replace | 易学教程

Search and replace numbers with words in file [duplicate]

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问题 This question already has answers here : replacing text in a file with Python (7 answers) Closed 3 years ago . I have a file that contains numbers and letters and I want to replace all the numbers to words (for example, 8 is converted to eight). Well I just don't get a way to check if there is numbers on my file. What is the best effective way to do this? 回答1: The following should work, it reads an input file, uses a regex to find all of the numbers, and the num2words library to replace each

js刷新页面方法

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1.刷新方法列表　　最近常遇到js刷新页面的需求，就搜集了一些资料来整理一下常用的方法当做我的学习笔记和大家分享！　　1、history.go(0) 　　2、location.reload() 　　3、location.replace(location) 　　4、location.assign(location) 　　5、window.navigate(location) 　　6、document.URL=location.href 　　7、document.execCommand('Refresh') 2.刷新方法解析 1， reload 方法，该方法强迫浏览器刷新当前页面。语法：location.reload([bForceGet]) 参数： bForceGet，可选参数，默认为 false，从客户端缓存里取当前页。true, 则以 GET 方式，从服务端取最新的页面, 相当于客户端点击 F5("刷新") 2， replace 方法，该方法通过指定URL替换当前缓存在历史里（客户端）的项目，因此当使用replace方法之后，你不能通过“前进”和“后退”来访问已经被替换的URL。语法： location.replace(URL) 通常使用： location.reload() 或者是 history.go(0) 来做。此方法类似客户端点F5刷新页面

Lowercase part of a string with XPath regular expression

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问题 In a node, a string might contain one or more substrings delimited by single or double quotes. For example <node>Some text "and Some" More</node> What I have to do is lowercase the text that is not surrounded by quotes, so the result should look as: some text "and Some" more I've tried two things: with replace : replace('Some text "and Some" More', '"([^"]*)"', '*') this will replace the text in double quotes with *. But how can I lowercase it? This doesn't produce the desired result: replace

Replacing any NULL fields with a string

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问题 I'm new to SQL and this problem has stumped me. I am supposed to write an SQL statement that lists all the data in a table, but if a column might contain NULL values (in this case only one field is NULL), the phrase "-NONE-" must print in that column for that row. The lab hints that I must use one or more single-row functions to accomplish this. We are using Oracle SQL Developer to test scripts. I am trying to use the REPLACE function but I keep getting errors. I've tried using NVAL, REPLACE,

PHP replacing all occurances of certain string pattern in HTML formatted text

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问题 I have input text that can be long HTML text with tags and so on. Example of input can be something like: Lorem ipsum dolor sit amet, consectetur adipiscing elit. %image1% <h2>Lorem ipsum</h2> Cum sociis natoque penatibus et magnis dis parturient montes. %image2% Lorem ipsum dolor sit amet, consectetur adipiscing elit. %image3% Lorem ipsum dolor sit amet, consectetur adipiscing elit. ... What would be the easiest way of

Regular Expression to split on specific character ONLY if that character is not in a pair

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问题 After finding the fastest string replace algorithm in this thread, I've been trying to modify one of them to suit my needs, particularly this one by gnibbler. I will explain the problem again here, and what issue I am having. Say I have a string that looks like this: str = "The &yquick &cbrown &bfox &Yjumps over the &ulazy dog" You'll notice a lot of locations in the string where there is an ampersand, followed by a character (such as "&y" and "&c"). I need to replace these characters with an

PHP正则表达式语法汇总

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首先，让我们看看两个特别的字符：'^' 和 ‘$' 他们是分别用来匹配字符串的开始和结束，一下分别举例说明 "^The": 匹配以 "The"开头的字符串; "of despair$": 匹配以 "of despair" 结尾的字符串; "^abc$": 匹配以abc开头和以abc结尾的字符串，实际上是只有abc与之匹配大理石检测平台 "notice": 匹配包含notice的字符串你可以看见如果你没有用我们提到的两个字符（最后一个例子），就是说模式（正则表达式）可以出现在被检验字符串的任何地方，你没有把他锁定到两边这里还有几个字符 '*', '+',和 '?', 他们用来表示一个字符可以出现的次数或者顺序. 他们分别表示："zero or more", "one or more", and "zero or one." 这里是一些例子: "ab*": 匹配字符串a和0个或者更多b组成的字符串("a", "ab", "abbb", etc.); "ab+": 和上面一样，但最少有一个b ("ab", "abbb", etc.); "ab?":匹配0个或者一个b; "a?b+$": 匹配以一个或者0个a再加上一个以上的b结尾的字符串. 你也可以在大括号里面限制字符出现的个数，比如 "ab{2}": 匹配一个a后面跟两个b（一个也不能少）("abb" ; "ab{2,}"

Replacing parts of expression in prolog

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问题 I need to simplify identities in prolog (e.g. x+0 = x , x-x=0 , etc.). For this I need to replace parts of the expression (say x+0 by x ). Can you please help me in doing the replacement? 回答1: A neat thing about Prolog is that you can deconstruct an arithmetic expression pretty easily. Your basic template is going to look like this: simplify(X, X) :- number(X) ; atom(X) ; var(X). simplify(X+Y, X1+Y1) :- simplify(X, X1), simplify(Y, Y1). simplify(X-Y, X1-Y1) :- simplify(X, X1), simplify(Y, Y1)

search and replace block of code in all files in linux

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问题 This question is philosophically similar to a question that's come up time and time again here: Search and replace text in all files of a linux directory How to search-replace content within files in Ubuntu Linux? Linux search and replace a complex string But they (with the exception of the last one) all deal with simple replacements. I have a somewhat large block of code which appears in many files (I wish copy/pasting source code was punishable by law), and I need to replace it. Is there

search and replace block of code in all files in linux

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