replace

问题 I know this question may be asked before but I did not find the correct answer that works. I tried this code $('body *').each(function(k,v){$(v).text($(v).text().replace("Hazem","mizzo"))}); but the page crashes, I don't know why. I'm prefer the code to be in pure javascript not jQuery. Thanks. 回答1: You should walk the DOM, find text nodes, and replace the found text in each. Here's a simple example. You can make walkText() more generic by passing a callback that does the replacement.

问题 I know this question may be asked before but I did not find the correct answer that works. I tried this code $('body *').each(function(k,v){$(v).text($(v).text().replace("Hazem","mizzo"))}); but the page crashes, I don't know why. I'm prefer the code to be in pure javascript not jQuery. Thanks. 回答1: You should walk the DOM, find text nodes, and replace the found text in each. Here's a simple example. You can make walkText() more generic by passing a callback that does the replacement.

问题 I know this question may be asked before but I did not find the correct answer that works. I tried this code $('body *').each(function(k,v){$(v).text($(v).text().replace("Hazem","mizzo"))}); but the page crashes, I don't know why. I'm prefer the code to be in pure javascript not jQuery. Thanks. 回答1: You should walk the DOM, find text nodes, and replace the found text in each. Here's a simple example. You can make walkText() more generic by passing a callback that does the replacement.

问题 I need to convert some strings with this format: B12F34 to something like that: Building 12 - Floor 34 but I have to add a value, say 10, to the second capture group so the new string would be as: Building 12 - Floor 44 I can use this postgres sentence to get almost everything done, but I don't know how to add the value to the second capture group. SELECT regexp_replace('B12F34', 'B(\d+)F(\d+)', 'Building \1 - Floor \2', 'g'); I have been searching for a way to add a value to \2 but all I

问题 I want to replace, say String oldString with String newString in an Array along the lines of: for (int i = 0; i < text.length; i++) { if (text[i].equals(oldString)) { text[i] = text[i].replace(oldString, newString); } } How would one go about this in Java? 回答1: You don't need to use replace() in this case, since you are already checking that text[i] is equal to oldString , which means you are replacing the entire String , which means assignment is sufficient: for (int i = 0; i < text.length;

问题 I want to replace, say String oldString with String newString in an Array along the lines of: for (int i = 0; i < text.length; i++) { if (text[i].equals(oldString)) { text[i] = text[i].replace(oldString, newString); } } How would one go about this in Java? 回答1: You don't need to use replace() in this case, since you are already checking that text[i] is equal to oldString , which means you are replacing the entire String , which means assignment is sufficient: for (int i = 0; i < text.length;

问题 Suppose I have a string such as 'I hate *some* kinds of duplicate. This string has a duplicate phrase, duplicate phrase.' I want to remove the second occurrence of duplicate phrase without removing other occurrences of its constituent parts, such as the other use of duplicate . Moreover, I need to remove all potential duplicate phrases, not just the duplicates of some specific phrase that I know in advance. I have found several posts on similar problems, but none that have helped me solve my

问题 Suppose I have a string such as 'I hate *some* kinds of duplicate. This string has a duplicate phrase, duplicate phrase.' I want to remove the second occurrence of duplicate phrase without removing other occurrences of its constituent parts, such as the other use of duplicate . Moreover, I need to remove all potential duplicate phrases, not just the duplicates of some specific phrase that I know in advance. I have found several posts on similar problems, but none that have helped me solve my

问题 Trying to find the exact format for doing this. I have a textField user input, I want to take that input and find multiple occurrences and replace each unique occurrence with a different unique character respectively. i.e. : replace " example " with " 1328571 " This is my code I currently have (currently is just set up for a single replacement so it doesn't work), formatted in the way that might help to explain what I'm trying to accomplish: let monoText: String = textInput.text! let

问题 Trying to find the exact format for doing this. I have a textField user input, I want to take that input and find multiple occurrences and replace each unique occurrence with a different unique character respectively. i.e. : replace " example " with " 1328571 " This is my code I currently have (currently is just set up for a single replacement so it doesn't work), formatted in the way that might help to explain what I'm trying to accomplish: let monoText: String = textInput.text! let