replace

php null replacement function

时光怂恿深爱的人放手 提交于 2020-01-05 12:08:32
问题 there is this function called Nz() in visual basic for application. the function checks variable nullity and returns a provided value if it finds the variable is null. i try to write the same function in php, which looks like below: function replace_null($value, $replace) { if (!isset($value)) { return $replace; } else { return $value; } } $address = replace_null($data['address'], 'Address is not available.'); of course, if $data['address'] is found null, php will stop executing the code and

php null replacement function

自作多情 提交于 2020-01-05 12:08:31
问题 there is this function called Nz() in visual basic for application. the function checks variable nullity and returns a provided value if it finds the variable is null. i try to write the same function in php, which looks like below: function replace_null($value, $replace) { if (!isset($value)) { return $replace; } else { return $value; } } $address = replace_null($data['address'], 'Address is not available.'); of course, if $data['address'] is found null, php will stop executing the code and

Replacing non-diagonal elements in a matrix in R (hopefully a better asked this time) [duplicate]

时光总嘲笑我的痴心妄想 提交于 2020-01-05 10:37:08
问题 This question already has answers here : How to replace non-diagonal elements in a matrix? (6 answers) Closed 6 years ago . Okay, I asked this question earlier but I got bashed (deservedly) for not specifying anything and showing no sign of previous attempt. So let me try again.. I'm using R, and I have a 463✕463 matrix. What I would like to do is to replace all elements other than the diagonal ones (X 11 , X 22 , X 33 ,...,X jj ) with zero. E.g. I want: [1 4 5 2 3 5 3 9 8] to be: [1 0 0 0 3

Replacing non-diagonal elements in a matrix in R (hopefully a better asked this time) [duplicate]

隐身守侯 提交于 2020-01-05 10:35:17
问题 This question already has answers here : How to replace non-diagonal elements in a matrix? (6 answers) Closed 6 years ago . Okay, I asked this question earlier but I got bashed (deservedly) for not specifying anything and showing no sign of previous attempt. So let me try again.. I'm using R, and I have a 463✕463 matrix. What I would like to do is to replace all elements other than the diagonal ones (X 11 , X 22 , X 33 ,...,X jj ) with zero. E.g. I want: [1 4 5 2 3 5 3 9 8] to be: [1 0 0 0 3

SQLite Insert and Replace with condition

╄→尐↘猪︶ㄣ 提交于 2020-01-05 10:28:43
问题 I can not figure out how to query a SQLite. needed: 1) Replace the record (the primary key), if the condition (comparison of new and old fields entries) 2) Insert an entry if no such entry exists in the database on the primary key. Importantly, it has to work very fast! I can not come up with an effective inquiry. Edit. MyInsertRequest - the desired expression. Script: CREATE TABLE testtable (a INT PRIMARY KEY, b INT, c INT) INSERT INTO testtable VALUES (1, 2, 3) select * from testtable 1|2|3

JavaScript Regex Replace Width Attribute Matching

孤街醉人 提交于 2020-01-05 10:27:15
问题 I am using RegEx to match a narrower set of TinyMCE HTML from a textarea. Widths are too big, creating run-offs so I am making test code in JavaScript. My question is why does $3 not only match "1000px" but also matches the rest of the document after the table tag? <script language="javascript"> // change table width function adjustTable(elem0,elem1) { // debugging, place results in div elem1.innerHTML = elem0.innerHTML.replace(/^(.*)(\u003Ctable.*?\s*?\w*?width\u003D[\u0022\u0027])(\d+px)([

Find and Replace for whole page

眉间皱痕 提交于 2020-01-05 09:09:40
问题 I'm trying to create a Find and Replace for the whole page. I'm Using findandreplace which is a mini-plugin which is: function findAndReplace(searchText, replacement, searchNode) { if (!searchText || typeof replacement === 'undefined') { alert("Please Enter Some Text Into the Field"); return; } var regex = typeof searchText === 'string' ? new RegExp(searchText, 'g') : searchText, childNodes = (searchNode || document.body).childNodes, cnLength = childNodes.length, excludes = 'html,head,style

How to replace the elements in a big sparse matrix?

浪尽此生 提交于 2020-01-05 08:46:47
问题 I have quite a big sparse matrix, about 150,000*150,000. I need to access into its rows, extract the non-zero elements and replace these values following the rule as as the code below: H = []; for i = 1: size(A,2) [a,b,c] = find(A(i,:)); % extract the rows if size(c,2)==1 % only 2 add = 0; elseif size(c,2) > 1 && any(c<2)== 0 % many 2s add = c; add(1) = -2; add(end) = 2; add(2:end-1) = 0; elseif size(c,2) > 1 && any(c<2)~= 0 % 2 and 1 k = find(diff(c)==-1); % find right 2 position add = c;

VB.Net Replace not working?

泪湿孤枕 提交于 2020-01-05 08:32:20
问题 Not sure if I'm doing something wrong or not, basically my code starts at "111111111" and counts up by adding "1" to the original number every time the thread is able to. I want the method to skip 0's in the sequence though, instead of going to "111111120" after "111111119" I would like it to go straight to "111111121". Private Sub IncreaseOne() If count < 999999999 Then count += 1 Else done = True End If If CStr(count).Contains("0") Then MsgBox("theres a 0 in that...darn.") CStr(count)

VB.Net Replace not working?

江枫思渺然 提交于 2020-01-05 08:32:14
问题 Not sure if I'm doing something wrong or not, basically my code starts at "111111111" and counts up by adding "1" to the original number every time the thread is able to. I want the method to skip 0's in the sequence though, instead of going to "111111120" after "111111119" I would like it to go straight to "111111121". Private Sub IncreaseOne() If count < 999999999 Then count += 1 Else done = True End If If CStr(count).Contains("0") Then MsgBox("theres a 0 in that...darn.") CStr(count)