent to what I WANT to do which is mystring.replace("substring", 2nd) What is the simplest and most Pythonic way to achieve this? Why not duplicate: I don't want to use regex for this approach and most of answers to similar questions I found are just regex stripping or really complex function. I really want as simple as possible and not regex solution. 回答1: You can use a while loop with str

How to replace different newline styles in PHP the smartest way?

由 淺唱寂寞╮ 提交于 2019-12-27 11:40:10
问题 I have a text which might have different newline styles. I want to replace all newlines '\r\n', '\n','\r' with the same newline (in this case \r\n ). What's the fastest way to do this? My current solution looks like this which is way sucky: $sNicetext = str_replace("\r\n",'%%%%somthing%%%%', $sNicetext); $sNicetext = str_replace(array("\r","\n"),array("\r\n","\r\n"), $sNicetext); $sNicetext = str_replace('%%%%somthing%%%%',"\r\n", $sNicetext); Problem is that you can't do this with one

How to remove all characters after a specific character in python?

由 拟墨画扇 提交于 2019-12-27 10:36:22
问题 I have a string. How do I remove all text after a certain character? ( In this case ... ) The text after will ... change so I that's why I want to remove all characters after a certain one. 回答1: Split on your separator at most once, and take the first piece: sep = '...' rest = text.split(sep, 1)[0] You didn't say what should happen if the separator isn't present. Both this and Alex's solution will return the entire string in that case. 回答2: Assuming your separator is '...', but it can be any

How to remove all characters after a specific character in python?

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-27 10:35:27
问题 I have a string. How do I remove all text after a certain character? ( In this case ... ) The text after will ... change so I that's why I want to remove all characters after a certain one. 回答1: Split on your separator at most once, and take the first piece: sep = '...' rest = text.split(sep, 1)[0] You didn't say what should happen if the separator isn't present. Both this and Alex's solution will return the entire string in that case. 回答2: Assuming your separator is '...', but it can be any

How to remove all characters after a specific character in python?

由 若如初见. 提交于 2019-12-27 10:34:53
问题 I have a string. How do I remove all text after a certain character? ( In this case ... ) The text after will ... change so I that's why I want to remove all characters after a certain one. 回答1: Split on your separator at most once, and take the first piece: sep = '...' rest = text.split(sep, 1)[0] You didn't say what should happen if the separator isn't present. Both this and Alex's solution will return the entire string in that case. 回答2: Assuming your separator is '...', but it can be any

How to remove all characters after a specific character in python?

由 与世无争的帅哥 提交于 2019-12-27 10:34:08
问题 I have a string. How do I remove all text after a certain character? ( In this case ... ) The text after will ... change so I that's why I want to remove all characters after a certain one. 回答1: Split on your separator at most once, and take the first piece: sep = '...' rest = text.split(sep, 1)[0] You didn't say what should happen if the separator isn't present. Both this and Alex's solution will return the entire string in that case. 回答2: Assuming your separator is '...', but it can be any

哎

由 孤者浪人 提交于 2019-12-27 08:35:50
(function(window) { var rep = { // 替换用的数据，使用了4个零宽字符，数据量减少了一半。 '00': '\u200b', '01': '\u200c', '10': '\u200d', '11': '\uFEFF' }; function hide(str) { str = str.replace(/[^\x00-\xff]/g, function(a) { // 转码 Latin-1 编码以外的字符。 return escape(a).replace('%', '\\'); }); str = str.replace(/[\s\S]/g, function(a) { // 处理二进制数据并且进行数据替换 a = a.charCodeAt().toString(2); a = a.length < 8 ? Array(9 - a.length).join('0') + a : a; return a.replace(/../g, function(a) { return rep[a]; }); }); return str; } var tpl = '("@code".replace(/.{4}/g,function(a){var rep={"\u200b":"00","\u200c":"01","\u200d":"10","\uFEFF":"11

JS的replace方法

由 孤街浪徒 提交于 2019-12-26 17:08:37
replace() 方法的参数 replacement 可以是函数而不是字符串。在这种情况下，每个匹配都调用该函数，它返回的字符串将作为替换文本使用。该函数的第一个参数是匹配模式的字符串。接下来的参数 是与模式中的子表达式匹配的字符串，可以有 0 个或多个这样的参数。接下来的参数是一个整数，声明了匹配在 stringObject 中出现的位置。最后一个参数是 stringObject 本身。 下文展示了几种javascript正则表示式的repalce方式，有些方式我们很少在别的地方看到，如第二种和第三方中方法。 //下面的例子用来获取url的两个参数，并返回urlRewrite之前的真实Url var reg = new RegExp ( "(http://www.qidian.com/BookReader/)(\\d+),(\\d+).aspx" , "gmi" ); var url = "http://www.qidian.com/BookReader/1017141,20361055.aspx" ; //方式一,最简单常用的方式 var rep = url.replace(reg , "$1ShowBook.aspx?bookId=$2&chapterId=$3" ); alert(rep); //方式二 ,采用固定参数的回调函数 var rep2 = url

SQL Server Remove some specific characters from string

由 我怕爱的太早我们不能终老 提交于 2019-12-26 10:08:07
问题 SQL Server: I would like to create a function that removes specific characters from a string, based on parameters. parameter1 is original string parameter2 is characters want to removed from original string For example : call MyRemoveFunc('32.87.65.54.89', '87.65' ) -- this will return '32.54.89' call MyRemoveFunc('11.23.45', '23' ) -- this will return '11.45' call MyRemoveFunc('14.99.16.84', '84.14' ) -- this will return '99.16' call MyRemoveFunc('11.23.45.65.31.90', '23' ) -- this will

change inner key in multidimensional array php

由 情到浓时终转凉″ 提交于 2019-12-25 19:03:50
问题 I want to ask about how to replace inner key in a multidimensional array. I have an multidimensional array : $array1= array(array(5000, 6, 325, 3, 3, 517000000), array( 20000, 5, 217, 5, 3, 1692000000) ); The second array is $array2=array(1,2,3,4,5,6); I expected the new array is Array( [0] => Array ( [1] => 5000 [2] => 6 [3] => 325 [4] => 3 [5] => 3 [6] => 517000000 ) [1] => Array ( [1] => 20000 [2] => 5 [3] => 217 [4] => 5 [5] => 3 [6] => 1692000000 )) I have tried this code below by
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