replace

问题 I have a database that has names and I want to use PHP replace after the space on names, data example: $x="Laura Smith"; $y="John. Smith" $z="John Doe"; I want it to return Laura John. John 回答1: Do this, this replaces anything after the space character. Can be used for dashes too: $str=substr($str, 0, strrpos($str, ' ')); 回答2: Just to add it into the mix, I recently learnt this technique: list($s) = explode(' ',$s); I just did a quick benchmark though, because I've not come across the strtok

问题 I am trying to search and replace some of the text (eg 'Smith, John') in this pdf form file (header.fdf, I presumed this is treated as binary file): '%FDF-1.2\n%\xe2\xe3\xcf\xd3\n1 0 obj\n<</FDF<</Fields[<</V(M)/T(PatientSexLabel)>><</V(24-09-1956 53)/T(PatientDateOfBirth)>><</V(Fisher)/T(PatientLastNameLabel)>><</V(CNSL)/T(PatientConsultant)>><</V(28-01-2010 18:13)/T(PatientAdmission)>><</V(134 Field Street\\rBlackburn BB1 1BB)/T(PatientAddressLabel)>><</V(Smith, John)/T(PatientName)>><</V

问题 I am trying to search and replace some of the text (eg 'Smith, John') in this pdf form file (header.fdf, I presumed this is treated as binary file): '%FDF-1.2\n%\xe2\xe3\xcf\xd3\n1 0 obj\n<</FDF<</Fields[<</V(M)/T(PatientSexLabel)>><</V(24-09-1956 53)/T(PatientDateOfBirth)>><</V(Fisher)/T(PatientLastNameLabel)>><</V(CNSL)/T(PatientConsultant)>><</V(28-01-2010 18:13)/T(PatientAdmission)>><</V(134 Field Street\\rBlackburn BB1 1BB)/T(PatientAddressLabel)>><</V(Smith, John)/T(PatientName)>><</V

问题 I'm working on a Text Mining Solution with SQL and R. First I Import Data into R from my SQL selection and than I do data mining stuff with it. Here is what I got: rawData = sqlQuery(dwhConnect,sqlString) a = data.frame(rawData$ENNOTE_NEU) If I do a a[[1]][1:3] you see the structure: [1] lorem ipsum li ld ee wö wo di dd [2] la kdin di da dogs chicken [3] kd good i need some help Now I want to do some data cleaning with my own dictionary. An Example would be to replace li with lorem ipsum and

问题 I'm working on a Text Mining Solution with SQL and R. First I Import Data into R from my SQL selection and than I do data mining stuff with it. Here is what I got: rawData = sqlQuery(dwhConnect,sqlString) a = data.frame(rawData$ENNOTE_NEU) If I do a a[[1]][1:3] you see the structure: [1] lorem ipsum li ld ee wö wo di dd [2] la kdin di da dogs chicken [3] kd good i need some help Now I want to do some data cleaning with my own dictionary. An Example would be to replace li with lorem ipsum and

问题 This question already has answers here : Fast punctuation removal with pandas (3 answers) Closed last year . code: df['review'].head() index review output: 0 These flannel wipes are OK, but in my opinion I want to remove punctuations from the column of the dataframe and create a new column. code: import string def remove_punctuations(text): return text.translate(None,string.punctuation) df["new_column"] = df['review'].apply(remove_punctuations) Error: return text.translate(None,string

问题 I got this nice code, which I have no idea why doesn't work. It should get the value of a text input and replace each given national character with it's HTML code, for compatibility purposes. But, when I click the button, the function returns the string without any changes. Any idea? (jsfiddle) <a id="reminder1" onclick="document.getElementById('reminder2').style.display = ''; document.getElementById('reminder1').style.display = 'none';"> Set reminder </a> <a id="reminder2" class="reminder"

问题 I have about 100 lines that look like the below: assertEquals(results.get(0).getID(),1); They all start with assertEquals and contain two arguments. Im looking for a way to use find and replace all to swap the arguments of all these lines. Thanks 回答1: use the following regexp to find: assertEquals\((.*),(.*)\); and this replacement value: assertEquals(\2,\1); The regexp means "assertEquals( followed by a first group of chars followed by a comma followed by a second group of chars followed by

问题 I have about 100 lines that look like the below: assertEquals(results.get(0).getID(),1); They all start with assertEquals and contain two arguments. Im looking for a way to use find and replace all to swap the arguments of all these lines. Thanks 回答1: use the following regexp to find: assertEquals\((.*),(.*)\); and this replacement value: assertEquals(\2,\1); The regexp means "assertEquals( followed by a first group of chars followed by a comma followed by a second group of chars followed by

问题 Any one know a good way to remove punctuation from a field in SQL Server? I'm thinking UPDATE tblMyTable SET FieldName = REPLACE(REPLACE(REPLACE(FieldName,',',''),'.',''),'''' ,'') but it seems a bit tedious when I intend on removing a large number of different characters for example: !@#$%^&*()<>:" Thanks in advance 回答1: Ideally, you would do this in an application language such as C# + LINQ as mentioned above. If you wanted to do it purely in T-SQL though, one way make things neater would