repeat

Stop jQuery from repeating, example attached

我与影子孤独终老i 提交于 2019-12-04 02:36:55
问题 I have to attach a jQuery to an invoice. Sometimes I have to print multiple invoices as once in a batch. When this happens my exact same jQuery appears for every invoice and it runs each time creating extra elements I do not need. Is there a way to have a jQuery that appears more then once only run once when it is the last time it appears in the code? Thanks for any help. Example is below. I have previously posted this and everyone asked to see how I was doing it. I was not sure how to add

make image( not background img) in div repeat?

馋奶兔 提交于 2019-12-04 01:34:16
I'm trying to repeat-y an image that's in a div and no background image but haven't figured how. Could you please point me to a solution? My code looks like this: <div id="rightflower"> <img src="/image/layout/lotus-dreapta.png" style="repeat-y; width: 200px;"/> </div> You have use to repeat-y as style="background-repeat:repeat-y;width: 200px;" instead of style="repeat-y" . Try this inside the image tag or you can use the below css for the div .div_backgrndimg { background-repeat: repeat-y; background-image: url("/image/layout/lotus-dreapta.png"); width:200px; } Not with CSS you can't. You

How to create missing value for repeated measurement data?

扶醉桌前 提交于 2019-12-03 21:12:04
问题 I have a data set that not every subject’s observations were observed at the exact same time points, but I want to turn it in to a data set that every one’s observations were observed at the exact same time points (so that I can use it in SAS proc traj). For example, suppose I have dataset "m": id <- c(1,1,1,1,2,2,3,3,3) age <- c(2,3,4,5,3,6,2,5,8) IQ <- c(3,4,5,4,6,5,3,8,10) m <- data.frame(id,age,IQ) > m id age IQ 1 1 2 3 2 1 3 4 3 1 4 5 4 1 5 4 5 2 3 6 6 2 6 5 7 3 2 3 8 3 5 8 9 3 8 10 >

Add multiple triggers to single quartz job

前提是你 提交于 2019-12-03 17:33:34
问题 I want to dynamically add triggers to a job, but can't find any helpful methods off of Scheduler I though i would just be able to call the scheduleJob method an repetitively, but this gives me tthe ObjectAlreadyExists Exception "because one already exists with this identification". How can i do this? EDIT private boolean scheduleLoadJob( XfuScheduleTimeInfo time ) { LoadScheduleJob job = new LoadScheduleJob( time ); JobDetail detail; Integer id = Integer.valueOf( time.getScheduleId() ); if(

Fastest way to create new array with length N and fill it by repeating a given array

£可爱£侵袭症+ 提交于 2019-12-03 17:31:08
问题 I want to allocate a new array with the length N and fill it up by repeating a given array. The interface looks like this: <T> T[] repeat(T[] array, int n); To clarify what I mean here is a small example: String a = {"a", "b", "c"}; // b = {"a", "b", "c", "a", "b", "c", "a", "b", "c", "a"} String b = repeat(a, 10); Most of the programmer will come up with the following solution (for simplicity of array generation a specific type was chosen): public String[] repeat(String[] array, int n) {

Cypher: how to find all the chains of single nodes not repeated?

夙愿已清 提交于 2019-12-03 17:19:27
I want to find ALL the paths starting and ending from/to a specific node. I would like that each node in a path appears only once. For example, in a graph like this: (a)-[:REL]->(b)-[:REL]->(c)-[:REL]->(a) (a)-[:REL]->(e)-[:REL]->(f)-[:REL]->(a) (e)-[:REL]->(b) grafically: e → b ↙ ↖ ↗ ↘ f → a ← c Cypher code: CREATE (a { name:'A' })-[:REL]->(b {name:'B'})-[:REL]->(c { name:'C' }) -[:REL]->(a)-[:REL]->(e {name:'E'})-[:REL]->(f {name:'F'})-[:REL]->(a), (e)-[:REL]->(b) I would like that the research of chains starting from (a) returns (a)->(b)->(c)->(a) (a)->(e)->(f)->(a) (a)->(e)->(b)->(c)->(a)

How should I find repeated word sequences

久未见 提交于 2019-12-03 16:35:42
I need to detect the presence of multiple blocks of columnar data given only their headings. Nothing else is known about the data except the heading words, which are different for every set of data. Importantly, it is not known before hand how many words are in each block nor, therefore, how many blocks there are. Equally important, the word list is always relatively short - less than 20. So, given a list or array of heading words such as: Opt Object Type Opt Object Type Opt Object Type what's the most processing-efficient way to determine that it consists entirely of the repeating sequence:

How to repeat a dash (hyphen) in shell

丶灬走出姿态 提交于 2019-12-03 11:19:05
How can I repeat the character - n times in shell? I have read and tried this , but this does not work for - . It throws error invalid option . Below is the exact command that I used: printf '-%.0s' {1..100} Original posted line: printf '-%0.s' {1..100} I also tried escaping - by putting a \ but in that case it repeats \- n times. This throws an error: $ printf '-%.0s' {1..100}; echo "" bash: printf: -%: invalid option printf: usage: printf [-v var] format [arguments] This works fine under bash : $ printf -- '-%.0s' {1..100}; echo "" ------------------------------------------------------------

Display a list of images in a table format in JSF

南楼画角 提交于 2019-12-03 08:57:43
This is probably a really simple JSF question, but I can't seem to find the simple answer. I have a List of images, and I want to display them in a table of images. Each image is displayed with its filename. I'm using a ui:repeat tag as shown below. I don't get 5 columns as requested, however, only 1. <h:panelGrid id="resourcePanel" columns="5" rules="all"> <ui:repeat var="res" value="#{resourceUpload.resources}"> <h:panelGrid columns="1" rules="none"> <h:graphicImage value="/image/resource?id=#{res.idAsString}" style="width:100px;" /> <h:outputText value="#{res.name}" /> </h:panelGrid> </ui

set Background Image and xml Resource

喜你入骨 提交于 2019-12-03 08:29:57
I am using the following below code to round the corners of RelativeLayout. I save this as mybackground.xml in drawable folder. It's working fine for rounding the corner but the problem is that I also want to add an transparent image as a background of my RelativeLayout. How can I achieve both things? How can I use an image and a drawable xml (for rounding the corner) at the same time for a RelativeLayout ... <?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" android:padding="10dp"> <corners android