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repeated phrases in the text Python

由 谁说胖子不能爱 提交于 2019-12-02 04:44:27
问题 I have a problem and I have no idea how to solve it. Please, give a piece of advice. I have a text. Big, big text. The task is to find all the repeated phrases which lenght is 3(contain of three words) in the text. 回答1: You have, it seems to me, two problems. The first is coming up with an efficient way of normalizing the input. You say you want to find all of the three-word phrases in the input, but what constitutes a phrase? For instance, are the black dog and The black, dog? the same

Repeating sound from one Instance

由 拟墨画扇 提交于 2019-12-02 04:20:45
I've been reading about the different ways of programming sound into a c# XNA game. I've decided on using a sound instance for the volume controls, but while playing a .wav, I've realised that the sound will only play again after it's completed, whereas just using a Sound Effect .Play() (rather than an instance) will cause it to play multiple copies of themselves, should it be asked to. So my question is, in a scenario where holding down a button will cause a single sound effect to play multiple times at once (such as the repeating drone of a machine gun or the like), instead of waiting until

I want to set repeating alarm that triggers every day at different time

由 会有一股神秘感。 提交于 2019-12-02 03:46:28
问题 I need the alarm to be triggered every day at sunrise. I get the sunrise time like this:"06:55" Location location = new Location(latitude, longitude); SunriseSunsetCalculator calculator = new SunriseSunsetCalculator(location, "GMT"+localTime); String officialSunrise = calculator.getOfficialSunriseForDate(Calendar.getInstance()); That means every day the time to trigger will be different. alarms.setInexactRepeating(AlarmManager.RTC_WAKEUP, startmillis,intervalmillis, wakeUp); I would

python regex repetition with capture question

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-02 02:29:11
问题 using python3's regex capabilities, is it possible to capture variable numbers of capture blocks, based on the number of the repetitions found? for instance, in the following search strings, i want to capture all the digit strings with the same regex. search string 1(trying to capture: 89, 45): zzz89zzz45.mp3 search string 2(trying to capture: 98, 67, 89, 45): zzz98zzz67zzz89zzz45.mp3 search string 3(trying to capture: 98, 67, 89, 45, 55, 111): zzz98zzz67zzz89zzz45vdvd55lplp111.mp3 the

repeated phrases in the text Python

由 ≯℡__Kan透↙ 提交于 2019-12-02 01:30:01
I have a problem and I have no idea how to solve it. Please, give a piece of advice. I have a text. Big, big text. The task is to find all the repeated phrases which lenght is 3(contain of three words) in the text. Robert Rossney You have, it seems to me, two problems. The first is coming up with an efficient way of normalizing the input. You say you want to find all of the three-word phrases in the input, but what constitutes a phrase? For instance, are the black dog and The black, dog? the same phrase? A way of doing this, as marcog suggests, is by using something like re.findall . But this

python regex repetition with capture question

由 ╄→гoц情女王★ 提交于 2019-12-02 01:27:03
using python3's regex capabilities, is it possible to capture variable numbers of capture blocks, based on the number of the repetitions found? for instance, in the following search strings, i want to capture all the digit strings with the same regex. search string 1(trying to capture: 89, 45): zzz89zzz45.mp3 search string 2(trying to capture: 98, 67, 89, 45): zzz98zzz67zzz89zzz45.mp3 search string 3(trying to capture: 98, 67, 89, 45, 55, 111): zzz98zzz67zzz89zzz45vdvd55lplp111.mp3 the following regex will match all the repetitions, though all the values are not available for later use(only 1

Jquery Onclick not happening second time

由 大憨熊 提交于 2019-12-01 23:39:11
问题 I'm a bit confused as to why this isn't working; I assume that because I'm adding the class and its not being added back into the collection I'm not sure. Here it is on a jsbin http://jsbin.com/ayije although code is below also. Either way I can only get the action to happen on an element once. <html> <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js" type="text/javascript"></script> <script type="text/javascript" charset="utf-8"> $(document).ready(function () {

Predictable Javascript array shuffle

由 和自甴很熟 提交于 2019-12-01 22:38:11
I'm trying to predictably shuffle javascript arrays the same way each time the webpage is loaded. I can shuffle the arrays randomly, but every time i reload the page it's a different sequence. I'd like it to shuffle the arrays the same way every time the page loads. There are many arrays and they are part of a procedurally generated world. Chance.js worked perfectly. Thank you Billy Moon. My Example: <script type="text/javascript" src="assets/js/chance.js"></script> var chance1 = new Chance(124); // you can choose a seed here, i chose 124 console.log(chance1.shuffle(['alpha', 'bravo', 'charlie

Jquery Onclick not happening second time

由 为君一笑 提交于 2019-12-01 20:38:35
I'm a bit confused as to why this isn't working; I assume that because I'm adding the class and its not being added back into the collection I'm not sure. Here it is on a jsbin http://jsbin.com/ayije although code is below also. Either way I can only get the action to happen on an element once. <html> <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js" type="text/javascript"></script> <script type="text/javascript" charset="utf-8"> $(document).ready(function () { $('.optional').click(function () { $(this).removeClass('optional').addClass('selected'); return false;

Regex to determine if string is a single repeating character [duplicate]

由 删除回忆录丶 提交于 2019-12-01 18:56:07
This question already has an answer here: Remove repeating character 3 answers What is the regex pattern to determine if a string solely consists of a single repeating character? e.g. "aaaaaaa" = true "aaabbbb" = false "$$$$$$$" = true This question checks if a string only contains repeating characters (e.g. "aabb") however I need to determine if it is a single repeating character. You can try with back reference ^(.)\1{1,}$ DEMO Pattern Explanation: ^ the beginning of the string ( group and capture to \1: . any character except \n ) end of \1 \1{1,} what was matched by capture \1 (at least 1
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