replace

问题 I've looked all over for some regex that will cause R to disregard the next character within a regular expression string. For example, given myvector : myvector <- c("abcdef", "ghijkl", "mnopqrs") and a regex string: regexstring <- "[a-z]{3}XXXXXXXXX " which includes some unknown characters XXXXXXXXX, I want to tell R to ignore the final space in the regular expression string itself. After running the following, regexstring <- "[a-z]{3} " sub(regexstring, " ", myvector) gives, "abcdef"

问题 I am trying to delete the first occurrence of "<" and ">" in a cell without losing formatting of the remainder of the cell's contents. I have looked in several places here, and other, to no avail. This is what I am trying to do: Say "A1" contains the text: "This is <a> long string with several <occurrences> of a <special> character." In any case, What I am trying to do is remove the ">", and in a perfect world the "<", from the first word which contains them while maintaining the bold

问题 I am having trouble figuring out where I'm going wrong. So I need to randomly replace words and re-write them to the text file, until it no longer makes sense to anyone else. I chose some words just to test it, and have written the following code which is not currently working: # A program to read a file and replace words until it is no longer understandable word_replacement = {'Python':'Silly Snake', 'programming':'snake charming', 'system':'table', 'systems':'tables', 'language':'spell',

问题 As a part of text classification problem I am trying to clean a text dataset. So far I was removing everything except text. Punctuation, numbers, emoji - everything was removed. Now I am trying to use emoji as features hence I want to retain words as well emoji. First I am searching the emoji in the text and separating them from other words/emoji. This is because each emoji should be treated individually/separately. So I search an emoji and pad it with spaces at both its ends. But I am at

问题 Supposing I have the following DataFrame df df = pd.DataFrame({"a" : [1,2,2,2,2,2,2,2,2,3,3,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,5,5,5], "b" : [3,3,3,3,3,3,3,4,4,4,4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6,6,7,7], "c" : [4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,5,5,5,1,2,2,2,2,2,2,2,2,3,3]}) And I wish to replace number 4's which repeat more than 10 times in a row, in any column (there could be hundreds of columns), with 10 4's and the remainder 5's. So for example, 12 consecutive 4's would be replaced

问题 I would like to replace the values in column A:A using arrays: Dim aValueNew() As String Dim aValueOld() As String aValueNew = Split("ABC,DEF,GHI", ",") aValueOld = Split("123,456,789", ",") 123 needs to be replaced by ABC, 456 by DEF and so forth. What is the most efficient way of doing this? I am struggling on how to include the Replace function in a loop and your help would be appreciated. Something like: For i = 0 to i = 2 Range("A:A").Replace What:= aValueOld(i), Replacement:=aValueNew(i

问题 I want to write a function that converts regular path to path that includes environment variables: For example: C:\Windows\SomePath convert to: %Windir%\SomePath How would I do that and is this possible? Here is what I'm trying to do, but problem is, I need to check the string for all possible variables, is there some more automatic way? such that -replace operator wont be needed function Format-Path { param ( [parameter(Mandatory = $true)] [string] $FilePath ) if (![System.String]:

问题 Let's say I have the following extremely large string using Python3.x, several GB in size and +10 billion characters in length: string1 = "XYZYXZZXYZZXYZYXYXZYXZYXZYZYZXY.....YY" Given its length, this already takes +GB to load into RAM. I would like to write a function that will replace every X with A , Y with B , and Z with C . My goal is to make this as quick as possible. Naturally, this should be efficient as well (e.g. there may be some RAM trade-offs I'm not sure about). The most

问题 Let's say I have the following extremely large string using Python3.x, several GB in size and +10 billion characters in length: string1 = "XYZYXZZXYZZXYZYXYXZYXZYXZYZYZXY.....YY" Given its length, this already takes +GB to load into RAM. I would like to write a function that will replace every X with A , Y with B , and Z with C . My goal is to make this as quick as possible. Naturally, this should be efficient as well (e.g. there may be some RAM trade-offs I'm not sure about). The most

问题 How can I replace a substring of a string given the starting position and the length? I was hoping for something like this: var string = "This is a test string"; string.replace(10, 4, "replacement"); so that string would equal "this is a replacement string" ..but I can't find anything like that. Any help appreciated. 回答1: Like this: var outstr = instr.substr(0,start)+"replacement"+instr.substr(start+length); You can add it to the string's prototype: String.prototype.splice = function(start